How does a 6V25W motor speed up with a 12V or 6V battery

1. Increase the current of the rotor winding, 2. Reduce the voltage of the stator winding.

Yes, but increasing the excitation voltage seems to be low-key, because the excitation winding of the parallel excitation motor is absolutely not allowed to open the circuit, otherwise there is a danger of flying, if it is a series excitation motor, the voltage at both ends of the motor can be increased. Or the resistors are connected in parallel at both ends of the excitation winding. (The latter is recommended).

In the case of parallel excitation motors, the excitation voltage can be reduced or the voltage at both ends of the armature can be increased. (The former is recommended) is in danger of burning out the motor by increasing the voltage).

Without changing the structure of the motor, increase the voltage appropriately.

But overloaded operation, who can guarantee that the motor will not burn out?

The speed of the DC motor increases: if the motor structure is not changed:

1. Increase the voltage.

2. Reduce the load.

3. If it is separately excited, increase the excitation voltage, if the motor structure is changed:

Reduce the number of turns of the excitation winding, reduce the number of turns in the electrical region, upstairs said that it is wrong to add the number of turns. When the voltage is constant, the fewer the turns, the greater the current, and the greater the output power. However, when the silicon steel sheet is fixed, the number of turns is reduced to a certain extent, and the magnetic density is saturated, so the current cannot be converted into magnetic energy, and the power can not be increased).

The motor is not designed to be accelerated. Pressurization will burn out the motor, if you really want to speed up the speed can add some coils appropriately, this is easier to achieve. Disassemble the motor case and wrap the coil a few more times.

Hello! However, increasing the excitation voltage seems to be low-key, because the excitation winding of the parallel excitation motor is absolutely not allowed to open the circuit, otherwise there is a danger of flying.1 Increase the current of the rotor winding. Or connect the resistors in parallel at both ends of the excitation winding, 2 to reduce the voltage of the stator winding.

Yes, if it is a series motor, you can increase the voltage at both ends of the motor.

If it helps you, hope.

There is nothing wrong with a 3kg object, but the key depends on how long your arm is. The speed has changed from two revolutions a month to 500 revolutions a minute.

Hello, GX-DGN-EFFICIENT-MULTIFUNCTIONAL. The indicator light is not on, and there is no output for what is the reason. Thank you.

A 6V DC motor can use a 12V battery, and a voltage divider resistor needs to be connected in series on the 12V power supply, and the change is that the voltage divider resistor wastes 50% of the power.

First, calculate the current i of the 6V motor according to the power, and the voltage on the voltage divider resistor is 12-6=6V, and the size of the resistance is 6 i

Suppose the operating current is 6 V and the voltage of the voltage divider is 6 ohms.

A 6V DC motor cannot use a 12V battery, as too high a voltage will burn the motor.

A direct current machine is a rotating machine that converts direct current energy into mechanical energy (DC motor) or mechanical energy into direct current energy (DC generator).

It is a motor that can convert direct current energy and mechanical energy to each other. When it is used as a motor, it is a DC motor, which converts electrical energy into mechanical energy; When the generator is running, it is a direct current generator, which converts mechanical energy into electrical energy.

Burn up you can add a resistor to buck.

If the voltage is too much, it will burn out! A few more strings of 1N4001 bucks!

It is better to use a six-volt battery, the series resistance will heat up.

Definitely not! That would most likely burn the motor!!

It can not be explained: the motor belongs to the inductive load, he is different from the resistive load, the resistive load is only related to the resistance, if the resistance value of the two resistors is the same, ignoring the internal resistance of the power supply, the current of the entire power supply circuit is fixed, i=u 2r, then according to p=i*i*r, it can be seen that the two resistors share the same power, the same current, and the voltage is half of the total voltage, so that the insurance can be determined, and the inductive load is very complicated, and the load of each motor is different resulting in different speeds. The back EMF generated is also different, it directly leads to the voltage and power shared by the two motors are also different, if each electric load is heavy, resulting in the speed can not go up, so that the current of the motor will be very large, may exceed the rated compliance, if the load of each motor is very light, it will lead to the speed is too high beyond the design range, the motor is best not to be connected in series, and the insurance depends on the maximum current required by the motor.

No need to connect in series, just connect in parallel, but it may burn out the motor, I am two 6V motors in parallel, two 12V super power batteries in parallel, it has been used for a year, and the two motors are still normal.

6 volts DC boost to 12 volts DC with 25 watts load is ok, but not the best. The simplest is to use two 6-volt batteries, connected in series (preferably close to the old and new), and connect the positive and negative electrodes with wires to replace them.

If you use a 12V motor with a 6V power supply, the motor power will be reduced, the speed and torque will decrease, and it is best to change the motor parameters of 12V to 6V.

For a 6V power supply, adding a DC DC boost will do, but the efficiency will be relatively low.

DC step-up and step-down is a very troublesome thing, and it is recommended that you directly choose a 12V power supply, which will solve the problem.

Each motor has its own rated voltage and electrical power. Whether you use alternating current (household circuits) or direct current (battery power), there is a clearly defined voltage rating. The rated voltage is the voltage that enables the motor to work properly.

The maximum value of the rated voltage cannot exceed about a multiple, so your battery voltage is too high, the 6V motor will burn out, and the battery is fine.

If the voltage is too high, it will burn out or the battery will be scrapped.

Toy motors generally have 3V, and the 3V motor for batteries quickly gets hot because of overvoltage. The speed is slow with a 12V motor.

Buy a 6V motor, or connect a resistor to the original motor.

Fever should be due to the high voltage and high current, so it will be hot.

6V small motor, the car has 3V, hot is overvoltage.