Three cats catch three mice in three days, how many cats can catch 10 mice in 10 days?

3 Ah. 1 cat... It can't be said that if three cats catch three in three days, they catch an average of one one a day.

3 days, three.

For another 3 days, it was still this cat, and there were three of them.

For another 3 days, it was still these three cats, and three more were caught.

In the end, there is one day left, and no matter how the cats can catch one.

3 pcs. If 3 cats catch one mouse a day, those 3 will catch 10 mice in 10 days.

One, 1 cat catches 1 a day, 10 days is not 10!

I think it's 1, 1 cat catches 1 mouse a day.

It's still 3.

Because from the title, you can know that 3 cats can catch one a day, so you can catch 10 in 10 days.

10, because 3 cats can only catch 1 mouse a day (cooperation is required), so 3 to 10 cats catch 10 mice in 10 days.

According to "three cats catch three mice in three days", it can be seen that "one cat catches one in a day".

Therefore: one cat can catch 10 in 10 days.

3, three cats catch one mouse a day, three mice in three days, and ten mice in ten days.

It is known that on average, 1 cat catches 1 mouse a day, so 10 cats catch 10 in 10 days.

10 ah......Don't think about complicated problems in elementary school.

3 pcs.

Analysis: 3 3 3 can get a cat to catch a mouse a day.

Catching 50 mice in 50 days requires a few cats.

50x/3=50

x=3 columns of equations solution application problem Tanzhi Bridge steps:

1. Practical problems (reviewing the problem, figuring out all known and last known conditions and quantitative relationships) are fierce.

2. Set the last known number (generally set directly, sometimes indirectly), and use the algebraic formula of the last known number of sets.

Represents all the last known quantities.

3. Find the equation of the equivalence off.

4. Solve equations.

and find out the other conditions of the last knowledge.

5. Test (test whether it is the solution of the original equation and whether it conforms to the practical significance).

6. Answer.

Three cats catch three mice in three days, and the efficiency of one cat is one-third of a mouse day. The requirement for the question is that the efficiency of x cats is 1 rat day. So dividing 1 by a third equals 3That is, 3 cats catch 10 mice in 10 days.

The approach on the first floor is also correct, and I personally think that my thinking is more straightforward.

Summary. 3 cats catch 3 mice in 3 days, a cat catches a mouse in 3 days then a cat in 12 days is 12 3 = 4 mice, then 12 cats catch 12x4 = 48 mice in 12 days.

3 cats catch 3 mice in 3 days, 12 cats catch how many mice in 12 days?

3 cats catch 3 mice in 3 days, a cat catches a mouse in 3 days, then a cat 12 days Sakura is not 12 3 = 4 mice, then 12 cats catch 12x4 = 48 mice.

Typing to time dear ask the Lord.

Three cats catch three mice in three days, a few in six days, and how many days does it take for twelve cats to catch twelve mice.

Can it be faster. Don't you have to count?

24 in six days.

It takes three days. Method.

12÷3=4 4x6=24

12÷12x3=3

Reason, leave it to the children.

It was calculated.

How to hand in the text theory.

Isn't it written on it.

Summary. Based on the information given, we can draw the following conclusions:- 3 cats survived for 3 days and caught 3 mice.

6 cats survived for a few days and caught 6 mice. Based on the information in the title, we can conclude that every cat can catch one mouse per day.

So, 6 cats can catch 6 mice in a few days. The answer is: 6 cats can catch 6 mice in a few days.

3 cats catch 3 mice in 3 days, 6 cats catch 6 mice in a few days?

Based on the information given, we can conclude that the 3 cats survived for 3 days and caught 3 mice. 6 cats survived for a few days and caught 6 mice.

Based on the information in the title, we can conclude that every cat can catch one mouse per day. So, 6 cats can catch 6 mice in a few days.

The answer is: 6 cats can catch 6 mice in a few days. Ediga cheats.

Fellow, I really didn't understand, I can be more specific.

Based on the information given, we can conclude that the 3 cats survived for 3 days and caught 3 mice. 6 cats survived for a few days and caught 6 mice.

Based on the information in the title, we can conclude that every cat can catch one mouse per day. So, 6 cats can catch 6 mice in a few days.

The answer is: 6 cats can catch 6 mice in a few days. Ediga cheats.

3 cats catch 3 mice in 3 minutes = 3 cats catch 1 mouse in 1 minute 1 cat catches a mouse in 100 minutes catches 100 mice, that is, 1 mouse in 1 minute. How many cats can catch 1 mouse in 1 minute? 1 divided equals 5 so the result is 3 cats.

It's not that complicated, as "I'm not a pig" says, catching 3 mice in 3 days is an average of 1 mouse a day. So, to catch 100 mice in 100 days, it is enough to catch 3 cats.

Attention, I came first, but I went to collect some evidence! , 4, 34 pcs! , 2, because: 3 cats catch 3 mice in 3 days, and regard 3 cats as a collective, that is, 3 cats catch a mouse a day and sing the travel file.

So: as long as 3 cats can catch 100 old wild rats in 100 days.

All you need is 3 cats, 1, if it's my cat. There were no less than 100 of them caught in the town. ,1,It's still 3,0,3,0,0,0,,,

3 cats catch 3 mice in 3 minutes = 3 cats catch 1 mouse in 1 minute 1 cat catches 1 mouse catches 100 mice in 100 minutes, that is, catches 1 mouse in 1 minute. How many cats can catch 1 mouse in 1 minute? 1 divided by 5 So it is not so complicated to bear fruit in 3 cats, as "I am not a pig" rephrases say, catch 3 in 3 days.

2 cats catch 4 mice in 2 days, and 10 cats catch how many mice in 10 days.

According to the key mode analysis, the number of days is 10 2 = 5 times, and the number of empty is 10 2 = 5 times, 2 5 5 = 50 (only), answer: 10 cats catch 50 mice in 10 days.