How tall is the fourth tree? How many meters tall is a big tree

Method 1: Set the fourth tree to be m meters high.

8+10+12+m)/4+12=m

m=26 meters.

Method 2: Suppose the fourth tree is 12 meters long.

Then the average value of the four trees is (8+10+12+12) 4=14 meters.

And because the height of the fourth tree is twelve meters higher than the average height of the four trees, the height of the fourth tree is:

8 + 10 + 12 + 12 (12 meters higher)] 4 + 12 = 26 meters.

8+10+12+12*3+12) 3=26 Explanation: Because the average height is 12m, then each of the four trees plus 12m is 4 times the height of the 4th tree, if you don't add the height of the 4th tree at the beginning, then 3 times, so you can get the above equation, the answer is 26m

The law of these three numbers is to add 2 in turn, then the fourth number is 14, and 14 is the average of their four numbers, plus the height of the fourth tree is 26 meters.

I'm just thinking nonsense, so I'm talking nonsense!

The mathematical equations are very scientific and correct!

Solution: Let the heights of the four trees be a, b, c, and d, respectively, then there are:

d-12=(a+b+c+d)/4

4d-48=30+d

Therefore, d = 26 (m).

A: The fourth tree is 26 meters high.

Solution: Let the fourth tree be x meters high.

8+10+12+x)/4=x-12

30+x=4x-48

3x=78x=26

A: The fourth tree is 26 meters high.

If you want to make the length of the 4th tree the length of the 4th tree, you need to add 12 4 48 meters to the total length of the 4 trees.

The additional 48 meters need to be supplemented by the lack of the length of the first tree (since the length of the fourth tree is the same as the average after adding 48 meters), so: (8 10 12 48) 3 26 meters (the average length after adding 48 meters, i.e. the length of the fourth tree).

8+10+12+x)/4+12=x

x = 26 (m).

A: The fourth tree is 26 meters high.

The calculation is as follows: Let the height of the fourth tree be x

8+10+12+x)/4+12=x

8+10+12+x)/4=x-12

8+10+12+x=4x-48

3x=78x=26

A: The height of the fourth tree is 26m

Suppose the fourth tree is x, then (8+10+12+x) 4=y

x=y+12 solves x, i.e. the fourth tree is equal to 26 meters.

Let the fourth tree be x meters high, then x=(8+10+12+x) 4+12

This gives x=26

After rigorous mathematical analysis, the answer is 26m

There is a big difference between different trees. The tall ones can be 20-30 meters, and the shorter ones are 10-20 meters.

1. Pine trees: they are evergreen trees, most of which are tall trees. 20 meters high and up to 75 meters.

2. Chinese fir: an evergreen tree, up to 142 meters; The canopy is often spiral-shaped; The bark is scaly and brown.

3. Sycamore tree: also known as green tung tree, tung hemp, deciduous tree, native to China, can be as high as 12 meters.

4. Ginkgo biloba: can grow 20-40 meters tall. The ginkgo tree, also known as the ginkgo tree and the gongsun tree, is the ginkgo family.

5. Podocarpus: an evergreen tree, up to 20 meters high. The branches are densely developed and the crown is broadly ovate.

A growth ring is a layer produced by the growth of a tree in a year, which appears in a cross-section like a (or several) rings, surrounding the same rings that were produced in the past. Scale growth rings in fish refer to the dividing line between the narrow band formed in the autumn and winter of the current year and the wide band formed in the spring and summer of the following year. The secondary xylem produced by the growth ring vascular cambium during a growth phase constitutes a growth ring.

There is a clear seasonality, and only one growth ring is produced in a year, which is the age of the tree, also known as the tree's growth rings.

752 meters. Multiplication, is a shortcut to add up the same numbers. The result of the calculation is called the product, and the distribution is calculated to know how many meters is between the two trees from 4 meters to the 189th tree, and the operation track is 4* (189-1), and the result is 752 meters.

Answer: Every 5 trees are 40 meters between.

There are 3 trees between the 40 meters, except for the two trees at the beginning and the end.

The distance equivalent to 40 meters is divided into 4 intervals by 3 trees.

So the distance between the two trees is 10 meters.

There are 4 intervals between 5 trees.

In the same way, among the 10 trees, there are 8 trees in addition to the 2 trees in Shou Qin and Lawei.

There should be 9 intervals between 8 trees.

The total distance between the 9 intervals is 90 meters.

So 90 meters between the first trees of the ten locust trees.

40 (5-1)x(10-1)=40 4x9-210x9=90, A: 10 trees between is 90 meters.

1,500 slag trees are 2,000 meters of sap beams.

4. = 2000 meters.

Yes: A large tree is about 10 meters tall.

3 to 4 storeys high).

Because the distance between the two trees is 4 meters, and the fourth tree is separated from the sixth tree by the first five mountain reed trees, the total between the fourth tree and the sixth tree is 4+4=8 (meters).