Everybody helped me get these four math problems done!

1.Solution: Analysis: The area of a square brick with a side length of a meter = square meters), then 128 blocks have a total of 128 * square meters), and the area of a square brick of a meter = square meters).

So, 32 blocks are needed. ）

To reuse square bricks with a side length of one meter, x blocks are required.

x=32 x=200Answer: Switch to square bricks with a side length of meters, which requires 200 pieces.

2.Solution: If there are x girls in the pool, there are 3x boys, 3x-18=x3x-x=18

2x=18x=9

So it turns out that there are 3*9=27 boys.

A: There were 27 boys and 9 girls.

3.Solution: If Xiao Ming is x years old this year, he was X-3 years old three years ago.

6（x-3）=33-3

6x-18=30

6x=30+18

6x=48x=48/6

x=8A: Xiao Ming is 8 years old.

1 solution: square meters.

Square metre. Square metre.

32 blocks.

2 Solution: If there are x people for girls, there are 3x people for boys.

3x-18=x

So x=9 27 boys and 9 girls.

3 Solution: Three years ago, my mother was 33-3=30 years old.

Three years ago, Xiao Ming was 30 6 = 5 years old.

Three years later, Xiao Ming is 5+3=8 years old.

1 The area of a square brick is, the total area of the classroom is 128*, so 32 (blocks.

2. Let the number of boys be x and the number of girls be y x=3y; x-18=y;The solution is x=27 and y=9

3 Let Xiao Ming be x years old this year 6 (x-3) = 33-3 x = 8

2. It is twice as many as girls, so girls have: 18 2=9, boys have 9x3=27

Question 1: 200 pieces Question 2: 27 boys, 9 girls Question 3: 8 years old.

1.First of all, it should be clear that: c 2 = a 2 + b 2 = (a + b) 2-2*ab; From the equation, a+b=(2m-1), ab=4(m-1); Just bring it in and get m=;

2.(1) 12 2-25 +12 2; Then use the solution of problem 1 to substitute 12 2 + 12 2 = 12 ( +2-24 , and substitute it accordingly.

2)( 2= 2-2 +2=( +2-4 Properties of the binding root, i.e. + =2, =-5 3 solved.

One; Because a+b=2m-1, ab=4m-4, and by a 2+b 2=25, a 2+b 2=(a+b) 2-2ab=4m 2-12m+9=25, i.e. 4m 2-12m-16=0, m2-3m-4=0, so m=4 or -1 (round).

Two; From the meaning of the title, a+b=2,3ab=-5

1(3a-4b)(4a-3b)=12a^2+12b^2-25ab=12(a+b)^2-49ab=48+245/3=389/3

2(a-b) 2=(a+b) 2-4ab=4+20 3=32 3, vested a-b

But I think the data is a bit problematic).

In the first question, according to a, b are the two roots of the equation x 2-(2m-1)x+4(m-1)=0, a+b=2m-1;

a*b=4m-4

It is also a right-angled triangle.

a^2+b^2=c^2=25;

a 2+b 2=(a+b) 2—2ab=(2m—1) 2—2(4m—4)=25, and the solution is m=4;

m=—1 (rounded).

1)a+b=2m-1

ab=4(m-1)

A square + B square = (A + B) square - 2ab = (2m-1) square - 8 (m-1) = 5 square = 25

Then solve it yourself.

It is important to remember the method.

2) (1) Original formula = 12 square + 12 square - 17 The method is the same as above.

2) -= under the root of plus and minus (( square-4 ) solution is the same as above.

I don't have a pen by my side, so I'll tell you the idea directly.

You've got a lot more on this question, don't you do it yourself?

Solution: (I'll just list the formulas, let's do the math myself).

2、 170／68＝x／2

4. (1 5 4) x = 450 (set up a squadron to distribute x saplings).

6. The volume is 5 6 2 3;Volume 3 kg decimeter = weight (if taking a decimal, pi is taken.)

10. Note that the result is centimeters, and the final result should be converted to kilometers according to the title, and then divided by 100,000).

Fourth, solve the problem.

1、 3/240=x/440

2、 x／15＝20／﹙20＋5﹚

3. (The question did not say that wheat is packed into a cylindrical grain hoard, and how much of the grain hoard volume only occupies it?) Let this ratio be m, then 0 m 1) then the height of the grain hoard is 1 3.

6. 10 10 (Note: The volume unit of the tomato is centimeter, which is converted to decimeters, so divide by 1000).

7. [20 (25 8)] 100 (result multiplied by 100 converted to centimeters).

Slightly more, children are still good at this kind of question, no one will help you in the exam, if you really want me to help you do it.

Lazy kids aren't good students.

1.When Dongdong first caught up with Jingjing, it took exactly one more lap than Jingjing: 200 (6-4) = 100 seconds.

Dongdong ran: 100 6 200 = 3 laps.

Jingjing ran: 3-1=2 laps.

2.Draw a line diagram and take a look.

The age difference between the master and the apprentice remains the same: (37-10) 3 = 9 years old this year, and the master : 37-9 = 28 years old.

Apprentice: 28-9 = 19 years old.

3.Is the order of the words correct?

I don't know if there's the answer you're looking for.

200 (6-4) = 100 seconds.

Dongdong ran 3 laps and Jingjing ran 2 laps.

This year, the master is 28 years old and the apprentice is 19 years old.

Question 1 3, 2

Question 2 28, 19

I didn't understand the third question.。。。

Laps, 2 laps.

2. This year, the master is 28 years old and the apprentice is 19 years old.

I didn't understand the third question either!

Master Wang walked x kilometers per hour.

Arrive at the unit 10 minutes in advance, Master Wang will save 5 minutes for the car to walk the distance from the platform to the unit, and walk 50*5 60=25 6 kilometers from the platform to the unit.

A total of 55 + 5 = 60 minutes, x = 25 6 1 = 25 6 (km h).

A to the m+n power.

There are formulas available; 50 to the 4th power multiplied by 50 to the 24th power = 50 to the 28th power.

2 to the 5th power + 0 + 2 to the 3rd power + 0 + 2 + 1 = 43

Equal to a to the power of mn. Equal to 50 to the power of 28. Corresponds to 43

1. A to the n+m power.

4 to the power + 50 to the 24 power.

50 to the power of 24+4.

50 to the 28th power.

A to the m+n power.

That's 50 to the 28th power, 43