There are a few math questions that you can t, please ask for detailed answers.

The solution of these three questions lies in understanding the geometric significance of weight conditions.

1。The ellipse is a little bit over, this point is the vertex of the equilateral triangle with of2 as the base (c 2, root number 3 c 2), and then substitute it for the required value. Or connect AF1 to get a 60-degree right triangle. The answer is (root number 3-1) 2.

2.From the radius of the inscribed circle, the area of the triangle in the problem can be calculated as 8, so that the height with f1f2 as the base is 8 3, and 8 3 is the ordinate sought.

3.The quadrilateral is divided into two triangles on the x-axis, both with f1f2 at the bottom. The other two points are the highest at the end of the minor axis, the two triangles have the largest area, and the quadrilateral is the largest. The vector value is -2

The calculation may be wrong, but the solution is fine)

Today's primary school exam questions are not as simple as we think, many primary school exam questions are unfathomable, and even many exam questions are challenging IQ super IQ, brain teasers, etc., I remember that I never encountered such nerve-wracking exam questions when I was in elementary school, and now these exam questions are not teachers and adults can answer, netizens joked: The difficulty is really big, and those who can answer it are first-class masters.

The first way: What parking space is the car parked? This exam question is actually not difficult, it is a very common logical thinking and reasoning question in primary school, from ** we can know that the parking space of this car is very regular to follow, and the question also requires primary school students to complete the answer within 20 seconds, this primary school exam question seems simple, but many parents can't answer it, they have said that this is really nerve-wracking, many netizens ridiculed:

Coming up with such a question is simply challenging IQ, for a primary school student, how can it be possible to make an answer in 20 seconds, it can be seen that this question has stumped many people. Can you figure it out?

The second way: 6 () + 10 () = 1 ().This question is equivalent to a brainteaser of logical thinking questions and answers, which tests the student's cognition of time, we can know from **: 5 months + 7 months = 1 year, and so on, and so on, and finally ask:

6 () + 10 () = 1 (), I feel very nerve-wracking when I see this question, not to mention that parents can answer it, I don't know where to start to give the correct answer to this question, I really need primary school students to use their brains to test your IQ! Netizens have expressed: Many college students are impressed by such a brainteaser question, can you answer it?

Question 3: 90% of people will miscalculate the question

In fact, I don't know how to solve these three math problems, because I don't have any idea about these three math problems, and I think they are very profound.

No. You didn't tell me what the topic was, and I couldn't answer it in a concrete way.

I'm sure I won't answer them, because these are questions that have been painstakingly studied by mathematicians for generations and have not come to a conclusion, and it is difficult for ordinary people to make them.

Yes, these three math problems seem complicated, but they are actually very simple, and they can be easily solved as long as the ideas are clear.

Meaningless questions, blind questions!

Hello! 1.Solution: The puppy went for hours).

So the puppy walked 3 km)

2.Solution: Because the equation (k+2) x 2+kx-3=0 is known to be a one-dimensional equation about x, k+2=0

k = -2 so the original equation is -2x-3 = 0

2x=3x=3.Solution: A sweeps 1 16 per minute, B sweeps 1 12 per minute, so it takes 1 (1 16 + 1 12) = 48 7 (minutes).

1. As long as you consider the time it takes for A to meet B, time t=, then the distance that the puppy runs is s=3*;

2. The unary equation is k+2=0 , k=-2, so the original equation is 2*x+3=0, x=;

3. A speed x 16, B speed x 12, then A and B match time: x (x 16 + x 12) = 48 7 (minutes).

The second question upstairs is wrong, careless.

It takes hours for A and B to meet, and the speed of the dog is so the distance the dog walks.

From the known k+2=0,k=-2, the equation is -2x-3=0, x=-3 2, A is 1 16 per cent, B is 1 12 per cent, and the two of them together are 7 48 per cent, so it takes 48 7 points to sweep.

1.Find out how much time it takes from A and B to the time of meeting The distance traveled by the puppy is 3*km.

2.Because it is a one-time equation k+2=0 k=-2

Bring k into the original equation -2x-3=0 x=-3 for 2 min.

