scanf cannot be run in xcode

Has the landlord solved this problem?

There are three buttons on the left side of the organization button in the upper right corner, one of which pops up the console below, and when it appears, directly command r to run the program, and then enter it in the console.

The %d of scanf can only be used to input integers, you use 3 %d, there is no separator in between, so the program does not know that it is splitting in **, so the result ntype becomes 0. If you need to enter a floating-point number, you can use float ntype; declaration, and specify the input format with %f, e.g. scanf("%f %d %d",..And when entering, a half-width space is used in the middle, so that each variable can be correctly assigned.

Change the type of nnum to dnum (or fnum) for double (or float) and change the display format to"%lf"(or.)"%f")。

C++ uses Cin instead of Scanf.

**Modified to std::cin>>m>>b>>c;

"%c%c%c"

Here's what the format looks like.

The format string starts with %.

The landlord was confused.

Key questions.

The addition of & to the variable in your scanf causes you to enter a and then you don't have to enter it again.

You change it to ("%d", &b) try.

Explain why. Execute it twice, which is related to the buffer and should not be related to carriage return.

Actions such as your carriage return are remembered as the next input.

Don't use enter on the numpad

#include

int main()

1.After typing **, click on the triangle symbol in the upper left corner, and then run the program, sometimes because the program has already run once, so when you run it again, a related interface will pop up to ask, click stop, 2After running, enter the values in the correct format in the input and output boxes, 3Click enter, and you can see the result of the run.

The standard for judging whether the program has been run in xcode: see if the last line of the output box output is about returning to a 0, if this line is not displayed, it means that **is still reading and running, and it is not finished, it is waiting for you to enter some information, and then the system waits for you to enter some values, and then continues to read the **,)

Enter multiple times or give more than a few scanf parameters, such as scanf("%d%d%d",&a,&b,&c)。

Or write the input in a loop.

In addition, if there is an error or input, there will be a continuous input interruption.

If you ask that the program can be entered on the first run, but it can't be entered on the second run, you can just printf something at the beginning of the main function, and then solve it, and delete the printf when you submit **.

1 double quotation marks are indeed wrong, Tong 1st floor.

2. If you can only enter 1, you can see if the data type of your anynumber is char

You're not in the right quote, right?

scanf("%i",&anynumber);