Liquid level change question after the object melts the exam is coming soon... Please help the mas

My strictness, please see.

1 In general, when ice turns into water, the volume will definitely decrease, and the total liquid level will definitely decrease.

2 Looking at the level of the water, it can be deduced that the surface of the water does not change after the ice melts when there is no oil (see below). However, the buoyancy of the oil now makes the volume of water discharged from ice smaller than when there is no oil, and the volume of ice into water is greater than the volume of ice discharged in the water component of this mixture, so the water level**, that is, the interface of the separation, moves upward.

Complete. As for the derivation of the case where there is only ice and water in the second step, for the ice cubes floating on the surface of the water, according to the law of buoyancy, f = p water * g ice p ice * v ice * g i.e. v ice * p ice p water * v row. 1

Again, the ice becomes water and the quality remains unchanged v ice * p ice p water * v after it becomes water. 2 According to the 1 and 2 formulas, V exhaust V becomes water, so the liquid level does not change.

The density of ice is smaller than that of water, and the density is greater than that of water, so it floats on the interface of water and oil, the volume of ice is v1, the volume of water is v water, and the volume of oil is v oil, at this time the total volume is v1 + v water + v oil, and the volume after ice melts is v2, because the water density is greater than ice, so v2 is less than v1, then the total volume is (v2 + v water + v oil) is less than (v1 + v water + v oil) so the total liquid level falls, and the water volume changes from v water to (v water + v2) so the water level rises.

The liquid level drops. Analysis: The volume of the ice cube decreases when it turns into water (obtained by multiplying the mass = density by the volume).

The mass does not change, the density increases, so the volume decreases.

The interface between water and oil has not changed, and the overall decline has decreased.

The water surface remains the same.

The analysis is as follows: 1. The water formed after the ice cube is melted, its mass is the same as the quality of the ice, but the volume will be smaller.

2. According to Archimedes' principle, there are: F float g row.

3. The ice floats on the surface of the water, the ice is in equilibrium, and the buoyancy of the ice is equal to the gravity of the ice: f float = g ice.

4. To sum up the above two points, there are:

G row = g ice.

m row = m ice.

5. The quality of the water formed after the ice cube melts is the same as the mass of the ice, and the mass of the ice is equal to the mass of the drained water, so the quality of the water formed after the ice cube melts is equal to the mass of the drained water, that is, the water turned into by the ice can just fill the space originally occupied by the ice, so the water surface remains unchanged.

F2 + F3 water G Solution: After the stone is thrown into the water, the stone sinks to the bottom of the pool, the weight of the stone: G stone = F2 + F3, the stone is on the box, and the two are buoyant by the water:

F1 = G box + G stone, F float = water v drain g, volume of drained water: v row = g box + g stone water g boat itself drained water volume: v row = g box fraction water g, after the stone is put into the water, the volume of the box row of boiling water is reduced:

V row = V row - V row = g box + g stone water g -g box water g = g stone water g = f2 + f3 parts water g so the answer is: f2 + f3 parts water g

(1) If the iron does not sink to the bottom, the height remains the same. Because both buoyancy is equal to gravity. (2) Height reduction. The buoyancy of the box is equal to the gravitational force, and the buoyancy of the iron block is less than the gravitational force. The total buoyancy is reduced, the V discharge is reduced, and the liquid level is reduced.

The liquid level does not change. Analysis: Ice floats on water, and the buoyancy is equal to its own weight, and the traces are delayed and touched according to Archimedes' principle.

Posture talk f float g row g ice.

The key is: G row G ice.

Meaning: The gravity of ice is as heavy as the water that is discharged. And when the ice melts, it is water. Therefore, after the ice melts, the density increases and the volume decreases, just filling the space on the top and keeping the water surface unchanged.

Throwing a piece of ice at minus 5 degrees Celsius into a large basin of water at zero degrees Celsius will make it easy to bef

When the temperature of the ice is lower than zero, it will exchange heat with the environment, absorb heat, and the temperature will rise (the ambient temperature is not higher than zero, so the ice will not melt), and the water will lose heat and freeze (the temperature of the water will never fall below zero, and it will become ice if it is below the zero degree of the envy bush), so the water quality will decrease, and the ice quality will increase.

As for why is it wrong for you to add C, because C says that the water will freeze immediately, it is wrong"Right now"Water exothermy is a process, not an instant. The water will slowly turn into ice, not immediately. In addition, it is not necessary that all water will turn into ice in the final state, but it is right that the mass of ice will increase and the mass of water will decrease.

The density of the liquid discharged by ice is equal to its gravity, and the liquid level does not change when it is placed in water to dissolve.

When it is less than water, the discharge volume increases, so the liquid level decreases, which is equal to the same when the water is unchanged, and increases when it is greater than the water.

There is a stone in the ice, and if the whole noisy friend is submerged, the volume of the ice will decrease after melting, and the liquid level will be lowered.

The volume of water drained by ice is still its gravity, so the page remains unchanged when it melts. If there is an object with a density less than water, the liquid level will rise.

1) It can be seen from the image Huilian that the temperature corresponding to the straight section of the image is 0, so the melting point is 0, and the melting process is from the 1st minute to the 4th minute, which is in the state of solid-liquid coexistence, in this process, the object continues to absorb heat, the internal energy increases, but the temperature remains unchanged, so the option AC is wrong, B is correct;

2) The melting point of the sock return of the substance is 0, and it is liquid in the 5th to 6th min, and its internal energy increases, so d is wrong

Therefore, choose B