Simplification evaluation a b a b a b a b 2a 2b b a a b b where a 2, b 0 5,

a-b)*(a-b) (a+b)*(a+b) 2(a*a-b*b) = --

a*a - b*b a*a - b*b a*a + b*b2(a*a + b*b) 2(a*a - b*b)a*a - b*b a*a + b*b

The first numerator denominator of the above two equations is multiplied by a*a + b*b, and the four numerator denominators are multiplied by a*a - b*b

a*a + b*b)(a*a + b*b) -a*a - b*b)(a*a - b*b)

a*a - b*b) *a*a + b*b)a*a*a*a + b*b*b*b

a*a*a*a - b*b*b*b

Hello: (4ab -8a b) 4ab + (2a + b) (2a-b) = b -2a + 4a -b

4a²-2a

4x2²-2x2

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a-b+a-b/4ab)*(a+b-a+b/4ab)(4a^2b-4ab^2+a-b)(4a^2b+4ab^2-a-b)/16a^2b^2

a(4ab+1)-b(4ab+1)][a(4ab-1)+b(4ab-1)]/16a^2b^2

4ab+1)(a-b)(4ab-1)(a+b)/16a^2b^2(16a^2b^2-1)(a^2-b^2)/16a^2b^2a=2/3,b=-1/2

a^2b^2=4/9*1/4=1/9

So the hole: original = (16 9-1) (4 9-1 4) regret difference 16 97 Bipi 9 (4 9-1 4) 16 9

Simplify, then evaluate; (2a-b a+b)-(b a-b) where b a=-1 2

solution, obtain: (2a-b)(a-b)-b(a+b)] [(a+b)(a-b) a-2b)(a-b) 2+ab(a+b)] [(a+b)(a-b) 2].

[(2a-b)(a-b)-b(a+b)]/[(a+b)(a-b)］*a+b)(a-b)^2]/[(a-2b)(a-b)^2+ab(a+b)]

[(2a-b)(a-b)-b(a+b)](a-b)/ [(a-2b)(a-b)^2+ab(a+b)]

2(a^3-3a^2b+2ab^2)/(a^3-3a^2b+7ab^2-2b^3)

Because b a==-1 2

b==-a/2

Bring b into 2 (a 3-3a 2b + 2ab 2) (a 3-3a 2b + 7ab 2-2b 3)

2a^3+3a^3+a^3)/[(4a^3+6a^3+7a^3+a^3)/4]

6a^3/([18a^3)/4]

6a^3*(4/18a^3)