How do you do this question, teacher?

Well, the title is simple, but it's a pity that the formula has been forgotten.

You need to imagine the whole process of motion and then explain it with the physics formulas you have learned.

1) Imagined movement process:

Rub the MN rod with your hand, the MN rod rotates, and then, the stationary A ring is shaken, the rope OA is stretched, and then it reaches the state of problem (1), that is, it has just been straightened, then the A ring starts to do a circular motion, then you increase the force in your hand to turn the MN rod, and keep increasing the force, and then the OA rope is torn off, which is the state of problem (2), and finally it is thrown out. Until the ab rope is straightened, then continue to start doing a circular motion, which is the state of problem (3).

gameover!

This game can't be played anymore.

2) Physical explanation during movement:

For the A ring, the A ring starts to do a circular motion from rest, when the external force of the A ring is greater than the centripetal force required by the A ring, the A ring moves outward, so the rope is stretched, (this is how the clothes dryer works) and then to the (1) state, the A ring finally gets the new ** of the centripetal force it needs - the pulling force provided by the OA rope. Then, when the external force experienced by the A-ring is equal to the centripetal force required by the A-ring, the A-ring starts to move in a uniform circular motion. Then the rotation of the device accelerates, the centripetal force required by the A-ring becomes more and more large, and then, the limit provided by the rope OA, which is the state of problem (2), is reached, and then ......Then .........

And then there was none.

Physics problems, physical phenomena, space shuttle going into space, launching missiles, all problems are solved in this way.

In the beginning, you have to imagine the whole process, calling on your life experience, playing ball, mopping the floor, Angry Birds and so on. There will be some errors in it.

Then, start using what you've learned about physics, check your imagination, find the mistakes, correct them, and finally, the solution will emerge.

…Uh.........Have you already provided answers from your colleagues? ......

Well. However, learning to think still learns an answer.

The choice is your own.

I don't know, ask yourself. o( o hahaha

24 + 1 3 = 24 and 1 3 kg.

The last two questions do not explain Bai Zhibu, and guessing that Meng lead cannot solve the ear is easy to answer.

16 is 24 less than 1 3.

24 and 1 3 kg more than 24 3 kg.

16 is 24 less than 1 3.

1 3 = 24 and 1 3

24 and 1 3 kg more than 24 3 kg.

3. A 1 3 = B 1 4 = C, B is the largest.

4. Find the area of the planted tree first, and then find the remaining area.

The area under the remaining orange (2+3) 2, the brother and the group found the area of the first flower.

Solution A When the current source acts alone, the 12V voltage source is short-circuited.

According to KCL, the resistor current of the right terminal 2 is: 3i1-4-2i1=i1-4.

kvl：2i1×2=2×（i1-4），i1=-4（a）。u'=2i1×2=4×（-4）=-16（v）。

When the V voltage source acts alone, the 4A current source is open.

According to KCL, the resistance current of right segment 2 is: 3i1-2i1=i1.

kvl：2×2i1+12=2×。

u"=2i1=2×（-6）=-12（v）。

3. Superposition: u=u'+u"=-16+（-12）=-28（v）。i1=-4-6=-10（a）。3i1=-30a。

Controlled current source power: p=3i1 u=(-30) (28)=840(w)>0, and you and 3i1 are non-correlated positive directions, so the output power of the controlled current source is 840W.

Which question? Please send me the question** to see!

First of all, it is stated that the English question is not answered, and there is only one question.

Questions. <>

Thank you for that question.

Okay, please wait a minute, I'm calculating.

Questions. Thank you.

Do you understand?

Hope it helps! Give it a thumbs up!

Questions. Good.

This question is mainly the addition, subtraction, multiplication and division of fractions and general scores, sometimes it will be a little troublesome, but it is not difficult, and you need to be patient to solve.

Questions. <>

Could you please help me see the process of solving the sixth question, thank you.

Wait a minute. <>

I won't answer it later, that's all, goodbye!

You're welcome ha.

Thank you, Mr. Zhang, for your question, I love you.

The last two digits of the product are equal to the product of the multiplier single digit and the multiplied single digit.

The number before the last two digits of the product is equal to the product of the number in the multiplied tens plus 1 and the number in the multiplied tens digits. (or the product of multiplying the number in the tens and adding 1 to the number in the multiplied tens place).

As shown in the screenshot, 71x79=5609

The last two digits of the product are equal to 1x9=09;The number before the last two digits of the product is equal to 7x(7+1) or (7+1)x7=56

You didn't get all three questions right, and the correct way to do it is as follows:

The second group poured more.

The two groups watered a total of 5/9 of the flower beds.

Four-nineths of the remaining flower beds have not been watered.

This is to test the student's concept of fractions, the first group watered one-ninth of the flower bed, the flower is regarded as the whole one, that is, one times one-ninth, the second group watered four-ninth, that is, one times four-ninth, in fact, it is to compare the size of the fraction, the denominator is the same, the numerator is large, so the second group watered more.

(1)1/9<4/9

The second group poured more.

2) 1 9 Ten 4 9 = 5 9

The two groups poured a total of 5 9.

3) 4 9 a 1 9 = 3 9

The second group poured 3 9 more than the first

4) 1-1 9-4 9=4 9

There are 4 9 left unwatered.

More than to teach, to use more and less.

Brother, the first question is that the size is 1 9 < 4 9

The second problem is summation, 1 9 + 4 9

The third is that the whole garden is a whole, and it is regarded as 1, and all of it has 1-(1 9+4 9).

You're doing it wrong, 1) the second group is more.

3) 1-5 9 = 4 9 remaining

Derivative of f(z) = 3z 2+8i

The Z=1-i belt rock of Wuqing was stopped in front of the cavity jujube 3*(1-i) 2+8i=3*(1-2i-1)+8i=2i

Finding =2i Note: The square of i is equal to -1