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select ip_location,count(*)cishu from rlog_getbinddevice_dp
where thistime > to_date('2015-01-20 00:00:00', 'yyyy-mm-dd hh24:mi:ss')
and thistime < to_date('2015-01-21 00:00:00', 'yyyy-mm-dd hh24:mi:ss')
and system_id = 8006
and part_field = '20150120'
group by ip_location
It can be written like this.
But depending on your IP location, you should use like, so you should take a screenshot of your IP location.
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You can use the count function to calculate the number of repetitions of a field.
For example, the data in the test table is as follows:
To query the number of times each name is repeated in the name column, you can use the following statement:
select name,count(*)from test group by name;
Query Result:
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Take a look below, of course I'm writing it in SQL Server. But it is common in Oracle.
select ,case when is null then 0 else end as h,case when is null then 0 else end as t,case when is null then 0 else end as g from (
select distinct id,select [count] from table where id= and ra=100) as h,select [count] from table where id= and ra=200) as t,select [count] from table where id= and ra=300) as g
from Table a) b
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Where condition, and sum it with sum.
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For your requirements, it should be.
select count(id) from table where id ='1'
However, if you need to query the number of times all data in the table id field occurs, you need to perform a grouping query
select id,count(id) as occurrence number from table group by id
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Group by field a, use group by
Use a ranking function, such as rank(), when counting
Get the value of the rank() function <=3.
Try it out for yourself.
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SQL statements in Oracle cannot query the fields with the largest number of the same values in a field. When it comes to business logic screening.
1. Query the value of a field, and save it if it is the same.
2. Continue to query, if there is the same value, continue to save.
3. Compare the numbers in the set, if the same is the most, take out the id and query.
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Train of Thought Steps:
Count the number of occurrences of each value in the field.
Use the rownum or rank function to obtain the 3 values with the most occurrences;
sql:select col,t_count
from (select col, count(1) as t_count
from table1
group by col
order by t_count desc)where rownum <= 3
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In fact, the question examines bai as a group. It can be summed by sum, zhicount can be used to calculate the number of dao values, and group can be grouped by group by.
sql:select username ,count(accountno) as count,sum(amount) as amount
from tablename group by username;
The above can be sought.
Under the username, the number of accountno and the corresponding total amount.
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You can use excel** to count this, which is very convenient.
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select name, count(*)from table name where date between date1 and date2 group by name.
Date 1 and date 2 are the time points you set, you change the field name and table name--- supplement --- give a table structure and date field format, whether it is date or char, you don't describe these clearly.
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You mean what happens within 10 days of each person's first appearance?
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