Easy junior high school math problem T T take out all the points

1。The absolute value of a negative number is a positive number (right) and the absolute value of a rational number must not be a negative number (right)2. Two plus or minus 2 3

04. No.

6.Plus or minus 3 4 positive positive number.

7。Plus or minus 6

8。Plus or minus 1, plus or minus 2 and 0

9。Plus or minus 4 plus or minus 5

10。Equal or opposite.

y=-4 call hope it helps you.

Look at the answers, and don't get the order wrong!

2 -2 3 and 2 3

1 0 does not.

3 4 Positive Positive numbers 6 and 6

It may be equal or it may be a positive and a negative number.

Study hard.

The absolute value of a negative number is a positive number ( The absolute value of a rational number must not be a negative number ( How many numbers are there with an absolute value of 2/3? What is it?

A: There are 2. Yes - 2/3 and 3/2.

How many numbers are there with an absolute value of 0? What is it?

A: There is 1. Yes 0

Is there a number with an absolute value of - (minus)?

A: No. Because all absolute values are positive and there are no negative numbers.

Write all integers that are greater than - (minus) and smaller than + (positive) and use them together"<"Connect them with these two numbers.

Answer: -3<-2<-1<0<1<2<3<4<5<6<74 absolute value is (3/4) The absolute value of a positive number is (itself) The absolute value of a negative number is (its opposite).

A number with an absolute value equal to 6 is (-6 or 6).

Integers with absolute values less than 3 are: 3,2,1,0,-1,-2 Integers with absolute values less than 6 and greater than 3 are: -4,-5,4,5 If the absolute values of two numbers are equal, then these two numbers: are opposites.

Known |x|=3,|y|=4 x>y, then x and y are: x=-3 or 3, y=-4 or 4, respectively

SUM = (first term + last term) * number of items 2

Number of Items = ((Last Item - First Term) Tolerance) 1

and = (300 + 2006) * (2006-300) 2) + 1) 2 = 984 662

Solution: by 1 x - 1 y = 4

(multiply xy by xy and -xy).

y-x=4xy

x-y=-4xy

So (2x+3xy-2y) (x-2xy-y)=[2(x-y)+3xy] [(x-y)-2xy]=(-8xy+3xy) (-4xy-2xy)=(-5xy) (-6xy).

Ideas:1Simplification (conscious and conditional connection).

2.Ordinary substitution.

3.Evaluation.

Hello, the answer you want is:

Divide the numerator and denominator of fraction (2x+3xy-2y) (x-2xy-y) by xy (because xy is not zero), 2x+3xy-2y) (x-2xy-y)=(2 y+3-2 x) (1 y-2-1 x)=[3-2(1 x-1 y)] [-2-(1 x-1 y)]=(3 4-2 4) (-2-4).

The relationship between X Y and X Y can be brought in by one.

(2x+3xy-2y) (x-2xy-y)=[2(x-y)+3xy] [(x-y)-2xy]=[2(1 y-1 x) +3] [(1 y-1 x) -2] (the numerator and denominator are divided by "xy").

Ideas: Just remember one step for this topic: 1. Deformation (there are also simplified ones); 2. Substitution; 3. Calculate the result.

You guys learned so fast, we haven't even finished learning inverse proportional functions.

(1)x5-(2)2y=5a-31 y=(5a-31) 2(2)-(1)x3 gets 2x=31-3a x=(31-3a) 2, according to the title, x=(31-3a) 2 0 y=(5a-31) 2 0

So 31 3 a 31 5 10 + 1 3 a 6 + 1 5 so a

Multiply the first equation by 5 and substitute the second equation to find x y

Odd number. Think about which ones you have.