How to determine whether it is a Chinese character, how to judge whether a character is Chinese

This is a **:to determine whether there is Chinese in the string

#include

#include

int main()

char sztext = "It's ciw";

char c = 0;

char szchinese[3] = ;

int i = 0, nlen = strlen(sztext);

for(; i < nlen; i++)

if( sztext[i] >= 0 &&&sztext[i] <= 127 ) is not a double-width character?

c = sztext[i], printf("%c", c);

else is a full-width character.

szchinese[0] = sztext[i], szchinese[1] = sztext[i + 1], printf("%s", szchinese), i++;Chinese is 2 bytes, so i++

return 0;

Call the getbytes() method for that character, and if the returned array length is 2, it is a Chinese character, because unicode is two bytes long.

Unicode: The Unicode encoding range of Chinese characters is U4E00- U9FA5

uf900-\ufa2d

If it's not within this range, it's not a kanji. So just get a char to determine if it's within the above range.

u+4e00 u+9fb0 is the original Chinese character in GB2312 and GBK.

u+3400 u+4db6 includes those added kanji in .

Determine whether a character is Chinese.

public static boolean ischinese(char c)

Determine whether a string contains Chinese.

public static boolean ischinese(string str)

return false;}

Take advantage of the feature that one Chinese character occupies two bytes.

Use the len and lenb functions to find the number of characters and bytes of the string respectively, if the number of bytes is greater than the number of characters, it means that the string contains Chinese.

An example formula is as follows:

if(lenb(a2)-len(a2),"Contains Chinese","Does not contain Chinese")