Elementary School Math Problems Come to the Masters...

1.The ratio is 2 times larger than the former term, and 3 times smaller than the latter term, and the ratio is 6 times the original ratio.

2.40% of the number A is equal to the number 2 3 of the number B, and the ratio between the numbers A and B is (2 3:40%=2 3:2 5=5:3).

The oil yield of a kilogram of rapeseed is 40%, and that of a 400 kilogram of rapeseed is (40%).

Work something out. 1.A batch of coal was transported, 1 3 of the total was transported in the morning, and tons were transported in the afternoon, and a total of 5 7 of the total number was transported throughout the day, how many tons of this batch of coal were transported?

t) 2.The fruit store transports two baskets of fruits, the average weight of the basket is 40kg, it is known that the weight ratio of the two baskets of fruit is 2:3, how many kilograms of fruit weigh in each basket?

Total weight 40 2 = 80 kg.

First basket = 80 2 (2 + 3) = 32 (kg).

Second basket = 80-32 = 48 (kg).

3.A piece of iron wire centimeter, cut it into two sections according to 1:2, and then enclose two circles respectively, what is the area of one of the larger circles in square centimeters? (Joints are not counted).

The circumference of the larger circle is centimeters).

radius = cm).

So. Area = square centimeters).

It is best to have a process and an explanation.

5 7-1 3 = 8 21 8 21 of the total amount is then the total amount = tons) two baskets of fruit weigh 80kg, and the total ratio is 2:3 then a basket weighs 2 5 80 * 2 5 = 32 (kg).

The other basket weighs 3 5 80 * 3 5 = 48 (kg) and the larger circumference = cm).

radius = cm).

Area = square centimeters).

1. Fill in the blanks. 1. Expand 6 times.

2. Solve problems.

1. 5 7 minus 1 3 in the morning in the whole day to get a fraction of the total number of tons transported in the afternoon and a fraction of the tonnage in the afternoon to get the total tonnage of this batch of coal).

2. The first basket of fruits accounts for 2 (2 + 3) of the quantity, that is, 2 5, the first basket of fruits accounts for 3 (2 + 3), that is, 3 5 first seek: the total weight of the two baskets of fruits: 40 * 2 80 (kg) The weight of the first basket of fruits 80 * 2 5 32 (kg) The weight of the second basket of fruits 80 * 3 5 48 (kg) 3, the circumference of the larger circle is cm).

The radius of the larger circle is cm).

The area of the larger circle is square centimeters).

The law is to see the answer:

The original formula = 1-1 2+1 2-1 3+1 3-1 3-1 4+...1 9-1 10+1 10-1 11 (the same term of one minus one plus in the middle can be offset by the simple part).

If you don't understand, you can ask me.

Original = 1-1 2+1 2-1 3+1 3-1 4....1 10-1 Difference 11 = 10 11 (seems to be one less 1 loss Sun 20) Void Sign.

I don't seem to have learned equations in elementary school.

Question 1: The electricity price during peak hours is higher than the average electricity price;

The electricity price during the trough period is cheaper than the average electricity price;

The total price is based on the usage time of each period. Set the peak hour usage time t1, the trough hour usage time t, after the implementation of time-of-use electricity price, relative to the average electricity price, the peak hour needs to spend more, and the trough period can save the t2

That is, the time used during the off-peak period is greater than the time used during the peak period, and the time-of-use electricity price is cost-effective.

Question 2: If the total amount of this project is set as unit 1, then team A completes 1 5 per day, team B completes 1 4 per day, and A and B cooperate one day later to complete (1 5 + 1 4) = 9 20;

The remainder: 1-9 20=11 20

How many days will it take: total amount per day = (11 20) (1 4) = 11 5>2 rounded up, then it will take 3 days to complete.

1. Set up x hours of electricity consumption during peak periods and Y hours of electricity consumption during trough periods.

Time-of-use meter**=

Regardless of time**=

To be cost-effective in time-of-use electricity prices, then: time-of-use meter**-non-time-sharing** 02, set the total engineering quantity to x

A velocity = x 5, B velocity = x 4

Column: [1-(x 5+x 4) 1] (x 4)=days) Answer: It takes days.

