C Simple program modification, C Simple program modification

If you understand correctly, you want to use a common method to call, pass the parameters, the following is the easiest, if you want to make a common call method, you can try to add a form name parameter, modify the form appearance method.

Specify the border style for the form.

Specifies how the window is displayed.

private void modify_form(formborderstyle fbs, formwindowstate fws)

fbs; fws;

Modify the form appearance method.

Specify the name of the form you want to change.

Specify the border style for the form.

Specifies how the window is displayed.

public void modify_form(form frmname, formborderstyle fbs, formwindowstate fws)

fbs; fws;

What's going on here? I didn't get it.

What are you going to change it to???

Just change the operator overload method to the following!

static public fensu operator +(fensu a, fensu b)

int m= *

int n= *

int r=0;

int temp=0;

int p=0;

if(m>n)

temp=n;

n=m;m=temp;

p=m*n;

while(m!=0)

r=n%m;

n=m;m=r;

return (new fensu((

Enter 3 integers: 90 78 21

Enter 3 floats.

Three integers: 90 78 21

The maximum value of the first two integers: 90

The maximum of three integers: 90

Three floating-point numbers:

The maximum value of the first two floating-point numbers.

The maximum value of three floating-point numbers.

press any key to continue#include

using namespace std;

int max(int x1,int x2)double max(double d1,double d2)int main()

It may be that you have closed the connection on the client side before you have finished reading the data on the server side, so try to close the operation on the server side! The shutdown of the client is removed.

if, just add a condition, change it to this: if(3*a+b==1862 &&b >= 0).

#include ""

int main()}

Adopt Oh, pro (the previous sent wrong, modified the next).

The final output function is written incorrectly, it should be pintf("%d",s[k]);bar.

If so, fill in k=p;