Chemistry equations for Grade 8, all chemistry equations for junior 3

c+o2=co2

C and O2 react at a mass ratio = 3:8.

The mass of the first generation of CO2 is 11 grams (3 grams of carbon and 8 grams of oxygen, exactly the complete reaction) and the mass of the second generation of CO2 is 22 grams (6 grams of carbon and 16 grams of oxygen, there is carbon left, 6 grams remaining).

The mass of CO2 generated for the third time is 22 grams (6 grams of carbon and 16 grams of oxygen, oxygen is left, 8 grams remaining).

Why didn't the second experiment produce 28 grams of carbon dioxide? Which substance has a surplus? How many grams are left?

The two reactants reacted according to a mass ratio of 3:8, and only 22 grams of CO2 were generated, and there was a surplus of carbon, and 6 grams remained.

c+o2=co2

From this chemical equation and the molecular weight of each substance, it can be obtained that the mass ratio of carbon and oxygen when carbon dioxide is generated should be 12:32=3:8, so only when the two are exactly in this ratio can the reaction be complete, if it is not this ratio, then only the amount of carbon dioxide generated is obtained according to the mass of the least substance, and the third medium carbon is only 6 grams, so the corresponding can only consume 16 grams of oxygen, so only 22 grams of carbon dioxide can be generated.

To understand the basics, and then on the basis of understanding, these kinds of problems will be easily solved.

c+o2=co2

To generate 22 gCO2, you need 16 g of oxygen and 6 g of carbon dioxide (I want to use mol, considering that I may not have studied in junior high school).

So there is a surplus of carbon dioxide, 6g remaining

The chemistry equation for junior high school is as follows:1. Magnesium burns in air: 2mg+O2 ignites 2mgo2, iron burns in oxygen:

3Fe + 2O2 ignites Fe3O43, copper is heated in the air: 2Cu + O2 is heated 2CuO4, aluminum forms an oxide film in the air: 4Al + 3O2 = 2Al2O35, zinc and dilute sulfuric acid:

Zn + H2SO4 = ZnSO4 + H2 6, Iron and dilute sulfuric acid: Fe + H2SO4 = FeSO4 + H2 7, magnesium and dilute sulfuric acid: Mg + H2SO4 = MgSO4 + H2 8, Aluminum and dilute sulfuric acid:

2Al+3H2SO4=Al2(SO4)3+3H2 9, zinc and dilute hydrochloric acid: Zn+2HCl==ZnCl2+H2 <>

10. Iron and dilute hydrochloric acid: Fe + 2HCl = = FeCl2 + H2 11, magnesium and dilute hydrochloric acid: mg + 2HCl = = MgCl2 + H2 12, Aluminum and dilute hydrochloric acid:

2Al+6HCl==2AlCl3+3H2 13, iron and copper sulfate solution reaction: Fe+CuSo4==Feso4+Cu14, zinc and copper sulfate solution reaction: Zn+CuSo4==ZnSO4+Cu15, copper and mercury nitrate solution reaction:

cu+hg(no3)2==cu(no3)2+hg

The chemistry equations for the third year of junior high school are all as follows:1. Magnesium burns in air: 2mg+O2 ignites 2mgo2, iron burns in oxygen:

3Fe + 2O2 ignites Fe3O43, copper is heated in the air: 2Cu + O2 is heated 2CuO4, aluminum forms an oxide film in the air: 4Al + 3O2 = 2Al2O35, zinc and dilute sulfuric acid:

Zn + H2SO4 = ZnSO4 + H2 6, Iron and dilute sulfuric acid: Fe + H2SO4 = FeSO4 + H2 7, magnesium and dilute sulfuric acid: Mg + H2SO4 = MgSO4 + H2 8, Aluminum and dilute sulfuric acid:

2Al+3H2SO4=Al2(SO4)3+3H2 9, zinc and dilute hydrochloric acid: Zn+2HCl==ZnCl2+H2 <>

10. Iron and dilute hydrochloric acid: Fe + 2HCl = = FeCl2 + H2 11, magnesium and dilute hydrochloric acid: mg + 2HCl = = MgCl2 + H2 12, Aluminum and dilute hydrochloric acid:

2Al+6HCl==2AlCl3+3H2 13, iron and copper sulfate solution reaction: Fe+CuSo4==Feso4+Cu14, zinc and copper sulfate solution reaction: Zn+CuSo4==ZnSO4+Cu15, copper and mercury nitrate solution reaction:

cu+hg(no3)2==cu(no3)2+hg

There are mistakes that need to be corrected.