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Anonymous users2024-02-111) Let this function be g(x)=ax 2+bx+c through (0,0),(m,0),(m+1,m+1)so. 0=c
0=am^2+bm
m+1=a(m+1)^2+b(m+1)
Solution: a=1, b=-m
So y=g(x)=x 2-mx
2) g(x)=x 2-mx=(x-m 2) 2-m 2 4 minimum value is obtained at x=m 2, which is -m 2 4=-1 to obtain m= 2
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Anonymous users2024-02-10Let y=ax 2+bx+c
If the three points do not coincide, then m≠0 and m≠-1
Point (0,0) is substituted for y=ax 2+bx+c, c=0 point (m,0) is substituted for y=ax 2+bx, am 2+bm=0(1) point (m+1, m+1) is substituted for y=ax 2+bx, m+1=a(m+1) 2+b(m+1) (2).
1) (2) Synthesis.
am+b=0，a=1，b=-m
y=x^2-mx
y=x^2-mx=(x-m/2)^2-m^2/4m^2/4=-1
m=±2
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Anonymous users2024-02-09g(x)=ax^2+bx+c
From (0,0) to know c=0
g(x)=ax^2+bx
Bring in (m,0) (m+1,m+1).
g(m)=am 2+bm=0 so m=0 (rounded) or m=-b a (1).
g(m+1)=am^2+2am+a+bm+b=am^2+(2a+b)m+(a+b)=m+1
So (am+a+b-1)(m+1)=0, so m=-1 (rounded) and m=(1-a-b) a (2).
By (1), (2) so a=1 so g(x)=x 2+bx by the minimum value of -1 and g(x)=(x+b 2) 2-b 2 4 so b = 2 or -2
It can be seen that g(x)=x 2-2x, g(x)=x 2+2x, so m=-2 and +2
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Anonymous users2024-02-08To do differentiation, first you have to analyze which type it belongs to, and the first step is to convert it to d(sin5x)3
Then look at sin5x as a whole and differentiate it for sin5x 3 to get the square d of 3sin5x (sin5x).
The third step is that d(sin5x) is equal to cos5xd5x, and the fourth step is that d5x is equal to 5
There is already a lot of detail.
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