Question 1: Column return slide 1 2 (1 12 + 1 15) = 3 days.

Question 2: I don't make it clear how many meters are used for the second time than the first time.

The third leakage question: cube side length = (10 + 8) 4 8 = 9 volume = 9 9 9 = 729

Question 4: (1-1 4) (1 4+1 5)=5 3 Question 5: The sides of the cuboid are squares Area 100 4 = 25 The width and height of the cuboid = 5

Surface area = 2 (5 5 + 12 5 + 12 5) Question 6 A: B = (1-3 Jingqing 4) :(1-4 5) A = 72 5 (5+4) = 40

B = 72-40 = 32

Question 7. Columnar.

Question 8. 80 (3 4 + 15 60) = 80 km.

1. x(1 12+1 15)=1 Spring deficiency 2, so x=10 3x 9+1=40, so x=

3, let the cube side length a, 3a = 10 + 8 + a, so the backup code a = 9, 9 3 = 27a 2 = 100, a = 5So s=4a*15+2a2=3506, x+y=72; x/4=y/,y=32

7, x imitation sen, which 2+30=4x

Hello, I am very happy to answer your questions, this question is answered by Mr. Xiaotian for your pants, Mr. Xiaotian has ten years of work and has been working for a pure test, dedicated to serving you, your question I have only repented of seeing, I am sorting out the answer for you, please wait a while, reply to you within 3 minutes, don't worry.

Send it. <>

Questions. Question 7 to 10.

It's too much. So much.

Questions. Hee-hee] [hee-hee].

Wait a minute. All right.

Remember to give Zanha.

Questions. Are you sure?

Of course. <>

How to send another one.

That's going too far.

Questions. Please.

I'm exhausted.

The amount of 1 Zhang San sold to Li Si is 30*90%=27

After half a year, the house price is 30*(1+10%)=33

Therefore, the loss is 33-27=6

Note: I personally think that the house price **should be on the basis of the original house price**, and the original house price is 300,000 It's just that Zhang San sold it to Li Si at a 9% discount, so it should be based on 30**.

In fact, this question reminds me of a question in an IBM interview: a person buys a chicken for 8 yuan, sells it for 9 yuan, buys it for 10 yuan, sells it for 11 yuan, and asks him how much money he makes in the end?

There are four algorithms for this problem:

8 = 1, 11-10 = 1, 1 + 1 = 2, so in the end earn 2 yuan.

2. At first, there are only 8 yuan, and in the end you have 11 yuan, so you earn 3 yuan;

3. The first time to buy and sell, the protagonist loses 8 yuan, gets a chicken, and buys and sells for the second time; The protagonist gains 9 pieces and loses a chicken; The third time he buys and sells, the protagonist loses 10 yuan and gets a chicken; The fourth sale, the protagonist.

Gain 11 pieces and lose a chicken.

So the entire GDP (gross domestic product) generated is 8 9 10 11 38 yuan for 4 chickens.

4. There are 3 transactions in the whole event, let's take a look at which 3 are the specifics?

The first transaction: buy for $8, sell for $9, profit $1;

The second transaction: sell for 9 yuan, buy for 10 yuan, profit -1 yuan;

The third transaction: 10 yuan to buy, 11 yuan to sell profit 1 yuan;

The whole process: 1-1+1=1 yuan.

So the analysis shows that this person is a fool, because the last two transactions are equivalent to doing it in vain.

After testing, the enterprise believes that:

The result is: he could have earned 3 yuan directly, but after 3 transactions, the total profit became 1 yuan.

So the correct answer is: -2 yuan!

2 Let the washing machine have x sets (x-18): x = 2:3 solution x = 54

There are other easy ways to do this, and I'm writing this in the hope that you'll understand.

1. Zhang San's house was worth 300,000 yuan and was sold to Li Si at a nine-percent discount (90%). After half a year, the house price ** 10, Li Si sold it to Zhang San again, so how much money did Zhang San lose by selling and buying? To calculate the process

The selling price of Zhang San's house is.

30 90 27 (10,000 yuan).

