Finding the arc length of a semicircle? How do you find the arc length and area of the semicircle?

It's not a half-garden, it's a bow.

Bow calculations. Chord length b= bow height h=

radius r=(b 2+4h 2) 8h

The corner of the garden is a = 4arctg (2h b).

Arc length = r * a = 4 rarctg (2h b).

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The formula for calculating the arc lengthis: l=n r 180, l= r

The formula for the sector area is: <>

1. Arc length formulal = n (central angle.

Pi. r (radius) 180 = (radian of the central angle) r (radius) in a circle with radius r, because the arc length of the 360° jujube is equal to the circumference of the circle.

c=2 r, so the arc length of the central angle of n° is l=n° r 180° (l=n°x2 r 360°).

For example, the arc length of the radius of 1cm and the central angle of 45° is the stool.

l=nπr/180

Approximately equal to2. Formula for calculating the sector area

where l is the arc length, n is the central angle of the fan, is pi, and r is the radius of the fan. Arc length l=2 Angle of the central angle (angle system) Pi Radius 360° Arc length l = angle of the central angle (angle system) Pi Radius 180°

There are two ways to calculate an arc:

Angle system: s= *n*r*r 360

Radian system: s=lr 2=a*r*r 2

The question in the question uses the radian system, r is the radius, and l is the arc length.

The semicircle is also an arc, the straight line connecting the two points of AB is the chord AB, and the semicircle is neither an inferior arc nor an excellent arc, it is a beam that distinguishes the inferior arc from the superior arc.

The circumference of the semicircle can be calculated by judging the arc length.

Assuming that the length of the arc of the semicircle is l, then the circumference c of the semicircle can be calculated by the following formula:

c = 2πr

where r is the radius of the semicircle. Since it is a semicircle, the radius r is equal to the length of the arc l divided by twice the length of

r = l / 2π)

Substituting the value of r into the formula for the perimeter gives the formula for calculating the circumference c of the semicircle:

c = 2π(l / 2π))l

Therefore, the circumference of the semicircle is equal to the length of the arc of the draft.

Multiply the arc length by 2, divide by pi, and divide by 2 to get the radius.

Arc length = circumferential angle * r, the circumferential slow digging angle of the semicircle is 90 degrees, or 2r = arc length and the rough circumference of the circle = 2) = 2

The radius is 2, note that the circumferential angle is 90 degrees, that is, 2, (when operating, use radians to substitute) c=2 r1 2c=1 2 2 r= r=1

Multiply the arc length semicircle by 2, divide by pi, and divide by 2 to get the radius.

Formula: l = n r 180° [arc length is equal to 180° bai of n (central angle) multiplied by du multiplied by r (radius)].

l=nπr/180°

l=nπ/180°× r

l×180°/nπ=nπ/180°× r ×180°/nπ180°l/nπ=r

r=180°l/nπ

In general, the arc length of a circle is still used: the radians of the arc length multiplied by the radius of the circle. Generally, there can be the following conversions:

1. The circumference c of the known circle and the angle d of the arc are id: arc length = c * (d 360);

2. The radius r of the known circle and the angle d: arc length = r * (d * 2pi 360).

The length of the week is 2 * radius.

Any angle = radius * (the value of the angle to which it is converted).

If you go deeper, use the line integration in mathematical analysis.

Its value can be derived.