How to find f in abcdef b efabcd???

b cannot be equal to 1, otherwise the letter of abcdef 1 product will still be in its original position. Let abcd=x, ef=y, and the column equation: (100x+y)b=10000y+x, and the solution gives (100b-1)x=(10000-b)y, so (10000-b)y

100b-1)=x is an integer, 10000-b may be a multiple of 100b-1, but (10000-b) is not when b=2 9.

100b-1, so (100b-1) must be able to split part of it divisible by y, and (100b-1) can be split if it is a composite number. 100b, assuming that the following is true, b is , abcdef b is larger, may be more than 6 digits, unless a=1, because a=1 and b=4 have been calculated, and if the marquee is not established, a cannot be 1. The rest of b = 3, column vertical, because a is different from b, a can not be 3, a b plus the carry later, and can only be e single digit, so a = 2, abcdef in the try f vertical is not true, only f = 9 is established, get a single digit d = 7, and then look at the multiplier in e, e also.

At the top of the product, it may be 6, and we get c=0, b=3, which is just right.

The f-number is the f-test.

, i.e., the sum of squares and degrees of freedom of dispersion between and within groups.

, significance is the level of significance corresponding to the f-statistic.

Illustrates the rejection of the null hypothesis, i.e., that there are significant differences between different levels of a single factor.

In ANOVA systems, the f-test can be used to detect the presence or absence of an effect or variance for a variant. The larger the f, the more significant the between-group variance is**, and the more significant the effect of the treatment. The smaller the f, the more stochastic variance is the main variance**, and the less significant the effect of the treatment is.

The size of the f-value has nothing to do with the size of the sample data itself, the range of the sample data value is 14-18, and the f-value is 21, this f-value is completely fine.

The denominator is an addition symbol. When f=5, the denominator is 5+4+3+2+1=15, and the numerator is 5. The result is 1 3.

Proof constructor f(x) = x 3-3x-1

Then Xiangcha f(1)=1 3-3-1=-3 0

f(2)=2^3-3×2-1=1＞0

i.e. f(1)f(2) 0

Therefore, f(x) has at least one zero banquet and filial piety point in the manuscript room (1,2) of the district hall.

Old. Equation x -3 x 1 has at least one root between 1 and 2.

For example, if you are a rounder, if you lose a fast sentence: f(x)=3x+2, then f[f(x)]=3*(3x+2)+2, and other functions can be compared to this.

<> cos b=(ab 2+bc 2-ac 2) 2ab*bc, converted to f1, f2, f, -, cos( - empty collision = (f1 2+f2 2-f 2) 2f1f2, f 2=f1 2+f2 2+2f1f2cos.

f= (noisy f1 2+f2 2+2f1f2cos) is happy to answer for you, if you don't understand the model of Huandou welcome to continue to ask.