Math Problem So what is the probability that the sum of the two integers will be 3 in the end?

Let the decomposition be two numbers A and B, and a can be obtained according to the division of the interval to obtain the probability of .

Let x+y=

0<=x,y<=

x,y evenly distributed.

p: When x belongs to [0,1 2], then [x]=0, y belongs to [,2],[y]=2, when x belongs to [1 2,1], then [x]=1, y belongs to [2,,y]=2, when x belongs to [1,,[x]=1,y belongs to [,1], [y]=1, when x belongs to [,2], then [x]=2, y belongs to [1,,y]=1, when x belongs to [2,then [x]=1,y belongs to [,0],[y]=0, when 1 2<=x<=1, or <=x<=2, the condition is satisfied.

Therefore, p=1 If you have any opinions, welcome to discuss and learn together; If it helps, select Satisfied!

It was with a pen in the title of the draft, and I wrote a lot of trouble.

I think to find a figure in the square around 2000!

The square of 45 is 2025, and the year 2025 is minus 45, which is 1800. So, you want to add 23 = 2025 + 23 = 2048, check 2116 46 square, so set up! ！

Let the number of positive integers be n and the number of negative integers be m, then the total number is (m+n).

p(m+n) 1)*(p(m+n) 1)=(m+n)*(m+n)=(m+n) 2 (where m, n are positive integers).

That is, the probability of the sum of any two integers is (m+n) 2

Is the sum odd or even? You can make it clear, huh? The probability teacher you said is not worth it, why are you calm?

What is the probability of the sum of any two integers? The meaning of the title is not clear!

Are you asking what is the probability of the sum of any two integers or what is waiting for something?

f( )=cos simplification to sin =-1 5 because is the third quadrant angle, so cos =-2 6 5=f( )=-1800-60, so f( )=cos(-1800-60)=cos60=1 2