Known 2007 a 2005 a 2006, then 2007 a 2007 a 2005 a 2005 a

Updated on society 2024-06-10
7 answers
  1. Anonymous users2024-02-11

    2007-a〕〔2007-a〕+〔2005-a〕〔2005-a〕

    2007-a)+(2005-a)] 2-2* 2007-a 2005-a (put the formula sought).

    4*[(2006-a) 2]-2*2006 (simplifying the square term and bringing in known conditions).

    4*[2006*2006+a*a-2*2006*a]-2*2006 (square term).

    4*[4024036+a*a-4012*a]-4012 --1.

    By the known condition 2006 = 2007-a 2005-a = 2007*2005+a*a-4012*a

    4024035+a*a-4012*a

    A*A-4012*a=4022029 (bring in 1 formula).

    When I woke up in the morning, I saw that you said, "The answer should be specific", so I wrote down the reason for doing this every step, hehe.

  2. Anonymous users2024-02-10

    2009-a) 2 + (2008-a) 2 , (2009-a) 2 + (2008-a) 2 -2 (Lu Ming 2009-a) (Shanhua 2008-a) +2 (2009-a) (2008-a), [2009-a)-(2008-a)] 2 +2 (2009-a) (2008-a), 1+2 2007, 4015

    Therefore, fill in 4015

  3. Anonymous users2024-02-09

    (2008-a) 2 + (2007-a) 2 = 1.

    2008-a) 2 -2 (2008-a) (2007-a) + (2007-a) 2 = 1-2 (2008-a) (2007-a), i.e., Heng Coarse (2008-a-2007 + a) 2 = 1-2 (2008-a) (2007-a), collated -2 (2008-a) (2007-a) = 0, (2008-a) (2007-a) = 0

  4. Anonymous users2024-02-08

    From the cautious branch to the judgment: wide chongsen.

    2008-a)*(2006-a)=2007 then: 2008-a) 2*(2006-a)2[(2008-a)(2006-a)] 2

  5. Anonymous users2024-02-07

    2006-a|+ Answer: A-2007 = A because A-2007 > = 0

    The empty ruler is used as |2006-a|+√a-2007)=a-2006+√(a-2007)=a

    Then (a-2007)=2006, i.e., a=2006 2+2007(a-2006 2+18)= 2006 2+2007-2006 2+18) = 2025=45

  6. Anonymous users2024-02-06

    Simplify both equations.

    Manuscript: Blind Zen a+2009-1) key dust (a+2009-1) = 2011a 2 + 2009a + a + 2009a + 2009 2 + 2009-a-2009-1 = 2011

    a^2+4018a+2009^2=2011a+2009）^2

    a^2+4018a+2009^2

    It should be understandable, I wrote it myself, and it was divided.

  7. Anonymous users2024-02-05

    (2005-a)+(a-2003)] 2 and [(2005-a)+(a-2003)] is completely squared.

    2005-a）²+2×（2005-a）×（a-2003）+（a-2003）²

    2005-a）²+a-2003）²+2×(-2004) [2005-a）×（2003-a）=2004]

    So. 2005-a) +a-2003) =4+2 2004=4012 Look at the preparation and stop the praise of me

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