30 27 3 (10,000 yuan) was lost

Later, Zhang San's ** price was.

27 (1 10) million yuan).

lost 10,000 yuan).

A total of losses. 30,000 yuan).

2. When a new batch of washing machines is sold in the supermarket, when 18 are sold, the ratio of the remaining washing machines to the number of washing machines in this batch is 2:3, how many washing machines are there in this batch? To calculate the process

What is sold is the total amount.

1 2/3 1/3

This batch of washing machines has.

18 1/3 54 (sets).

Zhang San sold to Li Si: 30 * 90% = 270,000 yuan Loss 1: 30-27 = 30,000 yuan Li Si sold to Zhang San: 27 * (1 + 10%) = 10,000 yuan Loss 2: 10,000 yuan total loss: 3 + 10,000 yuan.

The ratio of the rest to the number of washing machines in this batch is 2:3, which means that the remaining is 2 copies, and the total number is 3 copies, so what is sold is 1 copy, that is, 18 units. 18*3=54 units.

90 27 (10,000 yuan).

Although he sold it to Li Si for 270,000 yuan, the actual house was still worth 300,000 yuan, so the price of **10% increase was 300,000 yuan).

In this way, the house is now worth 33 (10,000 yuan), and Li Si lost 33-27 + 3 = 9 (10,000 yuan) back and forth

2. Suppose the washing machine is 1, and the ratio of the rest to the total number of units is 2:3, then the ratio of the sold to the total number of units is 1:3, so it is very simple.

Just use 18 3 = 54 (sets) on it.

- (30*90%*110%) = should be understood, right? I don't know how to ask me).

2. Sell 18 units, and the remaining washing machines account for 2 3 (that is, 2:3) of the total number of units

Then the sold accounted for 1 3 1 3 3 accounted for 18 units. Then the total number of units is 18 (1 3) = 18 * 3 = 54 units.

1. The loss of selling to Zhang San:

30*(1-90%)=3 (10,000 yuan).

Buyback loss:

30-3) * (1 + 10%) - 30-3 ) = 10,000 yuan) total loss:

3 + million yuan) 2, set up this batch of washing machines there are x sets.

x-18）/x=2/3

x = 54 (sets).

1.Sell the house Zhang Sande: 30 * 90% = 270,000.

Bought back and spent: 27 * (1 + 10%) = 10,000.

One buy and one sell is a loss: 10,000.

2.There are x sets of washing machines in this batch.

x-18)/x=2/3

x = 54 (sets).

1.Zhang San sold the house and got a total of 30 * million yuan, and the loss was 30-27 = 30,000 yuan, and half a year later, he spent 30 * (1 + 10,000 yuan, and overpaid 33-27 = 60,000 yuan.

2.There are x sets of washing machines in this batch. Rule.

x-18)/x=2/3

Solution x=54

1.Sell the house Zhang Sande: 30 * 90% = 270,000.

Bought back and spent: 27 * (1 + 10%) = 10,000.

One buy and one sell is a loss: 10,000.

2.There is a problem with question 2, and the question is incorrect.

1. The current price of the house = 30 * 10,000 yuan; Selling price = 30 * 10,000 zhang three losses = 33-27 = 60,000.

2. The number of washing machines = (x-18) x =2 3 The solution is x=54

60,000 yuan, the money for the second purchase minus the money for the first sale is OK.

2. Suppose the washing machines are divided into quintiles, 18 accounts for three-fifths, and eighteen is divided by its proportion to get the answer 30

300,000*10,000.

27*(1+10%)=10,000.

30-27+ (10,000.)

2.If there are x sets of washing machines in this batch, then: (x-18): x=2:3 gets: x=54 sets.

1.Sell the house Zhang Sande: 30 * 90% = 270,000.

Bought back and spent: 27 * (1 + 10%) = 10,000.

One buy and one sell is a loss: 10,000.

Multiply 90% = 27 (10,000) 27 times (1 + 10%) = 10,000) 10,000).

2 = 1 (portions) = 18 (sets) 18 times 3 = 54 (sets).

You have to believe me, I must be right.