There are a few math problems that will not be solved urgently! It s going to be handed in tomorrow

1.A cuboid is twice as long as it is wide and 2 times as high as it is widened, and its surface area is enlarged (4 times) 2The sum of the edges of a cuboid is 60 cm, the length is 6 cm, the width is 5 cm, the height is (4) cm, the surface area is (148), and the volume is (120) 3

The surface area of a cube is 24 square centimeters, the edge length is (2) cm, and the volume is (8) ml = ( ) cubic centimeter = ( ) liters How many meters of wooden strips do you need to make a cuboid wooden frame with a length of 45cm, a width of 30cm, and a height of 10cm? 6.A cuboid is 16cm long, 8cm wide, and 4cm high, and how many small cubes with 4cm long edges can be placed inside?

7. How thick can the school spread cubic meters of yellow sand in a rectangular sand pit with a length of 6 meters and a width of 6 meters? 8.If the height of a cuboid increases by 2cm, it becomes a cube, which is an increase of 56 square centimeters in surface area, and the volume of the original cuboid is how many cubic centimeters.

One, 4 times. II, 4, 148, 120

III, 2, 8

Four, five, 45x4 + 30x4 + 10x4 = 340

6. (8 4) x (16 4) = 8

Seven, eight, 56 4 2=7, 7x7x5=245 I really don't want to, I recommend reading more books.

One, 4 times. II, 4, 148, 120

III, 2, 8

Four, five, 45x4 + 30x4 + 10x4 = 340

6. (8 4) x (16 4) = 8

Seven, eight, 56 4 2 = 7, 7x7x5 = 245

Take a look and you'll find out.

Each of the h is multiplied by 5 and the remaining number.

Respectively, these four numbers are the square number of , .

So h = 5 * t squared).

When t = , h = 5 * 5 * = m.

Mathematics, physics and chemistry are interconnected, in physics: h 1 2*g*t 2 when g 10 is taken; h＝5t^2

1）：h＝5t^2

2) When t=, h=5* (m).

(1) According to Newton's second law, h=1 2gt 2 (g is the acceleration of gravity, theoretically for the convenience of calculation, g=10m s 2);

2) When t=, h=1 2*10*.

h=5*t2 (i.e., 5 times t squared).

When t=, h=5*

（1） (1-6％)x

2) (xy) multiplied by (x-y).

..I can't understand the back.

Simplifying the question should be problematic, and the second item cannot be simplified.

1.Multiply the first term under the root number by (2-1) to get (2 512) (1 256)=2 2=4 (The title should be written incorrectly, right?) The parentheses should be connected by multiplier signs).

2。Count from back to front, multiply the last two first, then multiply the previous one, and finally get 1. (The title is written incorrectly, the second item is 2 + root number 3, not 2 times root number 3).

3。For this infinite term, let the value be x, x 2=2-y, y 2=2+x, subtract the two formulas, and simplify to get y=x+1, x=(5

14.x=(3 ,y=(3 ,x+y=10,x*y=1,primitive=(x 3+y 3) (x 2y 2)=x 3+y 3=(x+y) 3-3x 2y-3xy 2=1000-3(x+y)=970

15.2+1 a=w, so the original formula=1 a=2

17.x+y=(5, it can be proved that this number is greater than 2 and less than 3, so x=2, y=(3+5, substituting the value to get the original formula = 5

2.A pencil x yuan, an eraser y yuan 3 pencils and 2 erasers the amount of money b = -3 (a + 6) - (3-b) + 2 = 32m -4m = 2 2m -4m + 2008 = 20105（7y-3z)（8y-5z）=56y^2-35yz-24yz+15z^2=56y^2-59yz+15z^2

1。It is known that the unit price of B drink is X yuan bottle, and the unit price of A drink is 1 yuan less than that of B drink, Xiaofeng bought 2 bottles of A drink and 3 bottles of B drink, and spent a total of (5x-2) yuan.

A unit price: x-1

It took a total of 2 (x-1) + 3x = 5x-2

2。The algebraic formula 3x+2y can be interpreted as ( ).

3 x times and 2 y times the sum.

Or: X yuan per kilogram of apples, y yuan per kilogram of pears, how much is it to buy 2 kilograms of apples and 3 kilograms of pears.

3。If |a-1|+(b+3) = 0, then the value of (a+6)-(3-b)+2 is (3).

Both the absolute value and the square number are greater than or equal to 0.

The sum of two numbers greater than or equal to 0 equals 0, then both numbers are 0

a-1=0b+3=0

Solution: a=1, b=-3

a+6)-(3-b)+2=(1+6)-(3+3)+2=7-6+2=3

4。If m -2m = 1, then the value of 2m -4m + 2008 is (2010).

2m^2-4m+2008

2(m^2-2m)+2008

5。Operation: 7y-3z) (8y-5z) to process.

7y*8y-3z*8y-7y*5z+3z*5z

56y^2-24yz-35yz+15z^2

56y^2-59yz+15z^2

1. 5x-2

2.The sum of three times x and two times y.

5.= 56y squared - 35zy-24zy + 15z squared = 56y squared - 59zy + 15z squared.

The first question is 5x-2

The second question is the sum of 3 x and 2 y.

The third question is B+3, is there a 2 in the upper right corner? If it's 2, then a is 1, b is -3, and when I bring it back, I know that the value is 3

The fourth is 2010, you take 2m square-4m out of 2, it's the same as the previous fifth (7y-3z) (8y-5z).

7y*8y-7y*5z-3z*8y+3z*5z=56y-59yz+15z.

It's too troublesome for me to square this, * is a multiplier sign.

halo, 1, (x-1)*2+x*3=5x-2;

2. I don't know what this questioner is trying to ask?

y-square-59xy+15z-square.

Ignore the fact that x is not equal to y

When x=0, -99<=y<99,100*2-1 values x= 1, 1<=|y|< 99,99*2-1 value. x= 99, y=0, 2*1-1 values so there is a total.

100*2-1+2（99*2-1)+.2(1*2-1)=199+4(1+2+..99)-198=19801 group solution.

Considering the solution of x=y, a total of -49<=x=y<=49, a total of 99 groups once, a total of 19801-99=19702 groups to meet the meaning of the problem, you can also refer to it.

It can be done with linear programming! This image is definitely in the first quadrant, with a total of 98 groups.