A math problem, hurry, who will give me a detailed answer in 10 minutes, don t use equations

Analytical combined with elimination:

Let the total number of stones be 1

1) two cars together, each transport 6 times can be transported, 2) when the 6 times of the trolley can be transported by the cart, or the 6 times of the cart can be transported by the trolley, the number of times transported at the same time is that the cart is less than the trolley 5 times, 4) when the cart is transported for the trolley, the number of times the cart needs to be transported should be less than 6 times: 1, 2, 3, 4, 5 times, the car for the cart transport according to the theme corresponding, 5, 7, 8, 9, 10, at the same time the number of the trolley transport should be greater than 6, so there are 5) when the cart for the trolley transport, The number of times the cart needs to be transported should be less than 6 times: 2, 3, 4, 5 times, the car for the cart to transport the cart according to the theme corresponds to 7, 8, 9, 10, then there are 6) the cart alone 8 cars, corresponding to the trolley alone 13 cars, 8) the cart alone 9 cars, corresponding to the trolley alone 14 cars.

9) 10 cars for large cars and 15 cars for small cars.

10) 11 cars for large cars and 16 cars for small cars.

According to the topic, the sum of the separate traffic volume of the large car and the small car should be equal to the combined volume of 1 6, then there are: 7) 1 8+1 13≠1 6 is not in line with the topic.

8) 1 9+1 14≠1 6 is off-topic.

9) 1 10 + 1 15 = 1 6 is in line with the topic.

10) 1 11+1 17≠1 6 is off-topic.

Therefore, it takes 10 times for the cart to be transported separately.

You can't do without equations.

The total number of stones is 1, and the large cart is transported x times, and the small car is x + 5 times.

Then the cart can carry 1 x of stones at a time, and the cart can carry 1 (x+5).

By the inscription 6*[1 x+1 (x+5)]=1

Get x=10

That is, the cart needs 10 times.

This question is in the sixth grade of primary school.,It's really a bit over-the-top.。。。 A minimum of the second year of junior high school is required.

The solution has been written upstairs. As a senior in high school. Denote.. Elementary school to do this. No.

Featuring x sets of costumes; Scheduled to be completed on y days, 20y=x-100

1）23y=x+20

2) Obtained from (1).

x=20y+100 substitution (2).

23y=20y+100+20

3y=120

y=40x=20*40+100=500

So the task of this batch of costumes is 500 sets; It was originally scheduled to be completed in 40 days.

Let the speed of B be x kilometers per hour, and the speed of A be 2x kilometers per hour 2x*3+x*4=100

10x=100

x = 10 A speed = 10 * 2 = 20 km/h.

B speed = 10 km/h.

Let the velocity of A be x, then the velocity of B is x 2, then, (4-1)*x+4*(1 2)x=100, we can get x=20, so the velocity of A is 20km h, and the velocity of B is 10km h.

Let the velocity of B be x kilometers, then the velocity of A is 2x kilometers, and the equation is 3*2x+4*x=100

Get x = 10 km.

So, A's speed is 20 km/h, and B's velocity is 10km/h.

Solution: After x hours, the height of the bell fungus can catch up with the height of the bamboo. Then:

25x+ = 4x + 34

Solution: x = (hours).

A: After hours, the height of the bell fungus can catch up with the bamboo. That is, at half past 9 o'clock, the height of the fungus can catch up with the height of the bamboo.

(1) Eat twice as many apples as pears every day. Then the remaining apples are the 1 3

7 1 3 = 21 (pcs).

2) The number of people who passed for the first time in the total number of people: 1 (1+1 4)=4 5 The number of people who passed for the second time in the total number of people: 1 (1+1 6)=6 7 The number of people who passed increased: 22.

So in total: 22 (6 7-4 5) = 385 people to solve the equation: let the total number of people be x

x*6/7-x*4/5=22

x=3853) If two of the classes are assigned 4 units per class, and the remaining classes are assigned 2 units per shift, then there are 4 more units, then each class is assigned 2 units, which is more.

4 2 2 8 units.

If there is a class with 6 units, and the rest of the classes are divided into 4 units, and there are less than 12 units, then each class is assigned 4 units, which is less.

12 2 10 units.

There are 9 classes of (8, 10), (4, 2).

