If the solution set of the inequality groups x a b and x a b is 1 x 2, find the values of a,b

The solution set for the inequality group xa-b is -1a+b=2a-b=-1

The solution yields a=1 2 b=3 2

Solution: Derived from the question:

a-b＜x＜a+b

1 x 2.

a-b=-1①

a+b=2②

Solve the system of equations.

a=1/2b=2/3

The solution set for the inequality group xa-b is -1a+b=2a-b=-1

The solution yields a=1 2 b=3 2

Remember to be careful when writing!

Solution: Derived from the question:

a+b=2a-b=-1

The solution yields a=1 2

b=3 2 I don't know that it is expired m has.

Solution: Derived from the question:

a+b=2①

a-b=-1②

The solution yields a=1 2

b=3 2 You have to learn to draw inferences.

Solution: {a+b=2(1)

a-b=-1(2)

1)+(2) gives a+b+a-b=2-1

a=1/2(3)

Substitute (3) for (1).

1/2+b=2

b=3 2, so {a=1 2

b = 3 2 Answer: A is 1 2, b is 3 2

Solution: From the meaning of the question, {a-b x a+b}={-1 x 2}, the original inequality group can be reduced to.

So: a-b=-1

a+b=2 gets: 2a=1 solves.

a=b= a=1/2

Substitute a = 1 2 to get .

The solution of the group of inequalities b=3 2 is.

a=1 2b=3 2Answer: a=1 2

b=3/2

Let's start with the inequality: ax>b

of the solution set. Because a is a real number, the range of values of x is required, and both sides of the inequality must be "multiplied" by 1 a, or the two sides of the inequality divided by a

1) If a>0, then x>b a, in this case, the solution set of inequality ax>b is;

2) If a<0, then the solution set of xb is, then the range of values of a is:

The problem should be a condition that omits b: 2x-a

x-2b solves this inequality to form (2b+3), so 2b+3=-1

b=-2a+1)/2=1

a=1so(a+1)(b+1).

x-2a+b<0

Shift items: x 2a-b

2x+3a-5b>0

Shift: 2x 5b-3a

Divide 2 on both sides at the same time.

x 5b-3a hail 2

Because the solution set of the inequality implicit group x-2a+b<0, 2x+3a-5b>0 is -1, 2a-b=6

5b-3a/2=-1

The solution is a=4 and b=2

The number of x> excitation a, the solution set of x>b is x>a

Then you can know that a>b is the same as the biggest.

and a<0, then b is also less than 0

So -b>0, x lead J-b

b>A and the two potatoes have no intersection.

So the solution set is an empty set.

First of all, a is not equal to 1, because, if there is a lack of a = 1 generation of people to argue the inequality of: 0>0, it is illogical to argue sensitively.

Secondly, if the solution set is x<1, we can see that when both sides of the inequality are divided by a-1, the unequal sign changes, so there is a-1<0, i.e., a<1

In summary, the value range of a is a<1

Solution: (a+b)x-(2a+7b)>0

a+b)x>2a+7b

Because its solution set is x<-3, when both sides are divided by a+b, the direction of the unequal sign changes, a+b 0

x<(2a+7b)/(a+b)

So (2a+7b) (a+b)=-3

2a+7b=-3(a+b)

5a=-10b

b=-a/2

Because a+b 0

So a-a 2=a 2 0

It can be obtained: a-b=a+a 2=3a 2 0

Solution inequality (a-b) x 2a+b

Both sides are divided by a-b, and the direction of the unequal sign changes.

x＜(2a+b)/(a-b)

2a+b)/(a-b)

2a-a/2)/(3a/2)

1, so the set of solutions for this inequality is x 1

change in direction of the unequal sign; (2a+7b) solution; (a+b)=-32a+7b=-3(a+b)

5a=-10b

b=-a, the direction of the unequal sign changes.

x＜(2a+b)/,a+b＜0

x<(3a/2=3a/0

a+b)x>-3：

a-b=a+a/2a+7b

Because its solution set is x<2 0

Available; 2=a 2), so both sides are divided by a+b; (a+b)So(2a+7b) :(a+b)x-(2a+7b)>(a-b)=(2a-a2 0

Solution inequality (a-b) x 2a+b

Divide both sides by a-b; (a-b)

2a+b)/2

Because a+b 0

So a-a

0(a+b)x>2

Because a+b 0

So a-a 2=a -3:

a-b=a+a/(a+b)

So (2a+7b) 2 0

Solution inequality (a-b) x 2a+b

Both sides are divided by a-b, and the direction of the unequal sign changes.

x＜(2a+b)/(a-b)

2a+b) :(a+b)x-(2a+7b)>2), so both sides are divided by a+b haha··· The eighth week of weekly practice wow...

Untie; (a-b)

2a-a/(3a/,a+b＜0

x <, the direction of the unequal sign changes; 2a+7b

Because its solution set is x<2=3a2 0

Available; (a+b)=-3

2a+7b=-3(a+b)

5a=-10b

b=-a/(2a+7b)/

y=x²+2x+a=(x+1)²+a-1)≥a-1a=y=-x+3≤0，x≥3

b = because a is really contained in b

Therefore, the point representing (a-1) on the number line must be to the right of the point representing 3 and cannot coincide with 3.

So there is, A-1>3, A>4

The value range of the real number a is a>4

a Less than 0

Because x a is b

The symbol changed.

From a greater than sign to a less than sign.

So a is not a positive number.

But because a is the denominator, it cannot be equal to 0

So a is less than 0