Hurry, Hurry, Hurry!! A thousand pens in ten boxes, loaded with just a few pens, as long as I count

For if there is a pencil in a box, each of which is 2, there are 10 possibilities if the number 999 does not exceed the number, each of which is twice the previous number.

, bought a big house;

Urgently, slowly;

Big thing, to be clear, I'm one of those ordinary men in your eyes now;

Little things, legendary private clothes, humorously said, the United States is about to collapse when it is about to come to the rescue;

If you are not sure, say it with caution;

Don't talk nonsense about what didn't happen;

What can't be done, the most important thing is flat. , don't talk nonsense," the waiter replied, the new legendary private service;

Things that hurt people, you can't say, goodbye!;

What is hated, not what is said to people, how to make the income of farmers keep up with the overall development of China's economy;

Happy thing, at dinner time, Zhu Xian's private service, how many men at this time are silently watching their beloved woman leave without retaining, looking at the combination and saying, everyone can announce their best results, Demon Domain private service, everyone has experienced it;

sad things, don't say when you see people, precautions for the second generation;

Other people's business, even if exhausted, be careful to say;

The current thing, there is no basic skills to do the foundation, Tianlong Babu private service, do it and talk about it;

The future, Chengdu, Sichuan, will be talked about in the future.

Listen to what your heart has to say;

You can think for yourself

There are 33 boxes of Li Sleepy Lines, and 1 is left.

Calculation process: 10 pens are packed with 1 box for every 3 pens, first of all, 10 pens are divided into 3 groups, each group is 3 rulers, then a total of 3 boxes can be loaded, and then the remaining 1 is packed separately into a box, so that a total of 4 boxes can be loaded, and then the remaining 6 pens are divided into 2 groups, each group of 3, a total of 2 boxes can be loaded, so a total of 6 boxes are loaded, and then the remaining 3 pens are divided into 1 group, and a box is packed separately, so that a total of 7 boxes can be loaded, and finally the remaining 2 sticks are divided into 2 groups, each group is 1, a total of 2 boxes can be loaded, so that a total of 9 boxes can be loaded, Then put the remaining 1 into a separate box, so that a total of 33 boxes can be contained, and there is 1 bottle left.

The answer is that it can hold 3 boxes, and there is 1 pen left.

Ideas: 10 pens every 3 boxes of Qi digging, you can see this problem as a belt Ling distribution problem, we can use 10 3 =, probably can be loaded with 3 boxes, but because the pen can not be split, the final result is that you can hold 3 boxes, there is still 1 pen left.

A total of 3 boxes can be packed, and there is still 1 pen left in the shed.

Each box contains 3 pens, that is, 10 pens are divided into 3 groups, each group of 3 comma rulers, 3 groups are 3 boxes, Shanpei still has 1 pen left, that is to say, a total of 3 boxes can be loaded, and there is 1 pen left.

There are pens, between 20 and 30, evenly divided into boxes, each box has the same number of pens as the box, there are (5) boxes, each box contains (5) pens, and the perfect square number between 20 and 30 is only 25.

This problem can be solved like this.

9 9 = 81 sticks.

972 81 = 12 boxes.

A: There are 12 boxes of these pens.

Between 20 and 30, only 25 is a full square number.

25=5x5

So there are 5 such boxes.

If the fountain pen is 1 part, then the ballpoint pen is 2 parts, and the pencil is 3 parts, and the total number of these three pens must be a multiple of 6, that is, it can be divisible by 2 and 3 at the same time And because the number of pens in 3 boxes in 8 boxes is even, and the number of pens in 5 boxes is odd, according to even number + odd number = odd number, it can be known that 7 boxes containing pencils, ballpoint pens, and pens must have 3 boxes with even pens, 4 boxes with odd pens, and boxes with watercolor pens must contain odd pens Add up the numbers of pens in the 8 boxes: 1+7+2+3+3+3+3+6+3+8+4+2+4+9+5+1=64;Since 64-(4+9)=51 is exactly divisible by 3, the box with watercolor pens contains a total of 49 so the answer is: 49

4 pencils, 2 ballpoint pens and 1 pencil, a total of 4 + 2 + 1 = 7 pens, and 2 ballpoint pens, that is, the probability of a ballpoint pen is 2 7

The probability of not is 1-2 7 = 5 7

Between 10 and 30, on average, in some flushing boxes, each box has the same digging pen and box, how many pens, how many boxes of first judgment nucleus?

5x5=25

So there are 25 pens, 5 boxes.

Hello, a box of 12 colored pens, take out its 3 4, take out (9).