C determines whether the values in the array are continuous

Simply write a to see if it is satisfied, int qwe = new int[6] ;

for (int i = 0; i < 1; i++)int temp = qwe[i + 1] -qwe[i];

if (temp == 1)

elsebreak;

Iterating through the array doesn't do the trick.

bool f=true;

int index=0;

int start=qwe[index];

for(int i=1;i<;i++)

if(qwe[i]-start!=1)

f=false;

break;

start=qwe[i];

It's good to write a circular judgment, the following numbers are all 1 larger than the previous ones

Iterate through the array and use the dictionary collection dictionary to store the statistics of the number of occurrences of each element.

For example, to count the number of occurrences of each array element in an integer array, you can do this as follows:

1) Create a Console Application project (2) in Visual Studio

Array element values.

public iteminfo(int value)///

The value of the array element.

/public int value

The number of times the array element is repeated.

/public int repeatnum

class program

The collection dic is used to store the statistical results.

dictionarydic =

new dictionary();

Start counting the number of repetitions for each element.

foreach (int v in a)

elseforeach (iteminfo info in appears as many times as", ;

(3) Running results.

var data = new int ;

var lst = from v in datagroup v by v into g

orderby

select new

foreach (var v in lst): times", to count the numbers in the array according to their own grouping, and then sort the output If all are manual, you can use dictionary<>:

var data = new int ;

var dict = new dictionary();

foreach (var v in data) foreach (var v in dict): times",,;

For each element, if it doesn't exist in the dictionary, add it in, and then +1 the item

You can create another hash table, and then loop your array, such as the first element, to determine whether the key(1) exists in the hash table, if there is no 1, then it means that this is a new element, then insert the element in the hash table, value = 1;Loop down again, or determine whether 9 exists, if there is value++, if there is no value=1, so that the number of each element can be counted.

I found a strange problem today, and it was. Two projects in the environment, one supports, the other does not, and it is not possible to be identical. Sometimes new file support is added in unsupported projects, but sometimes it is not supported, and it is found that the comment of contains in the supported project is a paragraph found on the Internet**, although it is not quite the same as this, but it can make the array use contains

Arrays have contains, in. .NET Framework Edition, the Array class implements iCollectionString SS=NewString ; 2.

boolb = (ssasicollection).contains(1);

MSDN is described as follows:

At. .NET Framework Edition, the Array class implementation As a result, generic interfaces do not appear in the declaration syntax of the Array class, nor do they have reference topics for interface members that can only be accessed by casting arrays to generic interface types (explicit interface implementations). One of the key things to note when casting an array to one of these three interfaces is that adding, inserting, or removing members of an element throws.

notsupportedexception。

The second method in the example below is one of the three methods described above.

1) First Method:

int ia = ;

int id = ,1);

Here 1 is the value you are looking for if(id==-1) does not exist else exists (2) The second method:

string strarr = ;

bool exists = ((ilist)strarr).contains(a);if(exists) exists else Note: Required with ilist.

c Array Duplicate Element Removal Algorithm:

By iterating over each element in the original array, add the element to the new generic liststring, if the liststring is already included, it will not be added, and when the original array is traversed, the result of deduplication will be stored in the generic.

Since the requirements do not have any requirement for the sequence of elements of the result, the following algorithm is adopted to improve the efficiency string stringarray =

listliststring =new list();

Sort arrays.

int maxline = ;

region calculates the first one separately.

if (sourcedata[0] != stringarray[1])

#endregion

for (int i =1; i < maxline;i++) is to first sort the arrays so that the same arrays are arranged together. Then iterate over the original array, take out the current element and the previous element at once, skip if the two elements are equal, and save the elements to the generic liststring if they are not equal.

The first time you run it, the previous element is empty, so take the first element out and handle it separately).

public static void aa(double arr,double number, out double min, out double max)

In this way, pass the parameters to get the effect:

For loop and array, if you continue < 5, check whether the previous one is < 5 after > 5, note the position of the array, and then the output is not over?

I'll give you a piece of code :

public static intgetnum0(int position,intnum,int val)

Check the position first to determine whether it meets the range requirements of the array.

int num0 = new int[;

for(int x=0;xnum0[position]=val;

for(int x=position+1;x<;x++)num0[x]=num[x-1];

return num0;

It's a very simple paragraph**, I don't need to explain it

Pour. I watched it again. I found myself misunderstood. Do it all over again.

In this kind of flexible data storage, we generally do not use arrays, but use arraylist, which is something similar to linked lists, which can easily delete, add, and insert elements without you having to do any other work, and the following is an example:

arraylist aaa = new arraylist();

Add an int element.

what a bird!"Add a string element.

321);Insert an int element at position 0.

Delete the first element of aaa, note that you must provide a pointer to the object when deleting, not a real value.

aaa[0]=321;Set the value of the first element.

c can know the length of the array via the length property.

int a =

int b = ;b is equal to 6

You can use an inner and outer loop to iterate through the entire array for each element, picking out the same elements. Here are a few things to note:

1. Consider that the same element will appear multiple times.

2. Because of the use of traversal, avoid comparing yourself with yourself.

3. The array is out of bounds.

public static float selectsame(float soudat)

if ( 1) return null;

else return ;}

First, the set outer loop and inner loop are executed, and finally the output can be judged if it is satisfied.

Loop through the embedded comparison conditions to meet the conditional output.