-
y+1/3-y-1/2≥y-1/6
y-y-y-1 6+1 2-1 3 (move the term, move the unknown to the left, move the constant term to the right, note the change).
y 0 (merge similar items).
y 0 (a negative sign before an unknown number, remember to change the unequal sign when divided by -1).
2+3(x+1)>3x-1/4
2+3x+3 3x-1 4 (brackets).
3x-3x-2-3-1 4 (move the term, move the unknown to the left, move the constant term to the right, note the change).
0 -21 4 (There are two possibilities for unknowns to be eliminated: 1If the solved inequality is correct, then all real numbers can be solved; 2.If not, there is no solution).
ps: In fact, solving inequalities is exactly the same as solving equations, they are all according to the parentheses, merging similar terms, and simplifying a few steps, but there are several special cases for the answers to be solved in the final solution of inequalities: the unknown is preceded by a negative sign, and remember to change the direction of the unequal sign when dividing by -1; There are two possibilities for unknowns to be eliminated:
1.If the solved inequality is correct, then all real numbers can be solved; 2.If not, there is no solution).
-
y+1 3 - y-1 2 y-1 6 <***** Write it right? y-y=0
1/3-1/2+1/6≥y
y 02+3(x+1) 3x-1 4 <***** what is this? After elimination, 3x is gone.
2+3x+3>3x-1/4
3x-3x>-1/4-2-3
-
2x 3 Behs 1
2x <-4
x Sell Lu 6 If the regret distribution is helpful to you, please give and praise, thank you for pulling I wish you good progress in learning!
-
(1) Remove the parentheses, 6-3x-3 1, shift the term to obtain, -3x 1-6+3, merge the same kind of term, -3x -2, the coefficient is 1, x 2 3
It is represented on the number line as follows:
2) 3(x-2)+8>2x①
x+1 3x-x-1 2, by , x -2, by , x -1, on the number line, is expressed as follows:
So, the solution set of the inequality group is -2 x -1
-
Remove the parentheses, 3[y-2y+14] 4y
Remove the middle brackets, 3y-6y+42 4y
Shift the term to obtain 3y-6y-4y -42, merge the same term to obtain -7y -42, and reduce the coefficient of x to 1, x 6
-
1)6-3(x+1)<1,6-3x-3<1,3x<1-6+3,3x<-2,x>2
The set of solutions representing inequalities on the number line is:
2) The solution set of inequality 3-x 0 is: x 3, the solution set of inequality 4x+1 x+7 is: x 2, the solution set of the inequality group is: x 2, and the solution set representing the inequality group on the number line is:
-
1+2x<3+x①5x≥4x?1, from : x 2, from : x -1, the set of solutions of the group of non-scattered equations is -1 x 2, and the set of solutions of the group of inequalities is expressed on the number axis of the punch letter grip as:
-
(1)5(1+2x)+2(1-3x)>-45+10x+2-6x>-4
4x>-11
x -11 represents the solution set on the number line as:
(2) Solve inequality 2x-1
5x+1 gets x -1
Solve the inequality 5x-1 3(x+1) to get x 2 The set of solutions for the group of inequalities is -1 x 2
Represent the solution set on the number line as:
-
1) Remove the parentheses, 8-8x 20-5x+3, move the term to obtain, -8x+5x 20+3-8, merge the same kind of terms to obtain, -3x 15, the coefficient of x is 1, x -5, on the number line is expressed as:
2) denominator, 3 (3y-1) 10y+5-6, deparentheses, 9y-3 10y+5-6, shift term, 9y-10y 5-6+3, merge similar terms to obtain, -y 2, the coefficient of x is 1, y -2, expressed on the number line as:
Fractional inequalities are reduced to integer inequalities and solved. The solution of a fractional inequality is as follows: the first step is to remove the denominator, the second step is to remove the parentheses, the third step is to move the terms, the fourth step is to merge the same terms, and the fifth step is to reduce the coefficient of the unknown to 1. >>>More
Let's say there are x boxes, y parts.
Get the inequality. >>>More
Solution: <>
Solve inequality , x 1, solve inequality , x 3, on the number line as follows: >>>More
The answers are: a>1, in the range of (1 a,1);
When a=1, there is no range less than 0; >>>More
1. Multiple choice questions.
1. If a, b are arbitrary real numbers, and a b, then ( >>>More