Physics question, why was I electrocuted by the mouse?

Static bar, are you wet feet or no shoes.

It's normal to feel something. You're fine now to prove that the current is definitely not big.

This kind of current is not very large, do you think the voltage at both ends of the mouse will be very large? Isn't it dangerous to hold hands all day?

The resistance of a person is indeed very large, but remember that a person is a conductor! Voltages greater than 36V are dangerous to people.

Generally, it should be 5V, and it will not be electrified, and if it does, it may be static electricity.

The voltage that people can withstand is less than 36V, the indoor voltage is 220V, in addition, the capacitance existing inside the computer will also make the voltage higher than 220V (so the electrical appliances are not required to be disassembled at will), the situation you said may be contact discharge, not to be underestimated, you must pay attention to it.

But have you ever wondered what is the use of a large resistance if the voltage is large enough?

There is no shortage of conditions.

If you assume that the electric field is balanced to the right, then the electric field force will be fierce to the right, and the net force of the electric field and gravity must be in the same straight line as ab.

1) Column formula: g = eqtan30°, find the mg2 of the root number of e = q fraction 3 times) The resultant external force of the particle is the net force of the electric field force and gravity, that is, f = 2g = 2mg, the acceleration a = f m = 2g, and the kinematic formula is used to solve s, that is, v0 = 2as, and s = v0 4g is obtained

3) The final velocity is 0=v0-at, and t=v0 2g is found

This problem is that the conditions are insufficient, and at least there should be a diagram to show the angle between the AB direction and gravity. Otherwise, according to the title, there is a vector triangle as shown in the figure. Since the angle between the direction of the resultant force (electric field force) and the vertical direction is unknown, the relationship between the resultant external force (electric field force) and the magnitude of gravity is not clear.

Acceleration cannot be calculated.

This is a junior high school physics problem, and junior high school physics does not need to consider the change of resistance with temperature.

Question 1: No matter what power supply is connected, the resistance remains unchanged The resistance r (U 2) P=R=484 ohms can be found from 220V 100W But the actual power is 81 watts, then there is i=9 22 from (i 2)*r=p

The output power of the power supply is p, total=iu=9, 22*220=90, the lamp consumption is 81, then the wire consumption is 9

Question 2: The current i=p u and the maximum amount of 6A per square millimeter is required, so the minimum area s=i 6= will definitely burn out if it is used in four square millimeters.

Question 3: From the formula: U 2 R=P, we can know that the maximum value of U is that the open root number of PR is equal to ten.

So adding 9v works (but not working normally), adding 15v will burn out after a while.

1. This question cannot be done in principle, because the resistance value of the "200V, 100W" bulb will drop when the voltage is not enough, 000W 220 6= If 4mm2 wire is used, it will be burned.

It is available, but with 15V it will burn the resistor.

5W (excluding losses such as voltage conversion).

The question is to test whether the concepts of power and voltage are confused.

How can a 12V power supply afford a 220V appliance?

If you're a 220 AC appliance, you can just buy a low-power car power supply, which is a DC-AC inverter power supply.

The three resistors are connected in parallel.

I won't say much about that, you should be able to do the math.

3 in parallel.

Explanation: The 2 dots in red can be seen as a dot that I have marked.

i=i1+i2

r1 ten r2

l4/3+l4/4

48/7(a)

Upstairs wrong: The 2 ohm resistor was shorted, and only the last two were connected in parallel.

The reason is that the unit of voltage is v, and the unit of current is c s, q=v*c s*s

Physics exercises.

Electric hot pot converts electrical energy into internal energy (or heat).

9. The circuit diagram is as follows: 10 question C.

10, a no battery. Short circuit when closed, D has no switch, E is the same as B, F pair.