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If the distance between AC and AC is x kilometers, then the car departs to C and then returns to meet Group A after 2x (60+4)=x 32 hours, then there is x 32+(18-4*x 32) 60=x 60+(18-x) 4
If x=16, the distance between AC and the two places is 16 km.
Group A walked 4*16 32 2 km, and Group B walked 18-16 2 km.
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Solution: Suppose soap is $ x and toothpaste is $ y.
39x+21y=396
52x+28y=518
13x+ because 132 ≠
So there is no solution to the equation.
So there is a mistake. I'm a teacher, thank you.
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It is known that in the solution of the binary equation 3x+2y=k, 2x+3y=k+3, the sum of x,y is 8, and the value of k is obtained.
Solution: Replace 3x+2y=k with 2x+3y=k+3 to get:
2x+3y=3x+2y+3
Shift: 2x+3y-3x-2y=3
Merge similar items: carry filial piety y-x=3
x+y=8y-x=3
x+y=8+y-x=3:
2y=11y=
Substituting y==y-x=3 to get the back draft.
x=I'm a teacher, thank you.
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Solution: 12+b=-2
5a+20=15②
Derived: b=10
Result: a=-1
So get it again:
x+5y=15③
4x-y=-2
Solution: Hall do x=14, y=29 5
I'm a teacher, thank you.
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At this time, the total profit w 20x+16800-a*x=(20-a)x+16800, a<200-170 30
When A<=20, X takes the maximum value, that is, X 40 (i.e., Type A is all sold by A, the same as Q2).
When A>20, X takes the minimum value, i.e., X 10 (i.e., B sells Type A).
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Input: 2013 Summer Vacation Seventh-Grade Mathematics You can check and learn to carry a boat.
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Is it applicable to people's education textbooks?
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1) Set up a closed water pipe before the land mold cover put x hours of yards of water.
The water released within 2 hours after the water pipe is closed accounts for a pool of water
There was one in the pool before. of water. x=
Wasted : pool).
2) After Y hours, the water in the pool begins to overflow and make a morning noise. y=
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1) Set the water for x hours before closing the water pipe.
The water released within 2 hours after the water pipe is closed accounts for a pool of water
There was water in the pool before.
x= wasted: pool).
2) The water in the pool begins to overflow after Y hours. y=
1): Square difference formula: original formula = (y+3+3-y)(y+3-3+y)6*2y12y >>>More
1.Let the single digit be x, then the ten digit is x+1, and this two-digit number can be expressed as 10 (x+1)+x, that is, 11x+10, from 30<11x+10<42 and x is an integer, the solution is x=2, and the two-digit number is 32 >>>More
n*(n+2)*(n+4)*(n+6)+16n*(n+6)*(n+2)*(n+4)+16(n^2+6n)(n^2+6n+8)+16(n^2+6n)[(n^2+6n)+8]+16(n^2+6n)^2+8(n^2+6n)+16(n^2+6n+4)^2 >>>More
First, the number of squares.
1. The number of small squares n1=3n >>>More
Solution: Let bod=2x°, then boe=3x°
ob bisects boc, coe= boe=3x° >>>More