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Not necessarily. Here we choose the frame of reference defined by "stationary", and the other frames of reference are not necessarily the same. Stationary means that the position of the particle in the selected coordinate system does not change, that is, the velocity of the particle relative to the selected frame of reference is equal to zero, and has nothing to do with acceleration.
Therefore, the velocity of the object at rest must be zero, and it can have acceleration (e.g. by a force) or no acceleration (e.g. equilibrium by force). It's just that a rest with acceleration can only be instantaneous, because the next acceleration will break the rest; Whereas, a rest without acceleration can be held for a while.
The fact that the object is at rest in motion according to lz shows that the velocity varies with time and there is acceleration. However, this excludes the case of continuous rest. For example, if an object is at rest in t [t1,t2], then it can be determined that the acceleration within t (t1,t2) is zero.
Some definitions of "rest" in secondary schools emphasize zero acceleration, which is wrong.
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Not necessarily. Stillness simply means that its velocity is zero at this moment, but it may have an acceleration, and the state of velocity motion will change in the next moment. For example, if you hang a small ball from a spring, the ball moves in a vertical direction, and when it is at the highest or lowest point, the velocity is zero, but the acceleration is not zero.
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The state of rest of an object is relative. The object is at rest for a period of time, during which time its acceleration is zero.
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Relative to the observer's rest, in the state of rest, the object has no acceleration.
In the continuous process from rest to motion, or from motion to rest, the object has an acceleration.
v(t)*v(t)-v(t=0)*v(t=0)=2*a*s, v=velocity, a=acceleration, s=distance (distance), if v(t)=v(t=0)=0, a=0, if v(t) is unequal to zero, v(t=0)=0, there is acceleration a is not equal to zero, if siddus v(t=0) is not equal to zero, v(t)=0, there is acceleration a is not equal to zero.
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The effect of non-zero acceleration on an object is at least one of the magnitude of changing direction and velocity. So a no.
Uniform circular motion, belonging to category B.
Variable acceleration (change in the magnitude or direction of acceleration) motion and parabolic motion belong to class C and deceleration linear motion and belong to class D.
It is contemptible that BCD should be chosen
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It should be a CD
a If there is acceleration, either change the direction of the velocity or change the magnitude of the velocity b When the velocity is to the right and the acceleration is to the left, the velocity will gradually decrease, and when the velocity is reduced to 0, the magnitude will not change, but the velocity has no direction.
c When the velocity is to the right and the acceleration is to the left, the velocity will gradually decrease, and finally the velocity will be 0, and then continue to move in the direction, and the velocity will change.
d For example, the deceleration mentioned in b does not change the direction, but the speed decreases.
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The definition of inertia is the property of an object to maintain its original state of motion, and the index of the magnitude of inertia is mass.
When not affected by external forces, the inertia of an object can only keep it moving in a straight line at a uniform speed, but not making it move at an accelerated pace. As a result, your question itself is ill-described.
Here we should pay attention to the description of "constant state of motion" in physics, "constant state of motion" in physics means to maintain stationary or uniform linear motion, and any other situation cannot be called "constant state of motion", because it is changed by external forces.
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The object that is doing accelerated motion can only move in a uniform straight line after losing all external force, because the accelerated motion must be subjected to external force, which does not conform to Newton's first law.
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According to Newton's first law, the law of inertia, it can be seen that when an object is not affected by an external force, i.e., f=ma=0, the object will maintain a uniform linear motion or be at rest.
According to Newton's second law, f = ma≠0, a constant means that the force is constant. Acceleration is a vector quantity, and constancy means that its magnitude and direction are constant. Objects can only move in a straight line.
The direction of the acceleration of the so-called curvilinear motion or uniform motion changes from moment to moment. The value of the uniform circular acceleration may be constant, but the acceleration is absolutely not constant. There is a question of direction to consider.
It is concluded that the state of motion of the object when the acceleration is constant is: uniform linear motion, uniform acceleration or uniform deceleration linear motion.
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Stationary, uniform linear motion, uniform acceleration (deceleration) linear motion, flat throwing motion, oblique throwing motion. I've lifted it all, and there will be no more. The first of these is the most special, and each of the latter is the generalized result of the previous one (except for the flat tossing motion and the uniform acceleration motion).
Diagonal throwing motion: a constant;
Flat throwing motion: a is constant, v0 is perpendicular to a;
Uniform acceleration (deceleration) linear motion: a constant, v0 and a collinear;
Uniform linear motion: a is constant and zero (v0 is non-zero in the narrow sense);
Rest: a is constant and zero, and v0 is zero.
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Yes. According to the current theory, at the macro level, there is no object in the universe that is not subject to force, it must at least be subject to gravity and repulsion contrary to gravity. Then the acceleration a=f resultant external force m mass of the object.
An object has a mass, that's for sure, and is also subjected to gravitational and repulsive forces, which cause the object to be accelerated by the same magnitude but in opposite directions, but because the resultant external force on which they are subjected is zero, they do not manifest themselves.
