A more interesting physics problem, a small physics problem

Updated on educate 2024-06-02
11 answers
  1. Anonymous users2024-02-11

    Your question is wrong. When a group of people has a pull force of 18,000 N, the pull of an elephant cannot be 20,000 N, and the two are always equal in size. If the maximum pulling force of an elephant is 20000N

    The maximum pull force for a group of people is 18000N. Then the maximum force of the rope is 18000N. Done: Thank you.

  2. Anonymous users2024-02-10

    The resultant force can be calculated as 2000N.

    The rope is a stressed object, and it is enough to directly analyze the resultant force of the force. However, this rope is a rope whose mass cannot be ignored, but its gravity is negligible. The gravitational force is small relative to the tensile force and can be ignored, but the mass of the rope cannot be ignored, otherwise there will be an infinite acceleration.

  3. Anonymous users2024-02-09

    2000, according to the force analysis, the direction of the two forces is opposite, and the resultant force is the difference between the two, so it is 20000-18000=2000

  4. Anonymous users2024-02-08

    Of course it is a smaller force of 18000

    The rope does not take into account its own mass is forcefully unbalanced and there is acceleration, and the unbalanced net force is zero.

  5. Anonymous users2024-02-07

    It's 2000, you just need to consider the imbalance of the force at this time, and there should be acceleration.

  6. Anonymous users2024-02-06

    The resultant force is 2000 N, providing its acceleration.

    The internal tension is 18,000 N (Lou Da refers to the action and reaction forces reflected here).

  7. Anonymous users2024-02-05

    Since it is the resultant force is subtracted by 2000, the rope seems to be more confusing. It is better to change it to a wooden block to a left 20000 and a force to the right 18000Be clear this way.

  8. Anonymous users2024-02-04

    2000 Ah, the difference between the two interaction forces.

  9. Anonymous users2024-02-03

    It is easy to explain by the physical formula: q=c*m*t

    Wherein: q is heat; c is the specific heat capacity; m is the mass; t is the difference between the elevated temperature, which is the temperature after the change minus the temperature before the change;

    q1=c1*m1*t1;q2=c2*m2*t2, the simplest way to make c1 is 1 and t1 is 3, and it is easy to get the answer to be d3:4

  10. Anonymous users2024-02-02

    1.Under the action of constant resultant external force and drag, the acceleration is A11 2A1(4) = 8m

    a1=1m/s²

    After turning off the engine, the speed of turning off the engine is 4m s and the car moves for 2s to stop, and the acceleration is a2 = 2m s drag f = 2 * 2000 = 4000n

    f (traction) - f = 2000*1

    f=6000n

  11. Anonymous users2024-02-01

    There are the answers and processes you need!!

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