The relationship between ionized H is not skippable by the chemical elite

This is due to its nature.

Aluminum hydroxide is a white gelatinous substance that is almost insoluble in water. It can condense suspended solids in water and has the ability to adsorb pigments. In the laboratory, aluminum hydroxide can be produced by the reaction of aluminum salt solution with ammonia.

It is typical of amphoteric hydroxides.

Why is al(oh)3 bisexual? The principle of balanced movement can be used for a simple analysis.

Al(OH)3 is a weak electrolyte that ionizes with very few H+ and OH- ions. When acid is added to Al(OH)3, H+ immediately reacts with a small amount of OH- in the solution to form water, which ionizes Al(OH)3 according to the basic formula, shifting the equilibrium to the right, so that AL(OH)3 continuously dissolves. Conversely, when a base is added to Al(OH)3, OH- immediately reacts with a small amount of H+ in the solution to form water, which ionizes Al(OH)3 according to the acid formula, shifts the equilibrium to the left, and similarly, AL(OH)3 is constantly dissolved.

Emphasis: Aluminum hydroxide is insoluble in weak acids such as carbonic acid and insoluble in weak alkalis such as ammonia.

In layman's terms:

Assuming that aluminum hydroxide is soluble in acetic acid, then aluminum hydroxide becomes aluminum acetate, and aluminum acetate is a weak acid and weak alkali salt in water, which is easy to hydrolyze, and aluminum acetate becomes aluminum hydroxide back after hydrolysis, so it is insoluble in weak acid, and weak alkali is the same reason, because the product is unstable, easy to hydrolyze, and cannot exist in aqueous solution, so as a non-reaction, since it does not react, then aluminum hydroxide is still the aluminum hydroxide, which is naturally insoluble.

1.The hydroxyl group on ethanol is very stable and will not ionize H+ because of the electron pushing effect of the ethyl group, which increases the electron cloud density on oxygen, H+ is positive, and the electron cloud density on O increases, and the negative charge increases, and H+ should not leave.

The remaining two are also, the electron withdrawing makes the electron cloud on O have a small density and low electronegativity, which should not attract H+, and H+ should leave, so it is acidic. And because the electron absorption of carbonyl is much greater than that of phenyl group, acetic acid is more acidic than phenol.

2。It is precisely because the polarity of the sulfide-hydrogen bond is not as good as the oxygen-hydrogen bond, so it is more difficult for the H+ in the hydroxyl group to leave, so ethanol is less acidic than ethyl mercaptan. This is determined by the ability of S and O to bind protons. The S-H bond is weak, and H+ should be left.

1.According to the theory you can understand, it is to draw electrons and push electrons, and there is no need to say much else. The benzene ring is a large PAI bond with the ability to co-choke electrons, and acetic acid is not because of electron absorption, but more because of the fairly stable co-choke system of carboxylic acid anions.

Ethanol is not because the hydrocarbon group pushes electrons, but because it is too stable compared to the ethanol anion, which is quite unstable in the negative ion, and the hydrocarbon group cannot stabilize the negative charge at all.

2。This one is easy to understand, which is more acidic HCL or HI? Naturally, Hi, why, because I is much weaker in alkalinity than CL, and I electron cloud is too large and quite weak in offensiveness, like a marshmallow, unlike O2, it's like a small stone, don't look small, it's hard.

The difficulty of ionizing out H+ is related to the polarity of the bond and the magnitude of the bond energy. The stronger the polarity of the bond, the easier it is to ionize by interacting with the polar water molecules; The greater the bond energy, the more difficult it is to ionize.

There are -O-H in ethanol, phenol and acetic acid, due to the electron-withdrawing ability C2H5- (actually power-powered) ethanol compared with ethyl mercaptan, although the polarity of the O-H bond is stronger than that of S-H, but because the bond energy of the S-H bond is small, there are many O-H bonds (because the atomic radius of S is larger), which causes the S-H bond to be more easily broken and ionized under the action of water molecules.

The size of the acidity depends on the ability to ionize H, and the difference between O and S is that they have different periods in the same family. The chemical radius of S is larger than O, so the attraction of the outer electrons is O>S, and when forming a covalent bond, the attraction of O to H is greater than that of S to H, so it is not easy to ionize and is not acidic, while mercaptans are acidic because the attraction is not large enough to make H ionized and acidic.

Ethanol is neutral because of the electron pusher of the shutdown, phenol is weakly acidic because of the electron withdrawing of the phenyl group, and acetic acid is acidic because of the electron withdrawing of the carbonyl group. It is also due to the change in the attraction of the linked groups.

