A strange puzzle, a difficult little puzzle

The moment the knife was drawn, the thief turned from one side to the other, so it turned out that after the policeman in front of him shot, it became the policeman behind him.

1. "Chasing" means that the police are behind.

Well, of course, the bullet came through from behind.

As for the policeman in front, aren't there two policemen, one in front and one behind, both following the thief, then the one in front shoots, but it is still behind the thief.

It's a very simple question.

2. However, there is a bug in this problem:

The thief was chased by two policemen: 2 policemen.

There are 2 police officers at each exit on each side: 4 police officers.

If it's not a bug, then it means:

a. Or: The aisle is curved, that is. There is the same exit at both ends.

b. Or: If the aisle is straight, it means that there is a mirror in front of it.

Wow ka ka kaka.

Yes, the bullet has to go through the back, because the oncoming bullet must come out from the back.

Presumably, the concept of "bullets passing through behind" was deliberately blurred.

Personal opinion, I don't know if it's right or not.

Two of the policemen were standing at an exit (i.e., in front of the thief). The two policemen chasing him also had a front and back order, and the gun was fired by one of the policemen in front of him.

I don't know if that's right, maybe it's too simplistic, hehe.

It's very simple, what the thief is doing with a knife, just to resist, and to resist, he has to turn around, but at the moment before he turned around, he was hit by one of the two policemen who chased him. (Already turned around when he hit).

This proves the phenomenon that "the strange thing is that the gun was fired by a policeman in front, but the bullet passed through the back". (Shot in the back, but facing the police).

In fact, the "policeman in front" is "one of the policemen chasing him".

Both policemen fired, one with a silencer and the other without. That's why this phenomenon exists!

Because the thief has his back to the police in front and is facing the police in the back.

Because the thief is facing a mirror, and when he sees the police shooting in the mirror, it is actually the police behind him. Reason: The title says "There is a thief who is chased by 2 policemen", but then it says "2 policemen stand at each side of the exit", which is 4 policemen, so there is a mirror at the end of the aisle.

When the police pulled out their guns, the thief turned around and ran back in fright, at which point the gun went off. The thief was shot in the back. When he falls to the ground, he turns around 180°...A mystery through the ages.

Are there any policemen who shoot because a thief has a knife? And if there are four police officers blocking the intersection, how can your teacher go in and see which direction the bullet is coming through? If the conditions are not true, how can it be real, which makes us how to give the answer.

What is left after the third person has taken it: (1 2) (1 2) = 1 root left after the second person has taken it: (1 + 1 2) (1 2) = 3 roots left after the first person has taken it:

3-1 2) (1 2) = 5 roots, so there are a total of: (5-1 2) (1 2) = 9 roots.

The fourth person has all the sugarcanes, that is, 0 stalks left;

The fourth person was preceded by: (0 1 2) 2 1 root.

The third person was preceded by: (1 1 2) 2 3 roots.

The second person was preceded by: (3 1 2) 2 5 roots.

The first person was preceded by: (5 1 2) 2 9 roots.

There are 9 in total.

The first person asked for: 9 2 1 2 4 , and the remainder : 9 4 5 roots.

The second person asked: 5 2 1 2 2 , and the remainder: 5 2 3 roots.

The third person asked for it: 3 2 1 2 2 , and the remainder: 3 2 1 roots.

The fourth person asked for: 1 2 1 2 1 , and the remainder: 1 1 0 roots.

There are 4 2 2 1 9 in total.

Such questions have to be reasoned from the back to the front.

The last person asks the third person to add half and half of the left, and can only take one, so the said half should be 1 minus half the root equals the root, and all should be 1, that is, the first person takes half of the root and half of the root and then leaves one, so he takes 2 roots.

So it turned out to be.

The last person takes 1 stick, and the third person takes 2 sticks.

The second person took 4.

The first person took 8.

A total of 1 + 2 + 4 + 8 = 15 sugarcane.

As a result, you can push it from the front, the first person takes half of the 15 plus half of the root is 8, and there are 7 left, the second person takes half of the 7 plus half of the root is to take away 4 and there are 3 left, the third person takes half of the 3 plus half of the root is 2, there is one left, and the last person takes half of the 1 plus half of the root and takes it away.

The last person asks the third person to add half of the remaining half, and after all the sugarcane is divided, the third person takes it and leaves x roots, then.

x 2+x=1 and we can work backwards to get it.

y-(y/2+1/2)=1 y=3

z-(y/2-1/2)=3 z=5

w-(w/2-1/2)=5 w=9

So there are 9 in total.

Column equations are on the line.

Two-and-half (two-part x + one-half (1-quarter x-1) + one-half gives x=1

This should be called a very annoying little puzzle!!

Count our poor old Chen to death!!

I also write the style half dead!!

The last person asked for half of the remaining half of the third person's sugar cane and half of the cane, so the last person asked for a sugar cane.

Then there is (1+ roots) before the 3rd person takes it.

There is still (root) before the second person takes it.

In total, there are (roots.)

(((1+3+5+9=18 in total.) Kneel and beg for points. You can also ask in the future. Don't divide it, the points you give are too much.

