What is the formula for finding the maximum value and how to find the maximum value?

Maximum value function: max

Syntax: max(number1,number2,..

Note: 1. The parameters number1 and number2 can be numbers, cell names, contiguous cell ranges, logical values;

2. If it is a data reference such as cell name and contiguous cell range, usually only the numerical value or the numerical part calculated by the formula is calculated, and the logical value and other contents are not calculated;

3. If there is no number in the parameter after the max function, it will return 0

Example: If a1:a5 contains the numbers and 2, then:

max(a1:a5) is equal to 27

max(a1:a5,30) is equal to 30

Minimum function: min

min(number1, number2, .

Note: 1. The parameters number1 and number2 can be numbers, cell names, contiguous cell ranges, logical values;

2. If it is a data reference such as cell name and contiguous cell range, usually only the numerical value or the numerical part calculated by the formula is calculated, and the logical value and other contents are not calculated;

3. If the parameter after the min function does not have a number, it will return 0

Example: A1: A5 contains the values 10, 7, 3, 27, and 2, then.

min(a1:a5) is equal to 2

min(a1:a5, 0) is equal to 0

1.=max(if(sheet1!$a$2:$a$100=a2,sheet1!$d$2:$d$100))

Array formula, press Ctrl+Shift+Enter to end the formula.

2.The actual number of rows is replaced by row.

Use the indirect reference function indirect to return the value of column h for each workbook. Constitute a multi-dimensional reference. Use the subtotal parameter to 4.

I want to handle multidimensional references as if they were max. Find the maximum value of column h for each worksheet. Set max to extract the maximum value in the maximum value of each worksheet.

Look at the function x definition field and bring in the maximum value of the defined domain, which is the maximum value of the function.

The maximum value of the function is calculated as follows:

1) For any x i, there is f(x) m;

This sentence means that the value of the function in the definition domain of the function is less than or equal to a number (m).

2) There is x0 i such that f(x0)=m

This sentence means that in the domain of the definition of the celery number of the source, there should be such a thing as a function equal to x0 of m.

Finding the extreme value of hail is generally done by derivative, and its first derivative is equal to 0.

The maximum value is the largest value in the known data, and in mathematics, the maximum value of the function is often found, and the general solution methods include the commutation method, the discriminant method, the function monotonicity method, the number combination method and the derivation method.

RMS value of sinusoidal alternating current = maximum value 2 = maximum value; Or maximum = 2 RMS = RMS.

The RMS value of the current is specified according to the thermal effect of the current: let the alternating current and the constant current pass through a resistor of the same resistance, and if the thermal effect of the two is equal (i.e., the same heat is generated in the same time), then this equivalent DC voltage, the value of the current is called the AC voltage, the RMS value of the current).

In order to measure the work done by alternating current, a RMS value is introduced, which is based on the thermal effect of the electric current. That is, the value of the direct current is the effective value of the alternating current when the direct current passes through the resistance of the same resistance value and the heat generated in the same time.

1. Find the maximum value by the commutation method.

The maximum value of the commutation method mainly includes triangular commutation and algebraic commutation, and special attention should be paid to the range of intermediate variables.

2. Discriminant to find the maximum value.

It is mainly suitable for functions that can be reduced to quadratic equations about independent variables.

3. Combination of numbers and shapes.

It is mainly suitable for functions whose geometry is more clear, and the geometric model is used to find the maximum value of the function.

4. Function monotonicity.

First, the monotonicity of the function in a given interval is determined, and then the maximum value of the function is found according to the monotonicity.

In Y=AX2+BX+C, B2-4AC is greater than or equal to zero.

If a is 0, then there is a maximum value when x b 2a.

When a>0, when x blocks b 2a, there is a minimum value in Tongheng Hall.

<> first step to prove congruence seems a bit redundant, and the last step is a basic inequality, you can see if you can understand it.

It is known that the infiltration macros a+b+c=32, a 3*b+b 3*c+c 3*a and (a+b+c)*(a+b+c) 3 are related to the acreage.

In the first step, find the inequalities of a 3*b+b 3*c+c 3*a and (a+b+c) 4.

Suppose x*[a 3*b+b 3*c+c 3*a ] y*[ a+b+c) 4 ].

The number of dust resistance of the comparison system ==x=256, y=27

27(a+b+c)^4-256(a^3b+b^3c+c^3a)≥0

256(a^3b+b^3c+c^3a)-27(a+b+c)^4≤0

So a 3b+b 3c+c 3a 27(a+b+c) 4 256=110592=8*(24) 3

When a=24, b=8, c=0 take the equal sign or a=48, b=1, c=0 take the equal sign.

