Both sisters are away from home at the same time, the older sister walks 90 meters per minute, and t

The two sisters are away from home at the same time, the older sister walks 90 meters per minute, and the younger sister walks 60 meters per minute. When my sister arrived at the school gate, she found that she had forgotten to bring her textbooks, so she immediately went home to pick them up. Walk to meet my sister 180 meters from the school, how far is their home from the school?

Sister has more lines than sister in one minute: 90-60 = 30 meters.

When we meet, the sister has more lines than the sister: 180*2=360 meters.

Then the time of the encounter is: 360 30 = 12 points.

So the distance is: 12*60+180=900 meters.

90-60 = 30 (m).

180 divided by 90 = 2 (minutes).

60*2=120 (minutes).

180 + 120 = 300 (meters).

300 divided by 30 = 10 (minutes).

90*10=900 (m).

A: Their home is 900 meters from the school.

If you want to know why, look for me).

When we met, my sister did more than my sister.

180 2 360 m.

When we meet at the time.

360 (90 60) 12 points.

When they met, my sister and sister walked together for 2 whole journeys, and it was okay.

90 60) 12 1800 m.

Their home is close to the school.

1800 2 900 m.

The elder brother walked 180 2 = 360 meters more than the younger sister, and the younger sister walked 360 (90-60) = 12 minutes, so the total distance was 180 + 60 12 = 900 meters.

One, use the algebraic method to go.

Let their home be at a distance of l from the school, and when they meet, they will spend the same amount of time:

l+180) 90=(l-180) 60 solution gives l=900 (m).

Second, use arithmetic methods to solve.

When the older brother meets the younger sister, the older brother walks 2*180 360 meters more than the younger sister, and the older brother walks 90-60 30 meters more than the younger sister per minute.

So the time taken is 360 30 = 12 minutes.

Such that the distance from home to school is.

12*90-180 1080-180 900 meters.

Set up the school to get home is L, then the road taken by the elder brother is L+180, and the path taken by the younger sister is L-180, note that the time they use is the same, so use the distance speed = time, you get (L+180) 90=(L-180) 60, so L=900 meters.

720 meters.

The elder brother walked for 2 minutes and then returned the same way, and the return time should also be 2 minutes, so it took a total of 4 minutes, during this time, the younger sister walked 60 * 4 = 240 meters. If the total distance is x, after four minutes, the elder brother needs to walk x 90 minutes to school, and the younger sister needs to walk (x-240) to school for 60 minutes, then (x-240) 60=x 90, and the solution is x=720

1. Ask your brother to walk more miles per minute than your sister: 90-60 = 30 (m) 2, ask your brother to walk more than her sister in total: 180x2 = 360 (m) 3, ask for 360 meters There are a few 30 meters in it My brother walked for a few minutes, using:

360 30 = 12 (minutes).

4. My sister also walked for 12 minutes, and my sister walked: 12x60 = 720 (m) 5, at this time, my sister was still 180 meters away from the school, and the distance between my sister and the school was added: 720 + 180 = 900 (m).

A: Their home is 900 meters from the school.

If the sister's arrival time is x, then:

60*x=90*（x-4）

x=12 The distance from home to school is: 60*12=720m

Solution: Let the distance from my brother to the school gate be x

x/90*60+（180/90）*2=x-180x=900

Let me explain, my brother and sister are walking in the same phase, so the time for my brother to arrive at the school gate is x 90, because my sister and my brother are walking together, all my sisters walked x 90 * 60 when my brother arrived at school, and then my brother returned along the way, and after walking 180m, he walked 180 * 90 = 2 points, and his sister also walked 2 points, so my sister walked a total of x 90 * 60 + 2 * 60, plus 180, it is the distance.

If the meeting time is t minutes, then the distance traveled by the younger sister is 60t and the distance traveled by the elder brother is 90t

The distance from home to school is equal, and an equation is set up according to the equal distance: 60t+180=90t-180

Time t = 12 minutes, then the distance between home and school is s=60 12+180=900 meters.

Encounter time = 180 2 (90-30) = 12 minutes.

Distance = 12 (90 + 60) 2 = 900 meters.

=300 10, =30 (minutes).

60 30 = 1800 (meters).

Answer: It took 30 minutes for Xiao Ming to go to school, and his house is 1800 meters to school, so the answer is: 30, 1800

Catch-up distance: 45 5 = 225 (m);

The distance from home to school: 50 45 = 2250 (meters) Answer: It is 2250 meters from home to school

This problem is solved according to the time taken by the sisters.

The distance between home and school is x meters.

The distance traveled by the sister: (x+180) m The time taken by the sister: (x+180) 90The distance traveled by the sister: (x-180) m The time taken by the sister: (x-180) 60 And because the two of them took the same time.

So the equation (x+180) 90=(x-180) 60 is solved x=900 meters.

A: ...

Solution: From home to school, a total of x meters.

x－18060 ＝x＋18090

90(x－180)＝60(x＋180)

3(x－180)＝2(x＋180)

3x－540＝2x＋360

x 900A: Their home is 900 meters away from the school.