At first glance, it makes sense, but the actual calculation does not, the question of the relationsh

There is something wrong with your calculus ...

So we may take it for granted that when we go upwind is a little slower, but when we come back, it is tailwind, and one slow and one fast cancels off, which should be the same as the time it takes when there is no wind.

This sentence does not make sense.

Time = distance speed.

Since division is used, it is necessary to consider the problem of multiples.

The dividend and the divisor change by the same multiple, and the quotient remains the same.

When downwind, the airspeed is 150, and the ground speed: 150 + 60 = 210 The ground speed is 210 150 = 7 5 of the airspeed

The time taken is 5 to 7 when there is no wind

When the wind is headwinded, the airspeed is 150, and the ground speed: 150-60=90 is 90 150=3 5 of the airspeed

The time taken is 5 3 when there is no wind

The time taken to travel round trip is less than when there is no wind: 1-5 7=2 7 and one more: 5 3-1=2 3

Therefore, the round-trip time is more than twice the time when there is no wind.

One back and forth speed neutralization?! That's true, but that doesn't mean it takes the same amount of time! Because of the time required, speed is not reflected in the calculation in the form of simple addition and subtraction at the moment!

Although the numerator does not change, the velocity is added or subtracted as the denominator. If the other way around, the numerator is added and subtracted, and the denominator does not change, then your understanding is correct. You can just take a number and practice verifying it.

I'm sure you probably figured it out without reading it.

The upstairs solves the problem in a different way, and the conclusion is actually the same as that of the landlord. But the first half of the idea on the first floor was right.

The round-trip time is more than twice that of the windless time, which is logically confusing.

No matter how you calculate it, it is a downwind plus a headwind, and it takes 19% more time than no wind, which is actually not a contradiction. It would be nice to ignore the last sentence on the first floor.

Of course" because you're flying against the wind longer.

Illustrated by the equation, let the distance be s, the airspeed of the aircraft is a, the wind speed is b, then the windy case t1=s (a+b)+s (a-b) and the windless case t2=2s a

t1=2sa (a -b) Obviously, t2=2s a (a>0,b>0) because a > a -b so a (a -b )> 1 a so t1 >t2

Time = distance speed right;

Distance = time speed right;

Speed = Time Distance Wrong, it should be: Speed = Distance Time.

This is a calculation method in general life, depending on the situation in which it is used. In physics, velocity is a physical quantity of magnitude and direction, and strictly speaking, the above is not correct.

Math is true.

But in physics, we have to put it another way, time = displacement velocity displacement = time * velocity velocity = displacement time.

The third mistake should be the speed = distance and time of Lala.

The relationship between distance, speed, and time:

Distance = Speed Time Edition.

Speed right = distance time.

Time = distance speed.

In rectilinear motion, the distance is the length of the rectilinear trajectory; In curvilinear motion, the distance is the length of the curve trajectory. When an object returns to its original position after a period of time during motion, the distance is not zero, and the displacement is equal to zero.

The relationship between time distance and speed is as follows: 1. The distance is equal to the time multiplied by the speed, and the calculation formula is: distance = speed x time.

2. Speed is equal to the distance divided by time, and the calculation formula is: speed = distance time. 3. Time is equal to the distance divided by speed, the calculation formula:

Time = distance speed.

The relationship between time distance and speed is as follows:

distance = speed time;

Speed = distance time;

Time = distance speed.

Analysis] When the distance is constant, the faster the speed, the shorter the travel time, so the speed is inversely proportional to the time;

When the speed is constant, the distance is proportional to the time;

When time is constant, the distance is proportional to the speed.

The distance is equal to the time multiplied by the speed, the speed is equal to the distance divided by the time, and the time is equal to the distance divided by the speed.

Speed x time = distance, I'm talking about constant speed, thank you, give me points.

For uniform motion:

distance = speed time;

Speed is equal to the distance in time. v=s/t

Distance = Rate Time.

Displacement = velocity time.

To know the speed ratio, there must be a fixed value of one item in the distance and time before you can know the ratio of the other.

If the distance is constant, time and speed are inversely proportional.

If the time is constant, the distance is proportional to the speed.

7 seconds and 41 seconds are seconds, and speed is equal to distance divided by time which is 60

Seven minutes and forty-one seconds were replaced by 461 seconds.

Because time velocity = distance, known distance is certain, that is, the product of velocity and time, so time is inversely proportional to velocity.

In the natural sciences, distances are certain, distances are not necessarily, and time and speed are disproportionate.

The distance is certain, the distance is certain, and the time and speed are proportional.

Disproportionate, unless the displacement is said to be constant, time and average velocity are inversely proportional.

The formula s=vt tells us that the distance is certain, and the greater the speed, the shorter the time, so it is obviously inversely proportional.

The distance is certain, and the speed and time are inversely proportional, because the speed of time and the distance are certain, and when the distance is certain, that is, the product of speed and time is certain, so it is inversely proportional.