The chiral carbon atom in glucose, the chirality of the first carbon atom of glucose

Chiral carbon must look at the overall part of the connection, such as No. 2 carbon, the C above the No. 2 carbon belongs to the aldehyde group, the left is connected to H, the right is connected to OH, and the C connected below the No. 3 carbon is the part below the No. 3 carbon, and there are 4 different parts, which are chiral carbon.

L-glucose 5 carbon is the most farthest chiral carbon, and the organic chemical name aldehyde group takes precedence, and the aldehyde group carbon is 1, and then numbered from top to bottom.

The largest chiral carbon, that is, the chiral carbon configuration farthest from the carbonyl group, is compared with D-glycerol, the same is D, and the different configurations are L, which can be understood that OH is D series on the right and L series on the left.

The structure given in your book is different from that of organic chemistry in my university! We give the hydroxyl group of C2 C5 Even:

The d configuration is right, left, right, right.

The l configuration is left, right, left, left.

Therefore, the farthest chiral c is still C5, and the groups attached to C5 remain unchanged except for chiral carbon, C3, so they are still chiral carbon atoms.

L-Glucosaccharides are numbered C1 from the aldehyde group, but their position changes left and right, which is well understood, C4, because of C2, the other parts of the carbon chain are regarded as a group to judge whether it is chiral carbon or not.

To determine whether it is chiral carbon, it is easy to understand that except for chiral carbon, all other parts of the carbon chain are regarded as one group.

L-Glucosaccharides are numbered C1 from the aldehyde group, because the groups attached to C2, C3, C4, and C5 remain unchanged, but their positions change left and right, so they are still chiral carbon atoms, so the most distant chiral C is still C5

Summary. The chirality of the first carbon atom of glucose is r (dextralative). The reason for this problem is that the first carbon atom of glucose has two possible configurations, namely R and S (left-handed).

Due to their similar molecular structures, it is difficult to distinguish their chirality. The solution to this problem is to use the Cahn-Ingold-Advance (CIP) system, which is a system used to determine the chirality of atoms in organic molecules. It uses the charge and spatial configuration of the atom to determine the chirality of the atom.

The CIP system is a system used to determine the chirality of atoms in organic molecules, which uses the charge and spatial configuration of atoms to determine the chirality of atoms.

The number of digits is: A: -1

Can you elaborate on that a little bit more?

The chirality of the first carbon atom of glucose is r (dextralative). The reason for this problem is that the first carbon atom of glucose has two possible configurations, namely R and S (left-handed). Due to their similar molecular structures, it is difficult to distinguish their chiral nature.

The solution to this problem is to use the Cahn-Ingold-Advance (CIP) system, which is a system used to determine the chirality of atoms in organic molecules. It uses the charge and spatial configuration of the atom to determine the chirality of the atom. Personal Tips:

When determining the chirality of atoms in organic molecules, the CIP system should be used as it can accurately determine the chirality of atoms. Related knowledge: The CIP system is a system used to determine the chirality of atoms in organic molecules, which uses the charge of the atom and the configuration between the empty pants to determine the chirality of the atom.

The middle four C atoms of the six C atoms are chiral carbon atoms.

Because chiral carbon atoms refer to the four atoms attached to the carbon atoms, leakage or atomic clusters.

The different return mu c atoms are called chiral carbon atoms.

The first c has 2 Hs on it, so it is not a chiral carbon atom, and the last c atom has a c=o double bond, not four atoms or clusters, so it is not a chiral carbon atom. The four atoms or clusters of atoms in the middle four c atoms are not the same, so these four c are chiral carbon atoms.

Because glucose is a hexalon sugar, in this hexalon molecule, there are four chiral carbon atoms.

Standard answer!!

9.1 glucose in cellulose has several chiral carbon atoms (d)a 2 b. 3

c. 4 d. 5

e. 6

When the 4 atoms or clusters connected to the carbon atom in the organic molecule are not the same, the carbon atom is called a chiral carbon atom.

So there are 5 of them.

When the same carbon atom is connected to 4 different atoms, the substance is chiral and there are 2 of them.

Hello, the 4 carbon atoms in the middle of glucose are chiral carbon atoms.

That is, 2345's.

Glucose, C6H12O6, CH2OH (CHOH) 4CHo, Polyhydroxyaldehyde, HoCH2-CH(OH)-CH(OH)-CH(OH)-CH(OH)-CH(OH)-CHO

So, the middle 4 c atoms are chiral carbon atoms.

After addition with H2, that is, the aldehyde group plus H2 becomes a hydroxyl group, Hoch2-CH(OH)-CH(OH)-CH(OH)-CH(OH)-CH2OH

As you can see, there are still 4 chiral carbon atoms in the middle.

A monosaccharides can be divided into triose, butyrose, pentose, hexose, etc., and the structure of glucose is not the simplest, so a is wrong;

b monosaccharide is a sugar that can no longer be hydrolyzed, and glucose cannot undergo hydrolysis reaction, so it is a monosaccharide, so b is correct;

c Glucose contains 5 hydroxyl groups, which are quite a lot, and monosaccharides can be divided into aldose and ketose, which do not necessarily contain aldehyde groups, so C is wrong;

d According to the number of carbon atoms, monosaccharides can be divided into triose, butyrose, pentose, hexose, etc., and glucose contains a lot of carbon atoms, so d is wrong

Glucose, CH2OH (CHOH) 4CHO, has 4 chiral C atoms, which is the 4 in the middle.

After the addition with H2, it has to be hail early, hoch2-choh-choh-choh-choh-ch2oh, or 4 chiral c atoms, 4 in the middle.