How many sick dogs are there, how can they be calculated?

Updated on pet 2024-05-22
5 answers
  1. Anonymous users2024-02-11

    Written on the front words:

    Have these 50 people studied diagnosis? How can they tell if a dog is sick?

    And where did the gun come from?

    Furthermore, since it is not contagious, why should it be culled?

    Moreover, Isn't euthanasia okay?

    On the first day, everyone knew: there were sick dogs. Everyone looked at the dog and didn't move their hands, what does this mean? It shows that there is more than one sick dog. Otherwise, someone would see 49 sturdy dogs, and a gunshot would echo over the village...

    The next day, everyone now knows that there is more than one sick dog. Why haven't you done it yet?

    There were more than two sick dogs. Otherwise, when the two saw a sick dog, they would have splattered blood again.

    After appreciating this brutal truth, someone wandered through the night and then finally reached out with a sinful finger and pulled the trigger when dawn came. Explain that someone can be sure that their dog is sick.

    Because for them, they saw 2 sick dogs every day for 2 days.

    On the first day, no one will do anything. The next day, there was still no one to do anything, indicating that the owner of the two sick dogs also saw two sick dogs. That's a total of three sick dogs. And there is one that is definitely their own.

    So three cold muzzles were pointed at their respective kennels...

    Words written at the back:

    Because we only heard the gunshots, we didn't hear the dog's wail, and the owner couldn't look at his dog, so he definitely couldn't aim with his eyes, and we can also infer that none of the three people should have hit...

  2. Anonymous users2024-02-10

    One, since there is a sick dog, the disease is not contagious, there can only be one dog. The owner saw that the other dogs were not sick, so they naturally belonged to his own family. The next day, he picked up his gun and shot at his dog, but he couldn't hit it, and there was a burst of gunfire, but no dog barked.

  3. Anonymous users2024-02-09

    If there is only one sick dog, and the owner of the sick dog sees that the other dogs are not sick, then he knows that his hidden oak dog is sick, so there will be a gunshot on the first night. Because there is no gunshot, it means that the number of sick dogs is greater than L.

    If there are two sick dogs, the owner of the sick dog will see that there is a sick dog, because there is no gunshot on the first day, it means that the number of sick dogs is greater than L, so the owner of the sick dog will also know that his dog is sick, so there will be gunshots on the second day. Since there was no gunshot the next day, it means that the number of sick dogs is greater than 2.

    And so on, if there are gunshots in the first cong for three days, it means that there are three sick dogs.

  4. Anonymous users2024-02-08

    There was a mistake on the first floor, because I didn't know how many sick dogs there were. If there must be a sick dog in the village, and the owner sees that the other dogs are not sick, then he knows that his dog is sick, so there will be a gunshot on the first night. Because there is no gunshot, it means that the number of sick dogs is greater than one, which I agree.

    But there was no gunfire the next day, it could be because they saw that other people's dogs were sick, and the number could be greater than three to be destroyed, so some owners did not know how many there were, so everyone unified to kill the dog together on the third day, anyway, it was not sick, and it was used to eat. Dogs are not allowed in the future, so there is a burst of gunshots.

  5. Anonymous users2024-02-07

    If there is only one sick dog, and the owner of the sick dog sees that the other dogs are not sick, then he knows that his dog is sick, so there will be a gunshot on the first night. Because there is no gunshot, it means that the number of sick dogs is greater than L. If there are two sick dogs, the owner of the sick dog will see that there is a sick dog, because the first day did not hear the gunshot, it means that the number of sick dogs is greater than L, so the owner of the sick dog will also know that his dog is sick, so there will be a gunshot the next day.

    Since there was no gunshot the next day, it means that the number of sick dogs is greater than 2. And so on, if there is a gunshot on the third day, it means that there are three sick dogs.

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