How many different three digit numbers can be formed by using the four numbers 4, 5, 6, and 7 at one

The number of three-digit numbers composed of four numbers 4, 5, 6, and 7 is the arrangement of three of the four numbers, i.e., p3 4 = 4 3 2 = 24, so a total of 24 different three-digit numbers can be formed.

First determine the single digit of this three-digit number, choose any one of the four numbers, there are 4 choices; If you determine ten more digits, there are 3 options for a number that has been selected, and there are 2 options for the same number of hundreds. So it can be composed of different three-digit numbers:

4 3 2 = 24.

456,465,467,476,475,457,4 There are 6 kinds of hundreds, so there are 6*4=24 different three-digit numbers.

If you engrave these four characters once, you can make up a total of 16 different numbers in a unit, such as 456 or 457.

Use the four numbers 4, 5, 6, and 7 once to form a total of different three-digit numbers.

4 3 2 = 24.

A total of 24 different three-digit numbers can be formed.

456 567 674 745 can make up 4 three-digit numbers.

How many different three-digit numbers can be formed by using the four numbers 4, 5, 6, and 7 at one time? First of all, it's a matter of permutations, c43c32c31

How many different three-digit numbers can be formed by using the four numbers 4, 5, 6, and 7 at one time? 4x3x2

In permutation, I 456-457-465-467-475-476Each number starts with 6 digits, so there are at least 24 numbers, and you can also use permutations and combinations: a3 4=4x3x2=24

Combine with permutations.

It's four numbers, choose three of them, and then reverse the order to arrange.

If you use each of these four numbers once, you can form a total of 16 different three-digit numbers, such as 356, 357, 367, etc.

The first number can be any of the four numbers so there are 4 kinds, the second number can be any of the remaining 3 numbers so there are 3 kinds, and the third number can be any of the remaining 2 numbers, so there are 2 kinds, so there are a total of 4 3 2 = 24 different three-digit numbers.

With the four numbers 3567, a total of 4 3 2 = 24 can be composed of different three-digit numbers.

There are 4 possibilities for hundreds, 3 possibilities for tens and 2 possibilities for single digits, so the total is 4 3 2 = 24, so a total of 24 different three-digit numbers can be formed.

Hello, there are a total of 24 kinds of 4, 5, 6, 7 these four numbers each once, how many different three-digit numbers can be formed?

4x3x2=24

6 in the highest position: 6037, rotten Qing a total of 6 four mountains grandson digits.

There are 6 first four digits in each of the highest digits, so there is a total of: 6x3 = 18 quadruple digits.

There are 6 different ways to choose the hundredth number, (because 0 can't be the first place) there are 6 different ways to choose the ten-digit number, (because 1 number is selected) there are 5 different ways to choose the single digit, (because 2 numbers are selected), so a total of 6 6 5 = 180 choices, that is, 180 different three-digit numbers.

8x7x6x5=1680 (species).

This is a multiplication problem (pick-and-match problem).

There are 8 numbers to choose from in the highest thousand, 7 numbers to choose from in the 100 place, 6 numbers to choose from in the 100th place, and 5 numbers to choose from in the single place, 2211, 1122, 2221, 2221, 1112, 1222, 2111, 1211, 1121, 2112, 2122

Using the numbers 1 and 2 to form a seven-digit number, how many combinations are there?

2 7 = 128, there are a total of 128 group methods.

The numbers are arranged, a44 = 24 four-digit numbers.

2.Four students are lined up, and because there are directions (standing on the left and right of the row are different combinations), then there are 24 kinds.

Use the four numbers 3, 4, 5, and 6 to form a four-digit number, and the probability that the last digit of the four-digit number is 6 (choose b).

The probability is equal, so it's 1 4

That's 8 numbers, it's 6 numbers.

6*6*6*6=1296 combinations.

If it is 8 digits, it cannot be repeated.

8*7*6*5=1680 combinations (8 different arrays form 4 digits, which can be repeated 8*8*8*8=4096).

Not sure what your problem is!

There are 4 kinds of propositions that this kind of question generally can't escape:

Using the four numbers 7895 to form a four-digit number, how many four-digit numbers can there be: 24 answers.

Using the four numbers 7895 to form a four-digit number, what is the largest four-digit number Answer: 9875

Using the four numbers 7895 to form a four-digit number, what is the smallest four-digit number Answer: 5789

The four digits 7895 are used to form a four-digit number that is divisible;Generally, this number may be 2 3 5, all possible, but it can be divisible by 2, you need to be an even number, here is 8, divisible by 3, it is possible for the single digit to be these four numbers, so it will definitely not be such a proposition; Divisible by 5, the single digit must be 5 or 0 and here it is 5!

Hope it helps!

120 species. Here's the permutation formula:

Choose 4 out of 5, no restrictions, and the arrangement formula: 5x4x3x2=120

To be divisible by 2, it must be even, so the ends must be 2 and 8

When the unit digit is 6, there are 3*2*1 = 6 numbers, and when the unit digit is 8, there are 6 numbers, then there are 12 numbers in total.

Let the other number be x x and unequal to 9When 999x, there are 9. When 99x9 is, there are 9. When 9x99, there are 9. When x999There are 8 of them. So.

3x9+8=35 There are 35 in total.

With these four numbers, if you don't repeat them, you can make 4! = 24 different four-digit numbers. If it could be repeated, it would be 4 to the 4th power, which is 256 different quadruple digits.

The numbers 2, 3, 5, and 7 can be combined: 4x6=24 (kind).

If it can't be reused, there can be 24; If it can be repeated, there can be 256.

3 has 6 quadruple digits in the highest digit and 6 quadruple digits in the highest digit. So there are 3 6s, i.e., 3x6 = 18 four-digit numbers.

There are a total of 156 species in 4 to the 4th power.

Hello! (Four digits without heavy digits).

1) There are 3 numbers that can appear in the thousands;

2) The number on the thousand position is set, and there are 3 numbers on the hundred place to choose;

3) There are 2 numbers to choose from for the remaining tens; There is only one single digit. From the principle of multiplication:

3 3 2 1 = 18 (pcs).

Hope it helps!

This can be done by simply drawing out 4 different number arrangements.

a(6,4)=6*5*4*3=360.