Let a=max

Because 27(a+b+c) 4-256(a 3b+b 3c+c 3a)c(148(ac(a-c)+b 2(a-b))+108(bc 2+a 3)+324ab(a+c)+27c 3+14a 2c+162b 2c+176ab 2)+(a-3b) 2(27a 2+14ab+3b 2)>=0

So a 3b+b 3c+c 3a<=27(a+b+c) 4 256=110592

When a=24, b=8, c=0, the royal army returns to the orange sail to take the other hunger suppression.

It is not easy or impossible to use the method of elementary mathematics to explain the solution of the problem, the problem of elementary mathematics sometimes has a background in advanced mathematics, or is inspired by the knowledge of advanced mathematics, the problem is exactly like this, the problem has an obvious intention of strong patchwork, but the two coefficients 256,27 are like where the silver belt comes from, which requires the experience of the dry field to do the problem, the deep understanding of the problem, the need for wit and wisdom, the following try to give you an idea:

Solution: If a+b+c=32 and f(a,b,c)=a 3*b+b 3*c+c 3*a, then its maximum value must exist;

Step 1: Let a be an unknown, b and c as constants, and x as unknown constants.

then let f(a)=a 3*b+b 3*c+c 3*a-x[32-(a+b+c)], and the maximum value of f(a) exists;

Then: let f (a) = 3a b + c 3 + x = 0, the solution is a=a0, that is, f(a)max=f(a0);

Step 2: Let b be an unknown number and treat a and c as constants.

then let f(b)=a 3*b+b 3*c+c 3*a-x[32-(a+b+c)], then the maximum value of f(b) exists;

Then: let f(b)=3b c+a 3+x=0, and the solution is b=b0, that is, f(b)max=f(b0);

Step 3: Make c an unknown number and treat a and b as constants.

then let f(c)=a 3*b+b 3*c+c 3*a-x[32-(a+b+c)], then the maximum value of f(c) exists;

Then: let f (c) = 3c a+b 3 + x = 0, and solve the empty space c = c0, that is, f(c) max = f(c0);

When f(a,b,c)=a 3*b+b 3*c+c 3*a obtains the maximum value, f(a), f(b), and f(c) must obtain the maximum value at the same time;

then f(a,b,c)max=f(a0,b0,c0)=(a0) 3*b0+(b0) 3*c0+(c0) 3*a0;

Step 4: Find a0, b0, c0;

Yes: Yupai potato a0 + b0 + c0 = 32;3(a0)²b0+(c0)^3+x=3(b0)²(c0)+(a0)^3+x=3(c0)²(a0)+(b0)^3+x=0；

This system of equations cannot be calculated by hand, and the software is used to solve it: a0=, b0=, c0=;

Then: the maximum value of a 3*b+b 3*c+c 3*a f(a0,b0,c0)=(a0) 3*b0+(b0) 3*c0+(c0) 3*a0=415920

Using the Lagrange multiplier method, the content of advanced mathematics, the freshman study, has a partial derivative content.

It is known that a+b+c=32, a 3*b+b 3*c+c 3*a and the mausoleum belt let (a+b+c)*(a+b+c) 3 are related.

In the first step, find the inequalities of a 3*b+b 3*c+c 3*a and (a+b+c) 4.

Suppose x*[a 3*b+b 3*c+c 3*a ] y*[ a+b+c) 4 ].

Comparison coefficient ==x=256, y=27

27(a+b+c)^4-256(a^3b+b^3c+c^3a)≥0

256(a^3b+b^3c+c^3a)-27(a+b+c)^4≤0

Therefore, a 3b+b 3c+c 3a 27(a+b+c) 4 feet 256=110592=8*(24) 3

When a=24, b=8, c=0 take the equal sign or a=48, b=1, c=0 take the equal sign.

Map. This data is ** on the map, and the final result is subject to the latest data on the map.

It is known that a+b+c=32, a 3*b+b 3*c+c 3*a and (a+b+c)*(a+b+c) 3 are the relevant brigades.

In the first step, laugh at the inequality of closing a 3*b+b 3*c+c 3*a and (a+b+c) 4.

Suppose x*[a 3*b+b 3*c+c 3*a ] y*[ a+b+c) 4 ].

Comparison coefficient ==x=256, y=27

27(a+b+c)^4-256(a^3b+b^3c+c^3a)≥0

256(a^3b+b^3c+c^3a)-27(a+b+c)^4≤0

So a 3b+b 3c+c 3a 27(a+b+c) 4 256=110592=8*(24) 3

When a=24, b=8, c=0, the equal sign is taken, and when a=48, b=1, c=0, the equal sign is taken.