(1) Suppose you use electricity all day:

Time-of-use electricity price: 22-8=14 (hour) yuan).

24-14=10 (hour) yuan) yuan).

Do not install time-of-use electricity: yuan).

A: The case of electricity all day long.

2) The efficiency of A: 1 5 = 1 5 The efficiency of B: 1 4 = 1 4

1 5 + 1 4 = 9 20 9 20 1 4 = days).

A: It will take days to complete.

1 5 + 1 4 = 4 20 + 5 20 = 9 20 instead of 11 20. As for the first question, I think it should be.

But I really did it seriously. Seek adoption.

The first question is not known, and the second question: solution: There are known to:

Team A does 1 5 of the total project every day, Team B does 1 4 every day, and 1 5 + 1 4 = 9 20 of the total project is done in one day of cooperation. The remaining works are 1-9 20 = 11 20. The rest of the work is to be done by Team B:

Divide 11 20 by 1 4 to get the day.

Residents go out before 8 a.m. and return home after 10 p.m. Implement time-of-use electricity price calculation.

Forehead. What grade are you?

1.Solution: There are more trebles than alto (30-18) 18 100% more treble than bass (30-12) 12 100%=150%2

Solution: If the maximum side length of the cube is 3cm, the volume of the cube is 3 3 3 = 27 cubic centimeters.

The volume of the original cuboid is 5 4 3 = 60 cubic centimeters.

3.Solution:(

1. （30-18）/18=2/3=

The number of high voices is 150% higher than that of medium and low voices, respectively.2Cube side length = 3cm

Cube volume = 3 * 3 * 3 = 27 cubic centimeters.

Box volume = 3 * 4 * 5 = 60 cubic centimeters.

60-27) 60 = 11 10 = 110% less volume than before

3.(Wang Ping's grades are higher than the school record.)

1.More people in the high voice than in the middle voice (30-18) 18*100%=more than the low voice (30-12) 12*100%=150%2The side length of the cube is 3cm, the volume is 3 3 = 27 (cubic centimeters), and the volume of the cuboid is 5 * 4 * 3 = 60 (cubic centimeters), which is reduced by (60-27) 60 * 100% = 55% 3(

1. The number of people in the high voice is more than the number of people in the middle voice (30-18) 18=% more people in the high voice than in the low voice (30-12) 12 = 150 percent

2. (5*4*3-3 cubes) (5*4*3)=33 60 = 55 percent

3. (100 percent.)

1 30 60-18 60 = 20% more than the middle voice and 30 60-12 60 = 30% more than the low voice

2 The overall volume is 5x3x4=60 The maximum cube volume is 3x3x3=27, so it is less than the original (60-27) 60=55%.

3 High (

1 There are more people in the high voice than in the middle voice.

There are more people in the high voice than in the low voice.

2. The volume should be reduced compared with the original.

3. Wang Ping's grades are higher than the school record.

1.Specific middle voice: 30-18 18 = lower than lower voice: 30-12 12 = 150%.

5x4x3-27=33cm3 33/60=55%

Second, A originally had 15 books, and B had 3 books "A = 5 * B; (A+3)=3*(B+3) to solve the equation

The last question, A + B = 1980, (A-80) = B + 80 + 24, solve the equation, team A has 1082 people, team B has 898 people.

Master, asking so much at once, I also play soy sauce in order to complete the task. Let's go!

km 2 （90+82+86）/2/3＝43

Xiaoting 96-2 94 Xiaoguo.

4.(39+6) 5 9 Xiao Ming.

9*4 36 Xiao Wang.

Solution: If there are x pieces of wood yuan, then there are (202-x) pieces of two yuan yuan, and 5x-2 (202-x) = 163x = 81

Answer: There are 81 pieces of Wu Yuan and 121 pieces of Second Yuan.

Set $5 x sheets, $2 $202-x sheets.

5x=2(202-x)+163 x=81...202-81 = $121,,,2 of $5.

Answer:..

5-2=3 yuan.

$3 for an extra sheet, 163 divided by 3=

There is a mistake in this question.