For a few math problems about the limit, the number of coins will be increased to 30 if you have a s

Click to enlarge and then right-click Save to your desktop to open it with Paint.

Question 2 misses a minus sign, which is - 4

The method of arguing and fighting is as follows, carrying the grind.

Please do the divination test:

Some of the common equivalents of the age of the empty are kept in mind, and the block can quickly answer these limit questions.

The interpretation of the gods is shown in the diagram of the blind spine grip seepage in the following paragraph.

When x 0, lim (e 5x-1) x, which belongs to the 0 0 type, can be answered by the law of the Luo ruler cover the tower.

lim (5e 5x) 1, which is a normal function, substituting x 0 into it, will make a fuss.

So, the limit of the original formula is 5

It is possible to use the law of Lopida for the lack of delay, the condition is 0 0 or infinite infinite, and the formula of the upper Dan year is in line with the above article, and the derivative can be sought up and down, that is, the answer is 5

It's very simple, with the Lopida Rule.

In this case, the full multiplication can cancel out (n (n-1) in the n-1 term and (n-1) n in the nth term), and the original formula = (n+1) 2n = 1 2

2.(x^2-4)/(x^2-3x+2)=(x+2)(x-2)/(x-1)(x-2)=(x+2)/(x-1)=4

When it tends to 0, 1-cosx is equivalent to 1 2*x 2 in Sizhou, sinx is equal to x, and it is enough to substitute it into the original formula, and finally = root 2 2

4.I don't understand this formula, so let's make it a little clearer.

6) Divide the numerator and denominator by x, and the result is 3 4

10) The numerator and denominator are all 50, so just compare the coefficients. The coefficient of the numerator is 2 30, the denominator is 2 50, and the result is 2 (-20).

14) The formula for summing the proportional series, when the common ratio |q|<1, s=a1 (1-q)The numerator limit is 2, the denominator is 3 2, and the result is 4 3

It's been a long time, it should be like this, and the grandson of Lu Sun saw ** and learned to roll

Multiply the numerator denominator of the (x-1) bridge by x+1 at the same time to obtain (x2- x+ x-1) (x-1).

x+1+√x

So the limit is: 3.

This problem is the limit of 1 to the infinite power, utilizing.

1+ ) Approaching infinity) e a, a=

Teach you once and for all:

lim (1+u)^v = lim exp(v*ln(1+u)

u->0, v-> inf

Note that there is an equivalent infinitesimal here: ln(1+u) u then bring back to the original formula has.

lim (1+u)^v = lim exp(v*u)u->0, v-> inf

Combine this question with you: u=-5 x; v = x-1 then the original formula:

lim (1-5/x)^(x-1) = lim exp = lim exp = exp(-5)

This question is not to answer the teacher's question, but to ask the question as a teacher.

Teachers always think of the answers in advance, and then simplify them step by step to give the students the answers.

The question from the netizens upstairs is only one-third right:

1. The meaning of the question is that two specific values cannot be taken, and the question from the netizens upstairs can only be taken if x = -3, but the limit exists.

2. x = 2 Although it cannot be taken, the limit does not exist, which does not fit the topic.

3. The question must be like a question, and should not be given a factorization form, and the latter question is more like a question.

For specific, detailed, and in line with the topic, please refer to the figure below, which can be clicked to enlarge.

If you have any questions, please feel free to ask, answer questions, and explain questions;

The answer must be meticulous, the interpretation must be sincere, and the picture must be exquisite.

It is a 0 0 type, and the derivative method can be used up and down.

After derivation, it is under the root number (3+2x) divided by the root number (x+5), and the limit is 1 2