Excuse me, you said that the comparison of the degree of hydrolysis should be the comparison of aci

Taking NAF as an example, the main hydrolysis that occurs when dissolved in water is F-, that is, HF acid group. 》

That is to say, after sodium fluoride is dissolved in water, sodium ions and fluoride ions can be completely ionized (the nature of salt) to produce sodium ions and fluoride ions, but the hydrofluoric acid (HF) corresponding to fluoride ions is a weak acid, and under the condition of hydrogen ions, it will combine with hydrogen ions to a certain extent to form hydrofluoric acid (HF). Why, you can think like this, you add hydrofluoric acid (HF) to water, because it is a weak acid, so it will not be completely ionized, fluoride ions and hydrogen fluoride molecules (HF) have a certain proportion, the same if you add fluoride ions to water alone it will have a similar effect, then fluoride ions and hydrogen fluoride molecules (HF) will also have a certain proportion, but the ratio is not the same, but there is also a certain correlation, which is "the stronger the acid corresponding to the acid group, the more difficult the reaction 1 is, The less hydrolyzed. ".

No, you can still ask, hope.

I say this to "strong bases and weak salts".

Not contradictory. Maybe you have a misconception in this place that HCL, HI these are strong acids, and you will think that HF is also strong acids.

The actual HF is a weak acid, and its strong alkali salts will be hydrolyzed to a large extent in water.

The stronger the acid, the stronger the ionized hydrogen ions, and in turn, the weaker the ions bind to the hydrogen ions.

The second step of polyacid hydrolysis or hydrolysis of water, which is weaker depends on the specific compound and reaction conditions.

In general, if the first step of hydrolysis of polyacids has taken place, and the resulting product contains hydroxide ions (OH-), then the reaction rate of the second step of hydrolysis is usually slower because the OH- ions are already involved in the nucleus of the OH- in the first step of the reaction, and the water molecules can form hydrogen bonds with the OH- ions, reducing the reaction rate for further hydrolysis.

However, if the first hydrolysis of the polyacid group does not take place, or if the conditions of the local digger reaction are not conducive to the first step of hydrolysis, then the hydrolysis reaction of water is usually weaker. This is because the hydrolysis of water only requires one step of reaction, whereas the second step of hydrolysis of polyacids requires two reactions, so the rate of the second step hydrolysis reaction of polyacids will be comparatively slow.

In summary, the second step of polyacid hydrolysis and water hydrolysis is weaker, and specific analysis of compounds and reaction conditions is required.

Hydrolysis is the main response of neutralization and regression.

The inverse reaction. The more acidic it is, the more the neutralization reaction proceeds and the easier it is for the complete reaction to form salts.

The weaker the acidity, the degree of the neutralization reaction is not very large, and it is not easy to completely react to form salts.

Therefore, the weaker the acidity of the acid formed after hydrolysis, the stronger the degree of hydrolysis, and the weaker the hydrolysis.

It can be understood according to the equation before hydrolysis, after the hydrolysis of weak acid ions, a hydroxide ion will appear in the equation; Therefore, the weaker the acidity of the weak acid, the stronger the hydrolysis ability of the acid ions, and the stronger the alkalinity.

This sentence is for weak acids and strong alkali salts, taking NAF as an example, the main hydrolysis that occurs when dissolved in water is F-, that is, HF acid group.

The so-called hydrolysis is essentially the process of combining the acid group with H+ in the aqueous solution, F-+H+=Hf... Reaction 1

And because Nian Pei h2o=h+ +oh-。。 Reaction 2 Reaction 1 consumes H+, causing Reaction 2 equilibrium to shift to the right.

The combined effect of the two reactions is, 1+2, i.e., F-+H2O=HF+OH-。。 Reaction 3: The most critical step in this process is reaction 1, the weaker the acid corresponding to the acid group, the easier it is to proceed with reaction 1, and the greater the degree of hydrolysis.

The stronger the acid corresponding to the acid group, the more difficult it is to carry out reaction 1 and the less hydrolyzed it is.

To give you two of the most typical and important examples, the hydrolysis of the strong acid and weak alkali salt CuSO4 and the strong alkali weak salt Na2CO3, first of all, no matter what kind of salt hydrolysis, the greater the concentration of salt, the smaller the degree of hydrolysis, and the stronger the acidity or alkaline. Specifically, the greater the concentration of CuSO4 solution, the smaller the degree of hydrolysis of copper ions in it, but the greater the concentration of H+ ions produced after hydrolysis, because more Cu2+ occurs per unit volume than at low solubility. The same is true for Na2CO3 solution, the greater the concentration of the solution, the smaller the degree of hydrolysis of CO32- ions, but the amount of CO32- that occurs in a unit volume is more than that at a low concentration, so the concentration of OH- ions formed by hydrolysis is higher than that at a low concentration, and the more alkaline it is.

In a word, the greater the concentration of the solution, the stronger the acidity and alkalinity, and the less hydrolysis.

There is only one acetate ion** and the hydrogen ions ionized by acetate are equal to the acetate ions, so the concentration of hydrogen ions is greater than that of acetate ions.

Or use the charge to guard the rock, Mu Henglaili, in the acetic acid solution, C(H+)=C(CH3CoO-)+C(OH-), so the concentration of hydrogen ions must be greater than that of acetate ion.

You are wrong about that understanding, forget about it, and don't reinforce what is wrong.

If you have any questions, you can ask them again.