Of course, this is only a macroscopic phenomenon, and this Newton's second law of motion is not suitable for the situation under the microscope, and the object under the microscope needs to use quantum theory, but I have almost not been exposed to quantum theory, and I can only answer the situation under the macroscopic situation.
I would like to state that this is only an explanation of the theory of the present, not necessarily of the theory of the future.
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In the state at rest, the object has no acceleration.
In the continuous process from rest to motion, or from motion to rest, the object has acceleration.
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When the resultant force is zero, the object has no acceleration.
When the resultant force is not zero, there is acceleration.
If an object at rest is only momentarily at rest, it will have an acceleration.
It's a state of equilibrium at rest where there is no acceleration.
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Acceleration is possessed by an object that is moving in a non-uniform linear motion (the resultant external force is not zero).
Both rest and motion are relative, and if there is no object that can be compared, it is impossible to tell whether an object is in motion or at rest. Acceleration is the amount of change in the speed of motion per unit of time. If an object is at rest with respect to another object, then it has no motion with respect to that object and naturally has no acceleration.
If an object moves in a non-uniform straight line with respect to another object, then it has acceleration with respect to that object.
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Yes, and it can not be 0, because the object has inertia, when it is subjected to a huge force in an instant, the velocity can be 0, or it can remain at rest in an instant, but the acceleration is not 0 at this time, but if the force is balanced, its acceleration must be 0!!
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It depends on how you understand the word stillness
1, according to the general Chinese understanding habits, the rest here should always be stationary so that the acceleration is zero, in layman's terms, there is no acceleration 2, according to the strict definition of physics, rest is instantaneous rest, then it is not necessarily, at this time, if the external force is not zero, the acceleration is not zero, in layman's terms, there is an acceleration and the external force is zero, the acceleration is also zero, in layman's terms, there is no acceleration If it is a physics problem, it should be understood according to 2.
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This is a kinematic problem, before solving this problem, it is necessary to determine the reference frame of the object, when the object is in the Milky Way, when the object is stationary relative to the reference frame, it is necessary to classify and discuss, when the external force of the object is 0, of course the object has no acceleration, when the external force of the object is not zero, then there is acceleration, the direction of acceleration is the same as the direction of its combined external force, according to Newton's second law, it can be known that f=ma, the magnitude of acceleration can be obtained, in fact, in the Milky Way, The acceleration of both a moving object and a stationary object can be known according to Newton's second law.
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Yes When the car is just started, there is traction according to f=ma there is f there is m so there is a At this time, the car is stationary so the object at rest can have acceleration.
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Of course not! In layman's terms: acceleration is a variable that describes how fast or slow an object is from rest to a certain speed!
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The object at rest is in equilibrium, there will be no acceleration, acceleration a = velocity change v time t, no change in velocity, acceleration a = 0
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Yes, a=mg; Acceleration is only related to the mass of the object and g, not the velocity of the object. According to f=ma, there is f, there is m, so there is a
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There can be, for example, when the vertical upward throw reaches the highest point, the object velocity is 0 and the acceleration is g
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Yes, there is no such thing as an absolutely stationary object in relation to a moving object.
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There can be objects at rest with a net force of 0
According to Niu II's law, the net force can be non-zero
If you don't understand, ask me again.
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Answer: Acceleration a=0 Rest Illustrates force balance Force balance Force-balanced Net force is zero Acceleration is zero.
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Objects are always relatively stationary! Before we have the ability to determine the center of the universe! Objects are always in motion!
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Objects are not originally stationary, all objects, it is relative to motion, and it is also relative, relatively stationary.
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1) A stationary object accelerates for a period of time, and after reaching a certain speed, if the speed remains unchanged, it can also move in a straight line at a uniform speed. It is also possible to decelerate slightly, but not to zero, or to do a uniform linear motion at a new speed.
2) The object changes from rest to motion, and the motion state of the object changes, and there must be an external force in this process, and the direction of the external force is the same as the direction of motion (But this does not mean that force is the cause of the motion of an object)。After the object moves from moving up to maintaining a uniform linear motion, the resultant external force it experiences is zero, and there are two possibilities:
The magnitude and direction of the force that causes the object to change its state of motion change, and it reaches equilibrium with other forces.
This force is withdrawn.
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The velocity is v, the displacement is s, the time is t, the muzzle velocity is 0, and the initial displacement is 0
The problem is known: v k*s , k is the scale coefficient (constant) plus the speed of Qiaobochang is a, then it is obtained by a dv dt.
a=dv /dt=d(k*s) /dt=k* ds / dt=k* v
So, a k*(k*s) k 2* s
It can be seen that with the continuous increase of displacement, the acceleration also increases.
That is, the motion mentioned by the title Yinlu is: a variable acceleration motion with an initial velocity of 0 and an increasing acceleration.
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