6th grade math problems, everyone help! Thanks! Urgently needed!

Arithmetic: (50 26-970) (50-20) = 11 (sheets), 26-11 = 15 (sheets), that is, 11 cards with 20 face values, and 15 cards with 50 face values.

Idea: Assuming that all of them are RMB with a face value of 50, the total amount is 50 times 26 to get 1300 yuan, which is 1300-970 = 330 yuan more than the real number. The reason for the extra is that the 20 denomination is counted as 50, that is, each 20 denomination of RMB is overcalculated by 50-20 = 30 yuan, a total of 330 yuan more, then 20 denominations of 330 divided by 30 equals 11.

I don't know if you can understand it, this is the solution of the hypothetical method of the chicken-rabbit cage problem, and the equation method is used by so many people.

There are x sheets for 20 yuan and y sheets for 50 yuan.

Available: 20x+50y=970

x+y=26

Solution x=11

y=15A: There are 11 cards for 20 yuan and 15 cards for 50 yuan.

11 sheets for $20 and 15 sheets for $50.

Set the number of $20 as x and the number of $50 as y

20x+50y=970

x+y=26

Just solve the equation.

There are x sheets for 20 yuan and y sheets for 50 yuan.

So: 20x+50y=970

And x and y are both positive integers, so we can get: x=11, y=13, and there are 11 and 15 pieces of RMB paper with a face value of 20 yuan and 50 yuan respectively.

Chickens and rabbits in the same cage.

Algorithm: (50 26-970) (50-20) = 11 (sheets), 26-11 = 15 (sheets), that is, 11 sheets of 20 face values, and 15 sheets of 50 face values.

If you carefully flip through the math wide-angle example problems about chickens and rabbits in the same cage, this is easy to understand.

The system of equations for column x,y is .........Set 20 yuan has x sheets, 50 yuan has y sheets, and then solve it yourself, prompting that it will not be time to reflect on your own learning.

Solution: Set 20 yuan with x sheets, 50 yuan with y sheets, according to the title, get.

x+y=26

20x+50y=970

Solve the system of equations to get x=11

y=15A: There are 11 cards for 20 yuan and 15 cards for 50 yuan.

Set 20 yuan with x sheets, 50 with y sheets.

Column equation x+y=26

20x+50y=970

The solution yields x=11 and y=15

Solution: There are x pieces of RMB with a face value of 20 yuan.

Then there are 26-x pieces of RMB with a face value of 50 yuan.

20x+50(26-x)=970

30x=330x=11

A: There are 11 and 15 renminbi denominations of 20 yuan and 50 yuan respectively.

Let 20 yuan have x sheets and 50 yuan y sheets, and the following equation is obtained according to the meaning of the question.

1）20x+50y=970

2）x+y=26

The solution yields x=11 and y=15

That is, there are 11 tickets for 20 yuan and 15 tickets for 50 yuan.

11 pieces of RMB 20 and 15 pieces of RMB 50.

Set 20 yuan has x sheets, so.

20x+50(26-x)=970, get x=11, so 11 pieces for 20 yuan, 15 cards for 50 yuan.

20 yuan for 11 sheets. 50 yuan for 15 sheets. Now remove one of 50 and 20 yuan, and come out with 900 integers, which are calculated as 900 integers.