This school bought an English typewriter in common.

4 2 (9 2) 2 4 26 units.

4) Suppose 18 are all dragonflies (there are as many dragonflies as there are cicada feet) 118-18 6=10.

Spiders: 10 (8-2) = 5 pcs.

Cicadas and dragonflies: 18-5=13.

Let's say all 13 are dragonflies.

13 2-20 = 6 pairs.

Cicadas: 6 (2-1) = 6 cicadas.

Dragonfly: 13-6=7.

A: 5 spiders, 6 cicadas, 7 dragonflies.

5) 35 is "the average of the two numbers, plus the remaining third number", and we speculate that 70 is the sum of the two numbers plus 2 times the third number.

Or rather, the sum of three numbers plus a third number.

In the same way: 27*2 and 25*2 mean the same thing.

70+54+50 means 4 times the sum of these three numbers.

We can find the sum of these three numbers. (70+54+50) 4=70 is the sum of three numbers plus the third number, so the other two numbers can also be found as:

(1) Set x apples.

x-2*x/3=7

x=212) if there are no x passes, then 3x+4 passes.

3x+4+5=6*(x-5)

x=13, so there are 13+3*13+4=56 people in total.

3) There are x classes.

2 * 4 + (x-2) * 2 + 4 = 6 + (x-1) * 4-12x = 9 typewriters have 2 * 4 + (9-2) * 2 + 4 = 26 (4) set spider x, dragonfly y, cicada z

x+y+z=18

8*x+6*y+6*z=118

2*y+1*z=20

x=5 y=7 z=6

5) Let the three numbers be x, y, z

x+y)/2+z=35

x+z)/2+y=27

y+z)/2+x=25

x= y= z=

1.Pears x, apples 3x, n days: n=x, 2n=3x-7 : x=7, apples 21.

2.1st, fail x, pass 3x+4, 2nd: pass 3x+9, fail x-5=6: x=13, total: 56

3.x classes, n sets: 8+{x-2}*2=n-4 ,6+*4=n+12 : n=26

4.Spider x Dragonfly y Cicada Z: 8x+6y+6z=118,2y+z=20,x+y+z=18: x=5,y=7,z=6

5.The three numbers are xyz:y+z+2x=2*25=50, x+y+2z=2*35=70, x+z+2y=2*27=54: x= , y= , z=

1 Let the apples be x and the pears y y, then the pears will be eaten on day y, then: x=3y;

x-2y=7。The solution is x=21, y=7.

2 Suppose the number of people who fail the first pass is x and y respectively: x=3y+4;

x+5=6(y-5), x=43, y=133 then I won't call you, the main thing is to know how to break down each sentence into an equation or an inequality.

3: Set up typewriters x sets, Y shifts.

x-4=4*2+2*（y-2）

x+12=6*1+4*(y-1) The solution is x=26 y=94: set x spiders, y dragonflies, and z cicadas.

x+y+z=18

8x+6y+6z=118

2y+z=20 The solution yields x=5 y=7 z=65: let the three numbers be: xyz

1/2（x+y）+z=35

1/2（x+z）+y=27

1 2(y+z)+x=25 The solution gives x= y= z=

Solution: Let the purchase price of this kind of *** be x

By the title (1 + note: * is a multiplier sign).

Solution x=1200

Set the purchase price of x yuan, which is derived from the title:

x*（1+35%）*90%-50-x=208

Solution x=1200

1. Set the time to go to work in x minutes.

Then there is 12:10 + 2x+:10 (for 10 minutes) + 8 (for 8 hours at work) = 9:00

x=20min

So the time to leave the house is: 2:30, that is, the clock stopped for 2 hours and 20 minutes.

It's very confusing, in fact, the clock starts walking from 12:10 to 9:00 in the evening, during which Uncle Li goes to work and walks, and he arrives 10 minutes early, just subtract these)

2. There are x people who set 2 questions correctly.

7+5*6+2x+3x+4(52-7-6-2x)=181x=452-6-7-2x=31

3. No. 4. Set the cost of each type of candy to be X yuan.

Total number of kilograms: x

Total price: 3 x unit price = total price Total number of kilograms = 11 (yuan kilograms) The formula is not good to list, so it is written in words.