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Anonymous users2024-02-09A mirror that requires you to be half as tall.
Because it is not convenient to draw pictures here, please prepare a piece of paper and a pen and think while drawing as I said.
The image of an object in a plane mirror is equal in size, equidistant and perpendicular to the plane mirror.
Since people and images are equal in size, they must be as tall. In the diagram, if the person and the image are connected by a line, is it a rectangle?
Since the distance between the person and the image is equal to the plane mirror, is the position of the plane image in the middle of the rectangle?
So now draw a rectangle first. Suppose the left side of the rectangle represents a person, and the right side represents the image of a person in a flat mirror. Then draw a vertical line in the middle of the rectangle to represent the plane mirror.
If we use another line to connect the top of the person's head with the feet of the image, is this line a rectangle diagonal? Does the diagonal line just bisect the plane mirror?
Suppose a person's eyes are on top of his head, and he can see his head and feet at the same time. But is the light he sees at his feet the diagonal we just drawn?
If we remove the lower part of the plane mirror, is that line still there?
Regardless of the distance between the person and the plane mirror, the plane mirror is always in the middle of the rectangle, and the diagonal always bisects the plane mirror.
To sum up, if a person wants to see his whole body image in the plane mirror at the same time, the height of the plane mirror must be half of his height.
Since it is not very convenient to draw and narrate here, the landlord can draw it on paper by himself and understand it more.
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Anonymous users2024-02-08It depends on where you stand from the mirror. If it's next to the mirror, you need a mirror that is the same height as you, and if it's farther away, a smaller mirror is fine.
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Anonymous users2024-02-07Your understanding is only understood from the human point of sight, and your understanding of the image is the scope of the line of sight, but in fact, the whole world is in this mirror, and the size of the image is not limited by the size of the mirror.
The mirror with half the height can see all the angles, from the foot of the image to the midpoint of the eyes is just half of the height, so as long as there is a mirror with half the height, and the highest part of the mirror is level with the top of the head, you can see the whole body clearly.
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Anonymous users2024-02-06It's a virtual image, which means it's not really imaged, it's just reflective, so it's not in the mirror.
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Anonymous users2024-02-05The height of the mirror is at least half the height of the person, h=
According to the law of plane mirror imaging, the distance between the person and the image is equal, and the height of the mirror is at least h = to see the picture.
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Anonymous users2024-02-04The conditions are insufficient, and people don't know how far away from the mirror?
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Anonymous users2024-02-03The triangle of the box is symmetrical.
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Anonymous users2024-02-02How tall do you need a mirror to see your whole body?
Answer: 1 2 of the height of the human body
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Anonymous users2024-02-01Draw the picture in this way The distance between the object and the mirror is equal to the distance from the image to the mirror, and with a similar triangle, the result is 1 2 for the length of the body
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Anonymous users2024-01-31The mirror is half the size of one's height and is placed at eye level with the upper edge of the mirror and parallel to the person.
As shown below, the left side represents the person, and the middle side is a mirror.
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Anonymous users2024-01-30The <> light path map is shown above: the mountain section.
The human pulse is like a high a'b'= person height ab
The effective length of the mirror cd=a'b'Quivi spine 2=ab 2
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Anonymous users2024-01-29This kind of question can be directly half of the line, and the picture cannot be drawn by mobile phone.
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Anonymous users2024-01-28Solution: As shown in the figure, AD is human, A is the top of the head, D is the foot, B is the eye, FE is the mirror, and FE AD, as FB AD in B, intercept AG 2AB, C is the midpoint of GD, EC AD is in C, EF is the mirror. ag 2ab, bf ag, gd 2gc, ec gd fb vertically bisected ag, ec vertically bisected gd and ad ef, 2fe ad and ad fe A:
Mirrors at least.
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