There are three consecutive odd numbers whose product is 5 3, so what are the three numbers t

Hello! Three consecutive odd numbers, the product of the single digit is 3, then the single digit of the three numbers must not be 5, then the single digit can only be not satisfied).

The product is more than 50,000.

And the power of 40 = 64000

So these three numbers are around 40.

Combined with the single digits it is , so it is

First, the product is a four-digit number, and the three numbers are not much different, so first estimate that the cubic of a certain number is about 50,000, the cube of 30 is 2700, and the cube of 40 is 6400, so these three odd numbers are sandwiched between 30 and 40.

Two, consecutive odd numbers, which can end with 1, 3, 5 or 3, 5, 7 or 5, 7, 9 or 7, 9, 1. Let's only determine whether the last number of the product at the end is three. 1*3*5=15, 3*5*7=105, 5*7*9=315, the last digits are all 5, which does not meet.

And 7*9*1=63, the last digit is 3

Three, but to be consecutive, it can only be 27, 29, 31 or 37, 39, 41And 27*29*31=24273, 37*39*41=59163.

Four, the latter conforms, so these three odd numbers are 37, 39, 41.

The landlord may seem troublesome, but this is the correct thinking process of this question, and in the actual operation process, there is no need to be so troublesome, looking at the landlord.

These three consecutive odd numbers are 37, 39, 41The product is 59163

The product is a five-digit number starting with 5, 50,000 square is approximately equal to, 60,000 square is approximately equal to, so the three consecutive odd high disturbances of the god are 37 * 39 * 41 = 59163, which meets the requirements and is unique.

The acres of each hole are: 7,9,1

The number of the three cherry blossoms is in double digits.

It can only be.

The mantissa should be hungry for spring, and it should be rotten and resistant to 7,9,1 trial calculations.

Therefore, the estimated loss should be 37, 39, 41

Accounting 37 39 41 = 59163

Decompose prime factors.

These three odd numbers are 3, 5, 7, 2, zhhcang report has a detailed column? Know.

Report the herring.

The above three lines are the complete solution process.

zhhcang report.

How do you ask for a hall? Break down prime factors, wouldn't you? The guy below, please give a complete process, how do you solve a=5? , let the number in the middle of these three numbers be x, then the remaining two numbers are divided into (x-2) and (x+2) respectively from the title:

x-2)(x+2)x=105

The solution is x=5, so the three numbers are , 2, and let these three numbers be: (a-2), a, (a+2), then.

a-2)×a×(a+2)=105

Solution: a=5

Then: a-2=3, a+2=7

So: these three numbers are ,0,

315=3x3x5x7=5x7x9 So these three numbers are and 9

So the three numbers are 33, 35, 37

Answer: The product of the odd-numbered gear cluster height of these 3 Zheng Wu consecutive row rulers is 42735

315=3x3x5x7=5x7x9

So these three numbers are and 9 respectively

The 3 odd numbers are .

Because it is known that the odd number 6783 multiplied by 3 consecutive odd numbers, according to the product unit digit is 3, these 3 consecutive odd digits are respectively .

Because the three numbers are multiplied, the product is a thousand digits, so the three numbers are two digits. And because three numbers are consecutive odd numbers, it is obtained after trying that the three numbers are , that is, the answer sought.

Let the odd number in the middle be x, then the odd number before and after is x-2, x+2x(x+2)(x-2)=105, respectively

x(x^2-4)=105

x^3-4x=105

x=5 x-2=3

x+2=7 Sanzheng Pei volt number: 3,5,7,6,shuiguilin What is the symbol of the report? For example, 2 2 is 2 to the 2nd power of 2 is 2*2, let the odd number in the middle be x, and the odd number before and after the lift is x-2 and x+2 respectively

x(x+2)(x-2)=105

x(x^2-4)=105

x^3-4x=105

x=5 x-2=3

x+2=7 three numbers: 3,5,7,1, because 105 is a multiple of 5, so one of the odd numbers is a multiple of 5, so 3 numbers are 3,5,7,,0, and 105 is decomposed into a calendrical factor.

105=3x5x7,0,

Let the odd number in the middle be x, then the front is x-2 and the back is x+2x-2)x(x+2)=19575

From the meaning, x is an odd number, then x=27 is calculated

x-2=25，x+2=29

The sum of three odd numbers is 25 + 27 + 29 = 81

Note: The process of calculating 27 is calculated by short division and the product of the least common divisor of 19575.

Since 19575 is the product of three consecutive odd numbers, then 19575 must be a composite number, and we can write this product by decomposing the prime factors, and then adjust it to three prime numbers.