English physics questions are answered, and the English version of physics questions is explained in

This is college physics, right, simply translated:

a): Gives you the differential equation of the spring oscillator and proves that x=xmaxcos 0t is a solution to equation 1 (differential equation).

Find the relationship between the angular frequency and the oscillator mass m and the spring stiffness coefficient k, and solve the equation for this relation: = m k under the root number

b): This is an external driving force to discuss the following questions:

1. If the external driving force is fapp=f1cos 1t, prove that x=xmaxcos 1t is the solution of equation 2 of the problem. Let's solve the equation, the mathematical problem, in fact, we say that the vibration frequency of mechanical vibration under the action of external periodic driving force is the external driving frequency and not its own natural frequency.

2. Prove that the maximum displacement is determined by the driving frequency, and the relation satisfies the latter equation in 2. The method is to solve Equation 2 to get it.

3. Describe the motion of the oscillator when the driving frequency 1 is much smaller than the natural frequency 0 (the amplitude is very small).

4. Describe the motion of the oscillator when the driving frequency 1 is much greater than the natural frequency 0 (the amplitude is very small).

5. What happens when 1= 0? (Resonance, maximum amplitude).

Summary. Hello, glad to answer for you. <>

The English version of the physics problem is explained in detail as follows: according to the description of the problem, the formula of moment of inertia and the definition of angular momentum can be used to solve this problem. Let the distance from the center of mass of the system to the fixed point o be d, then there is:

The angular momentum of rotation around the center of mass of the system is lem=iem w=5 2mA·c 3a=5 6mc and the direction is perpendicular to the paper side. where w=c 3a, is the angular velocity of the rotation around the center of mass of the system, and lem is the moment of inertia of the system with respect to the center of mass. Since the two disks are symmetrical to each other, the moment of inertia of the two disks for the whole system is equal, i.e., i=i1+i2=1 2mA +4mA =9 2mA.

The magnitude of the angular momentum of the rotation of the point o is l =iw=9 2mA ·c 3a=3 2mc and the direction is perpendicular to the outward face of the paper. <>

Detailed explanations of physics problems in the English version.

Hello, glad to answer for you. <>

The English version of the physics problem is explained in detail as follows: according to the description of the problem, you can use the formula of rotational grinding inertia and the definition of angular momentum to solve this problem in Hail Mountain. Let the distance from the center of mass of the system to the fixed point o be d, then there is:

The angular momentum of rotation around the center of mass of the system is lem=iem w=5 2mA·c 3a=5 6mc and the direction is perpendicular to the paper side. where w=c 3a, is the angular velocity of the rotation around the center of mass of the system, and lem is the moment of inertia of the system with respect to the center of mass. Since the two disks are symmetrical to each other, the moment of inertia of the two disks for the whole system is equal, i.e., i=i1+i2=1 2mA +4mA =9 2mA in the source swim.

The magnitude of the angular momentum of the rotation of the point o is l =iw=9 2mA ·c 3a=3 2mc and the direction is perpendicular to the outward face of the paper. <>

Based on the above calculations, it can be seen that: a) Correct. b) Errors. c) Correct. d) Errors. <>

Can you please use it in English?

Yes pro. <>

Need an explanation later.

a) false. c) true. d) false.<>That's right. Dear, take a look. <>

Summary. Physics English questions.

Hello. Can you elaborate on the problem?

This will help me to better answer your questions<>

This one seems to be a chemistry question.

It seems like you would.

Hello, this requires your patience. I'm a chemistry major, but this English needs me to translate <>

Good. Thank you for your understanding.

Hello, how long do you need it, thank you.

Question 1: Take temperature and solubility as the horizontal and vertical coordinates.

Mark those dots.

Connect with smooth curves.

Find the temperature corresponding to 50 solubility according to the curve.

At 40 degrees, 100 grams of water is soluble, 40 grams of water is soluble, 50 grams of water is soluble, and 20 grams of water is soluble.

Question 2: Melting, sublimation, condensation.

Question 3: The difference between the motion of solid and liquid particles: the solid particles are closely arranged, the interaction force is large, and the amplitude of motion is small. Liquid particles have a large amplitude of motion.

Evaporation can take place at any temperature.

