Can anyone tell me how netizens add questions

x²-3x+1=0

x-3+1/x=0

x+1/x=3

x+1/x)^2=9

x^2+1/x^2=9-2=7

x + x one-half = (x + 1 x) (x 2-1 + 1 x 2) = 3 * 6 = 18

x to the fourth power + x to the fourth power = (x 2 + 1 x 2) 2-2 = 49-2 = 47

10a+b)^2-(10b+a)^2

100a^2+20ab+b^2-100b^2-20ab-a^2=99(a^2-b^2)

When a and b are not equal, you may wish to set a > b

then a 2-b 2 < = 9 2-0 2 = 81

99(a^2-b^2)=(3k)^2

i.e. there is 11(a2-b2)=k2

It can be seen that k is a multiple of 11, and 11(a2-b2)<=11*81=891, so k=11 or 22

That is, there is a 2-b 2 = 11 2 11 = 11 or 22 2 11 = 44, and a + b is odd or even with a-b.

So (a+b)(a-b)=11*1 or 22*2, i.e. a=6, b=5, or a=12, b=10 (this result is rounded off because a,b<10).

Therefore, the two-digit number is 65 or 56

The referred respondent is rewarded with 10 XP and 10 Fortune, which can be stacked with the reward. After the administrator recommends, it will not affect the process of the questioner's handling of the question, and the questioner can still adopt it if he or she returns.

Ordinary netizens are not qualified to recommend answers, and only those who meet the specified conditions and apply to become a category administrator have the right to recommend answers.

Here is the official announcement

In addition, after research, it is found that the respondents who continue to participate in such solved questions are generally low-level advertising users, of course, for some misadopted situations, better answers are still needed, so this kind of questions are open to high-level users.

I hope that high-level users can still actively contribute more perfect answers, and users below level 5 will try to answer questions that have not been accepted, and slowly accumulate the level they know, so that their accounts will have more weight, and I believe that they will soon have the permission to improve the accepted questions!

If you have any questions, click [Follow-up].

If the question is accepted or recommended, and the questioner does not ask you again, there is no way to add it, so choose to supplement it as soon as possible when your answer is not perfect, and only before the question is processed, if the questioner does not choose you as a satisfactory answer, you can continue to add.

You are in my answer in the personal center, there are questions you have answered, you click on the question you answered and an interface appears, and the following shows that there is a perfect answer, you can click to improve the answer to supplement!

The addition of relays can realize the daytime running lights on and off the headlights.

Do you now turn on the daytime running light when the circuit key is on? If it proves that you are using ACC electricity now.

Of course, it can also be controlled with 4 relays, and the wiring is relatively troublesome! It is necessary to find out the headlight low beam + pole and the left and right turn signal + pole.

If you want to add steering control or add functions such as turning on the fog lights and flashing, buy a "daytime running light controller" online, the function is much better than the 4 relays I said!

The simplest is this: a 5-pin relay. The left and right daytime running lights + poles are connected to 30, 87A is connected to the original line ACC, 85 is close to the light + pole, 86 is close to the iron, OK!

If you want to reduce the light, you need to know the power of the daytime running light or measure the current of the total circuit to calculate the size of the resistance, and the resistance value needs to be known.

Tell me how you want to change it!