Solving! High score !! 50

2x squared - 3x = 0

2(x^2-3/2x)=0

2(x^2-3/2x+9/16-9/16)=02(x^2-3/2x+(3/4)^2)-9/8=02(x-3/4)^2=9/8

x-3/4)^2=9/16

x-3 4 = plus or minus 3 4

x=0 or x=3 2

x squared - 6x + 9 = (5-2x) squared.

x^2-6x+9=4x^2-20x+25

3x^2-14x+16=0

Bring in the root finding formula 2a, negative b, plus or minus the root number, b square, minus 4ac14, plus and minus the root number, 196-192) 6

14 plus minus 2) 6

x = 2 or 8 3

The first brother to answer the question, the symbol is miscalculated.

1) 2x squared - 3x = 0, that is: 2 (x-3 4) - 9 8 = 0 so (x-3 4) square = 9 1 get x-3 4 = plus or minus 3 4 get x = 0 or x = 3 2

2) x squared - 6x + 9 = (5-2x) squared, 3x square - 14x + 16 = 0, there is the root finding formula x = -2 or -8 3

There are 34 people playing table tennis at the same time on 12 table tennis tables, how many tables are there for singles and doubles?

34 12 2 10 (person) 10 2 5 ( sheet) 12 5 7 (sheet).

A: There are 7 singles and 5 doubles.

The cage contained a number of chickens and rabbits, which had a total of 56 legs; There are also 4 more chickens than rabbits, how many chickens and rabbits are in the cage?

56 2 4) (4 2) 8 8 4 12 (only).

A: There are 12 chickens in the cage and 8 rabbits.

100 monks eat 100 steamed buns, big monks eat 4 each, small monks eat 1 for every 4 people, how many people are there for each big monk and small monk?

100 4 100) (4 1 4) 80 (person) 100 80 20 (person).

Answer: There are 20 big monks and 80 small monks.

17 grams of gold and 10 grams of silver, weighed in water are reduced by 1 gram, now there are 105 grams of gold, silver, alloy, weighed in water to get 98 grams, how many kilograms of gold weigh? How many kilograms does silver weigh?

105 98 7 (g) (17 7 105) (17 10) 2 10 2 20 (g) 105 20 85 (g).

Answer: Gold weighs 85 grams. Silver weighs 20 grams.

There are three classes in the sixth grade, the first and second classes account for five-sevenths of the total number of students, the first and third classes account for two-thirds of the total number of students, and there are 40 students in the first class of the sixth grade.

40 (5 7 2 3 1) 105 (persons).

A: There are 105 students in the whole grade.

There are Y tables for singles x and doubles.

2x+(12-x)=34

Chickens x rabbits in a cage.

6*x-4*4=56

Big monk x small monk Y people.

4x+ gold weighs x kilograms, silver weighs y grams.

16x 17+9(105- x) 10=98 x people in all grades.

40/(5/7+2/3-1)=x

Idea: From the first figure, we can know that two square and two cylinders are 40kg, then the second lead figure is 20kg with a square and a cylinder, so the circle is 10kg, and the branch is good because the two circles and a cylinder in Figure 3 are a total of 32kg, so the cylinder is 32kg-2 10 = 12kg, so the square is equal to (40-12-12) 2 = 8kg

So the answer is, square 8kg, round 10kg, cylindrical 12kg

Let x, y, z, list 3 equations, and solve them.

The first lane is 1o, the second lane lo, and the third lane is 12

Cubes 8 dg, cylindrical 12 dg, round 10 dg.

19 Reducing the stool is small.

21 Stress area Reduce the pressure of jujube collapsing.

22 Upper and lower B.

24 small low enlarged shirt board raised.

25 pressure difference suction orbit (I can't see clearly, I guess this means) satisfied.

It's ......Isn't it ...... at all?

It's been a long time since I've done it

1) The axis of symmetry is x=-1, and one of the intersection points of the x-axis is (2,0), so a is (-4,0), because 2 and -1 are 3, and the other is -1-3=-4

Then oc=2oa because a is (-4,0) so oa=4 so oc=8, so c(0,8).

d is the point of symmetry of a with respect to the y-axis, a(-4,0) so d(4,0).

2) What do you need to say about the second question......?It's good to substitute the three dots ......

3) It's also very simple, substituting (0,3) into what you calculated in the second problem, and calculate mn, because mn is horizontal, so the height of the parallelogram is the absolute value of (y-3) with high, with mn, with high, the formula for s comes out.

4) I don't know ...... because I didn't calculate the formulaI guess that the formula is a parabola with an opening downward, and it should be easy to find the extremum, right?

I'm sorry I didn't calculate it, but it's best not to copy the question, it's better to know the method and calculate it yourself Remember next time

Closed shed: an=1 (1+2+.n)=1/[n(n+1)/2]=2*[1/n-1/(n+1)]

The god is split by 1 + (1 + 2) and 1 + (1 + 2 + 3) of the slag 1 + +...1+2+3+4+..n) 1 out of 1

2*(1-1/2)+2*(1/2-1/3)+2*(1/3-1/4)+.2*[1/n-1/(n+1)]

2*[1-1 (n+1)] The middle terms are all minus) 2n (n+1).