The title is about the rate at the beginning, that is, the rate at the moment of starting, not the average rate of the whole reaction. At the beginning, the concentration of H+ is equal, and the rate is naturally equal. Is the metal reacting with H+ well, and what does it have to do with the strength of the acid?

Yes, so you can understand it.

There are not many hydrogen and hydroxide from bicarbonate ionization and hydrolysis, while the salt hydrolysis degree of double hydrolysis is very large, and there are more H+ and OH-.

Bicarbonate is hydrolyzed in water and is alkaline, HCO3 - H2O = H2CO3 + OH -, do you mean why does hydroxide not react with hydrogen ions, the ionization of water is very weak, the concentration is not high enough to react, the double hydrolysis reaction is basically to generate precipitate and gas, which are very easy to get out of the aqueous solution system, so the reaction can be carried out easily.

a. It is not necessarily an acid that can ionize H+ to produce H+, for example, sodium bicarbonate can also ionize hydrogen ions, but it is a salt, so the answer is wrong

b. The compound must be pure, but the pure substance is not necessarily a compound, but may also be an element, such as oxygen, so the answer is wrong

c. The process of chemical change must be accompanied by physical change, but the process of physical change is not necessarily accompanied by chemical change, so the answer is wrong

d. If hydrogen and oxygen are burned to produce water, energy must be consumed when water is decomposed into hydrogen and oxygen, so the answer is correct

Therefore, choose D

Not completely, you can think of one like this, if it is a strong and a weak reaction, the H(OH) ions are constantly being reacted so that the weak ionization will be promoted. Then the hydrolysis is the hydrolysis of weak acid and weak alkali salts, just one to H ions, the other to OH ions, to promote each other.

To use the limit thinking, the temperature does not change, the ionization constant does not change, as the water is added more and more, the concentration of hydrogen ions and weak acid ions is getting smaller and smaller, in order to make the product equal to the ionization constant, the weak acid must continue to ionize, when the amount of water is infinite, ionization can be regarded as complete.

ch cooh ch coo +(h+), zn reacts with (h+), constantly decreasing c(h+), thus constantly promoting the above ionization equilibrium to move in the direction of ionization, as long as zn is sufficient, it can eventually be completely ionized and reacted with zn.

People come and go on the river, but love the beauty of sea bass.

It does not belong to a chemical reaction, the essence of a chemical reaction is that the old bond is broken and the new bond is formed, and only the covalent bond is broken in this process, and no new bond is formed, which does not belong to the chemical reaction.

Senior 1 Compulsory 2 Chapter 1 Section 3 Chemical Bonds This part has learned the essence of chemical reactions.

The ionization of HCl is not a chemical reaction as no new species is formed. Although there is a coordination bond between H+ and H2O, high school chemistry generally considers this process to be a physical change. A typical example is that concentrated sulfuric acid is dissolved in water and exothermic, the teacher told you that it should be a physical change, in fact, the principle and process are the same, and a similar change occurs in the dissolution of concentrated sulfuric acid in water, because there is a heat change in the ionization and formation process.

According to Le Chartre's principle, it can be known that in a chemical equilibrium where the reaction conditions do not change, when the amount of product increases, the chemical equilibrium is pushed to move in the opposite direction (in the direction of the reactants). Since HCl is completely ionized in water and produces a large amount of H+, the H+ in the system increases a lot, which promotes the ionization of acetic acid to move in the opposite direction. It can also be explained by the chemical equilibrium equation, k=c(h+)*c(ac-) c(hac), under the condition that the equilibrium constant is unchanged, the increase of h+ concentration in the system will lead to the increase of c(h+)*c(ac-), while k remains unchanged, and c(ac-) decreases and c(hac) increases to keep k constant, so the ionization of hac is inhibited by the addition of hcl.

Isn't that simple? HAC is a weak electrolyte, and ionization is reversible, so if you add a large amount of H+, ionization can be suppressed.

KW = 10 to the power -14, at this time the ionization of water c(h+) = 10-13mol L

a. Sodium bicarbonate can ionize H+, and at the same time ionize cation sodium ions, which is not an acid, but a salt, so A is wrong;

b. Although carbon monoxide contains carbon elements, its properties are similar to inorganic substances, and it is classified as inorganic matter, not organic matter, so B is wrong;

c. Sodium hydroxide is composed of three elements and does not belong to oxides, so C is wrong;

d. Blue alum can be used with the chemical formula CuSO4?5H2O means that it is composed of a substance and belongs to the pure substance, so d is correct

Therefore, choose D