Boiling takes place only after the temperature reaches the boiling point.

I've kept you waiting.

If you have any questions in the future, you can come to me and contact me.

I have one more small request.

So many questions should deserve a thumbs up.

Relative Motion Has you ever learned? He asked you if you could jump over a distance of 2 meters when the man jumped? But there are too few conditions for this question, right? It shouldn't be the answer to the question, but if it's the answer question, I don't think the conditions are enough to do it.

Well, this question is more flexible, and we should consider it according to real life. It's all about momentum. The theory of relativity is definitely impossible, how can anyone jump so fast?

First of all, assuming that the boat has no resistance, if the person is as heavy as the ship, then his initial velocity should be half of the normal situation, so the person can jump at least one m, the actual boat should be heavier than the person, plus the water will have a lot of resistance to the boat when jumping out, then the whole has left momentum, and the person will definitely jump more than 1m. so i think he can

It uses Einstein's principle of relativity, according to the formula x for length shortening'=(x-vt) (1-(v 2) (c 2)) The length of the moving object becomes shorter in the direction of motion ......However, it can only be judged that the principle of relativity is used, and the qualitative operation cannot be carried out, and the conditions given by the question are not sufficient. If it's a choice of questions, please send the answers and I'll give you an analysis one by one.

<> the initial velocity in the vertical direction is v1=28sin49, and the horizontal initial velocity velocity is v2=28cos49. The acceleration due to gravity is g = 10m s or.

1. Let h=13m, solve the equation about t1 h=v1t1-gt1 2 2, and choose the value with the larger t1 value (the smaller value is when the ball is in the rising phase).

2. Let h=, solve the equation about t2 h=v1t2-gt2 2 2, and choose the value with the larger t2 value (the smaller value is when the ball is in the rising stage).

x=v2（t2-t1）

This problem is mainly about the conservation of energy, as friction and air resistance are negligible. Take the dotted line as the zero point of potential energy. The potential energy ep mgh, and the kinetic energy is ek=, ep ek

So 2gh = v*v

If it is required not to touch the second summit, then if the centrifugal force f mv*v r f is greater than or equal to mg, it will not touch the second summit.

So the critical velocity is mv*v r=mg

So v*v=36g

And because 2gh = v*v

So 36*g = 2gh

h = 18 (m).

So the height of the first mountain is 18 meters.

Solution: Let the skier mass be m and the speed of reaching the top of the second slope be v. The center of the circle O is the zero potential energy point, and Skier just loses contact with the snow at the crest of the second

Hill shows that on the second slope the skier is only affected by gravity, and if the support force is 0, the centripetal acceleration a=g m=g=v 2 r (1)neglect friction and air resistance

Ignoring friction and air resistance, the skier is only affected by gravity, and the mechanical energy is conserved, so there is:

mg(h+r)=mgr+1 2mv 2 (2) Substitute (1) formula (2) with (2) formula has:

mg（h+r）=mgr+(1/2)mgr

Simplification: h+r=r+1 2r

Substituting the data yields h=1 2r=18m.

Let the mass of this person be m, and the velocity of reaching the second vertex is v to find the height difference h

Conservation according to energy mgh=m(v-squared).

According to the centrifugal force formula f = 2m (v squared) r

f = mg = 2m (v squared) r

v squared) = gr 2

Substituting to the first formula gives h=r 2=18 meters.

The pulley moment, which produces rotational acceleration.

f1-m1g = m1a

m2g-f2 = m2a

f2-f1 = force f on the pulley

Moment of inertia * angular acceleration = f*r The moment of inertia is = 1 2mr2 angular acceleration * r = a

Synthesize the above equation.

f2-f1）r=a/r *1/2mr2

f1=m1g+m1a

f2=m2g-m2a

then m2g-m2a-m1g-m1a =1 2maa = (2m2g-2m1g) (m+2m2+2m1).

In a cello, like most other stringed instruments, the player positioning of the finger determines the fundamental frequency of the string. Suppose one of the strings on the cello is adjusted to play **c (262 Hz) when playing at its full length. With what score must the string be shortened in order to play note that this is the third highest interval (i.e. an e (330 Hz))?

How about five points above or one g (392 Hz)?