9 roots, the first person asked for 4 roots, and the remaining 5 roots

The second person asked for 2 roots, and the remaining 3

The third person asked for 2 roots, and the remaining 1

The last person asked for 1.

If the first person takes x roots, the total number is 2x + 1 roots.

The second person took (1 2) (x+1)-1 2=(1 2)x the third person took: (1 2)[(1 2)x+1]+1 2=(1 4)x+1

The last person took: (1 2) * (1 4) x + 1 2 = (1 8) x + 1 2

The four of them took a total of x+(1 2)x+(1 4)x+1+(1 8)x+1 2=x+(7 8)x+1+(1 2).

So x+(7 8)x+1+(1 2)=2x+1(1 8)x=1 2

x=4 roots. The total number is: 2x+1=9.

The first person took: x=4 roots.

The second person took: (1 2) x = 2 roots.

The third person took: (1 4) x + 1 = 2 roots.

The last person took: (1 8) x + 1 2 = 1 root.

Solution: Let there be a total of x roots.

From the title: (1 2).

And x 0 solves: x=9

Last person: 1 root.

The third person: (1+1 2)*2=3 roots.

The second person: (3-1 2)*2=5 roots.

The first person: (5-1 2) * 2 = 9 roots.

(((1+3+5+9=18 in total.)

Simple, "the eldest daughter can play the piano", it means that there is a daughter who is the oldest to find out the approximate number of 36 and look at "add up to your house number", the student knows that the main thing is that "the eldest daughter can play the piano" This sentence.

Because multiplying the three numbers to get thirty-six is 1 1 36 , 2 2 9 , 3 3 4 The age difference between the first one is too great, so it is not right, and the third one violates the condition that the eldest daughter can play the piano. So that's the 9 2 2 too!

The eldest daughter is 9 years old, and the 2 younger daughters are twins, each 2 years old. The age of the three daughters is multiplied exactly: 9*2*2=36 The sum of the ages of the three daughters is equal to:

9 + 2 + 2 = 13 (the student's house number) The eldest daughter can play the piano, indicating that the age should not be too big, after all, the teacher said: Yes. Played the piano too.

However, if you know the student's home number in the question, it is easier to calculate, I wonder if you missed it? Otherwise, there might be other answers to this question!

What don't you understand, the eldest daughter is nine years old, and the next two daughters are twins two years old each.

The escalator of a large shopping mall is transporting customers upwards at a constant speed, and now A and B are running up the escalator successively, and the speed of A and B running on the escalator is meters per second and meters per second respectively, and the number of stairs for A and B is 42 and 45 respectively, so what is the speed of the escalator's uniform movement? If there is an average of one customer standing on each step, how many customers are standing on the secondary escalator?

Method 1: Let the speed of the escalator be x, the time used by A is y, and the time used by B is z, then there are: (x+

Therefore, if you know that x=1m s; y=28s；z=25sx+

n=70 Method 2:

The speed of A and B should be order seconds, order seconds.

45-42] [28-25] = 1 level of seconds.

The speed of the escalator is 1 step second.

45 + 25 * 1 = 70 levels.

There are 70 levels in total, and there are 70 people standing full.

Method 3: Let the escalator be long l, and the number of steps is n, then the time of A on the escalator is t1=l (v1 +v), and the distance traveled by A relative to the escalator is s1 =v1 t1, and the proportional relationship has n 42 = l s1 and the above three formulas are obtained: n 42 = ( .

In the same way, for l there is n 45=( Comparing the above two equations, we get v=1 m s n=70

Method 4: The speed of the escalator is x meters and seconds, A uses a speed of 42 to reach the top of the escalator, and B uses 45 to reach the top, and the distance of the two runs is equal, so (, the solution is x = 1 meter second, and the escalator can stand 70 people. The final answer should be level 1 s, which can stand 70 people.

Are you satisfied with the hailstorms?

This time, the guest will provide a total of 9*3=27 yuan in cash.

Among them, the actual accommodation fee is 25 yuan, and the waiter is greedy for 2 yuan in the payment of the guest, so the actual total amount is 27 yuan.

The 27 + 2 yuan proposed in the title is actually a double calculation of 2 yuan, and the 27 yuan contains the 2 yuan that the waiter is greedy, and the calculation will produce an error again! Namely.

10 yuan per person, and then 1 yuan per person, that is, 9 yuan 9 yuan per person x 3 = 27 yuan.

The boss said that 25 yuan was enough, so he added 2 yuan.

It just so happened that the 2 yuan was "secretly hidden" by the waiter

So 25 + 2 = 27 + 3 = 30, no more, no less.

3 people each 9 yuan, 3 x 9 = 27 yuan, this 27 yuan includes 2 yuan from the waiter and 25 yuan for accommodation, 27 plus the return of three yuan, which is exactly 30 yuan.

I think it's the boss's!

Damn, the three of them only paid a total of 27 yuan, of which 2 yuan was in the waiter's place, and 25 yuan was in the boss's place! The two dollars taken by the waiter are within 27 yuan, so the addition is not valid.

There is no solution to this question. The sum of the two subtracted numbers is 12

The two anti-aging pants contain and are 2

The sum of the two subtractions minus the subtractions is 12 Husi2 10

And in fact 9 14 23 is not equal to 10, so there is no solution.