Which master is going to help me with the math problem

1.(2) Divide by 5 = 8/20 = 6: (15) =

2.The circumference of a circle is that its area is (square meters).

3.The radius of a semicircle is 3 cm, and its circumference is (6) cm

4.In, 7/8, 5/6, the largest of these 4 numbers is (7/8), and the smallest number is (5/6).

5.For a project, it takes 12 days for A to complete alone, and 15 days for B to complete alone, and after 4 days of the two teams, there is still (2/5) of the project

6.Solve equations.

x + 7/9 x = 4/3 x = 5 9

3/4 x + 5x% = x = 22

4/3 divided by x = 5/6 x = 10 9

5/6 + 5/8) multiplied x = 7/20 x = 6 25

7.It's easy to calculate.

12 times (2/3 + 1/6) 12*2 3+12*1 6=8+2=10

7.Vocabulary questions.

There are 49 boys and girls in Year 6 (5) class, and the ratio of boys to girls is 4:3. Boys 4 7*49=28 girls.

3 7*49=21 That one is not in question.

Question 1: Question 2: Area of Question 2, Question 3, Circumference, Question 4, Question 5/6 Minimum, Maximum 7/8, Question 5, Question 5, Question 2/5 Remaining.

Have you learned the unknown? If not, then I'll give you a step-by-step write, it will be easier to understand! But after you understand, it will be better to write without step-by-step! Divide and divide.

Or you can take a as a number and multiply a + divide by a column to find the result of a. The result of the Zen Brigade with A is a certain number).

After dividing it into 3 cubes equally, 4 polygons are added, i.e. each polygon has an area of 30 square centimeters. (So the bottom surface of the cuboid is 30 square centimeters, and the side is 30 * 3 = 90 square centimeters), then the surface area is (30 + 90) * 2 = 240 square centimeters.

Solution: f(x)*f[f(x)+1 x]=1

Let x=f(x)+1 x

f[f(x)+1/x]*f=1

So f(x)=1 f[f(x)+1 x]=f is incremented by f(x) over x>0.

So x=f[f(x)+1 x]+1 [f(x)+1 x]substituting x=1

Then 1=f(f(1)+1)+1 (f(1)+1)f(f(1)+1)=1-1 (f(1)+1) according to f(x)*f[f(x)+1 x]=1 is substituted into x=1f(1)*f(f(1)+1)=1

So f(1)*[1-1 f(f(1)+1)]=1 gives f(1)=(1+root: 5) 2 or (1-root: 5) 2, since 1 f(1)-f(1)=-1<0, i.e. f(f(1)+1).< f(1) is monotonically increased by the function, so f(1)+1<1, f(1)<0 so the value of f(1) is (1-root, 5), 2< p>

∵f(x)*f[f(x)+1/x]=1

f[f(x)+1/x]*f=1

From the above two formulas.

f(x)=f

f(x) is an increasing function on x>0.

x=f[f(x)+1/x]+1/[f(x)+1/x]∵1/f(x)=f[f(x)+1/x]

x=[1/f(x)]+1/[f(x)+1/x]∴x²*f(x)²-x*f(x)-1=0

Taking f(x) as an unknown, the unary quadratic equation is solved.

f(x)=x+ (x +4x) 2x =(1+ 5) 2x or f(x)=x- (x +4x) 2x =(1- 5) 2x and f(x) on x>0 is an increment function.

f(x)=(1-√5)/2x

f(1)=(1-√5)/2

Substitution method, there are still a lot of strongmen.

Then there's the details.

Let x=f(x)+1 x.

f[f(x)+1/x]*f=1

by f[f(x)+1 x]*f=1

f[f(x)+1/x]*f(x) =1

f(x)=f

Because the function is monotonically increasing.

So x=f[f(x)+1 x]+1 [f(x)+1 x] because f[f(x)+1 x]=1 f(x).

So x=1 f(x)+1 [f(x)+1 x] simplification gives x 2*f(x) 2-x*f(x)-1=0, which is a quadratic equation about f(x).

The solution yields f(x) = (1 + 5) 2x or.

f(x)=(1-√5)/2x

And because f(x) is an increasing function on x>0.

f(x)=(1-√5)/2x

f(1)=(1-√5)/2

2. False.

3, 4, 4, right.

1, C *2, what is that 718?

True/False Question 1False 3True 4 False.

Multiple choice question A application question will not be, the conditions are not enough.

<> according to the nature of the power function, the image decreases monotonically on (0,+.

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