Problems with the principle of the Fiesso light speed experiment

Fisso's speed of light I think it should be ......It's ......

The light source S, a semi-silver-plated flat mirror A, is reflected by A, and is emitted from the inter-tooth space of gear n onto the mirror M, and then reflected back and into the observer's eye through the semi-silver-plated mirror.

When the gear rotates, the light will be rotated at an angle when the light travels from the teeth to m and then is reflected back to the time δt between the teeth. If the gear turns to the next interdental space, the light reflected by M passes through the interdental space, and the observer can see the light again. The number of teeth of the gear is known, and the speed of light can be calculated by measuring the speed of the gear, and the time δt of the gear turning one tooth can be calculated, and then the distance between m and n can be measured.

Fisso measured the speed of light in the air at the time:

c 315,300 km/s.

That's how it works, and the previous speed measurements were based on c = s t

Calculation steps: According to the 720 gears you say your RPM * 2 = r s

The distance from the mirror to the light source is 8000 m

The linear velocity v = r = 2 n is calculated first

With the linear velocity, δt is then calculated; t = s t ( s is calculated, this is the distance between the two gears, i.e. a circle is divided into 720 parts. Because there are 720 gears, the arc length is used to calculate the line, and the perimeter is also OK).

Radian calculation: s = l = ( 2 720 ) r

The perimeter is calculated as s = c = 2 r 720

This counts ,,,t = s v

<> this principle is very simple, because there were no advanced instruments before, so the most primitive formula was used. Schematic:

As for the natural factor you mentioned, it should be the conditions of the experiment, the right weather and the place. I think it should be the choice of light source, if you want to say, there should also be the weakening of the light source, the refraction, diffraction, reflection, and scattering of natural air, because the speed of light is too fast, some unnecessary factors are canceled, maybe it is ignored, I don't know the specifics, probably that is, the theory of relativity, this has to ask Einstein.

Since it is observed by the eyes, it will be necessary to pay special attention to it, and since the eyes are very close to the lens, there should be no problems.

Do you see anything else to add? Hey, hey......

<> through this diagram.

You should be able to figure it out.

Can this diagram give you an idea.

The calculation should not be difficult.

v=s ts which part.

t How to calculate, a little trick.

The speed of light is so fast, how did Fiso measure the speed of light?

The incident ray is not affected, as long as the gear turns a tooth pitch ray can be shot through, mainly the past is reflected back, if the gear turns a tooth pitch when shooting back, the reflected light will be blocked and not seen.

To put it simply, the incident light can always shoot through when it is blocked, and the reflected light is blocked, and it is impossible to see it when it dies.

v=s t where s is 16 km and t is the time to turn a pitch is 1 second, then:

v=s/t16km/（1/

Based on your data, I did my best.