Xiao Ming s house is 47 meters away from the school, and Xiao Gang s house is 55 meters away from th

This can be seen in two ways:

1 Xiao Ming's family and Xiao Gang's family are in the same straight line, which is also divided into two situations:

1) Xiao Ming's house and Xiao Gang's house are on both sides of the school (i.e., B Xiaoming's house A school C Xiaogang's house), then the distance between the two families is:

47 + 55 = 102 (m).

2) Xiao Ming's family and Xiao Gang's family are on the same side of the school.

That is: C Xiaogang's house B Xiaoming's house A school or A school B Xiaoming's house C Xiaogang's house), then the distance between the two is :

55-47 = 8 (m).

2 Xiao Ming's family and Xiao Gang's family are not in the same straight line, that is to say, Xiao Ming's family, the school, and Xiao Gang's family 3 points form a triangle, which has to be calculated according to the angle of this triangle, and this will have infinite solutions.

There can be no answer to this

Their home may be in a straight line with the school, or it may be three points, there is no definite answer to this, there are infinite solutions.

It seems to be an elementary school problem, so I don't consider triangles, which are 102 meters or 8 meters.

It could be 8 meters or 102 meters.

This is a question that does not have a single answer, because it is not known. If the three sites are in a straight line and Xiao Ming's house is in the middle, the distance between the two houses is 55 47 8 meters, and the distance between the two schools is 55 47 102 meters. If the three locations are not in a straight line to form a triangle, and the angle between Xiao Ming's house and Xiao Gang's house and the school line is a, then the distance between the two houses is 47 squared plus 55 squared minus 55 times 47 times 2 times cosa

55-35 = 20 meters. Mathematical problems are generated through the use of abstraction and logical reasoning through counting, calculation, measuring, and observation of the shape and motion of objects. Mathematics problems can be roughly divided into fill-in-the-blank questions, true/false questions, multiple-choice questions, calculation questions, application questions, proof questions, drawing questions, thinking questions, reading questions, and regular questions.

Purely mathematical applications refer to the individual quantitative relations, which constitute problems that do not involve the existence and relations of quantities in real practical sense. Practical application is also a life problem about mathematics.

Practical problems are generally found in primary school textbooks, and usually only involve four operations on non-negative numbers. In junior high school, it is common to solve practical problems for column algebraic equations, or to solve practical problems by solving right triangles. In high school, there are often a variety of options available, such as functions, sequences, inequalities, derivatives, definite integrals, solving oblique triangles, etc.

Xiao Ming and Xiao Jun are both on the same road as the school, Xiao Ming's house is 55 meters away from the school, Xiao Jun's house is 35 meters away from the school, and Xiao Ming and Xiao Jun are 20 meters apart

20 (m).

Ask how many meters apart Xiao Ming's house and Xiao Jun's house are at the farthest distance.

This can be divided into two situations: 1 Xiao Ming's family and Xiao Gang's family are in the same straight line, which is also divided into two situations: (1) Xiao Ming's family and Xiao Gang's family are on both sides of the school (i.e.

B Xiao Ming's house A school C Xiao Gang's house), then the distance between the two is: 47 + 55 = 102 (m) (2) Xiao Ming's house and Xiao Gang's house are the same in school.

Summary. Xiaolan to Xiaoming's house is 784 meters, 264 + 520 = 784 meters.

Xiaofang's house is 360 meters to Xiaoming's house and 624 meters to the school. Xiaolan's house is 520 meters from the school, how many meters is her home to Xiaoming's house?

Hello dear, <>

Please wait a minute. Pro, Xiao Ming's house to the school is 264 meters, 624-360 = 264 (meters) Xiaolan to Xiao Ming's house 784 meters, 264 + 520 = 784 meters.

Dear, here's a way.

Another way is, 360 + 520-624 = 256 (m) pro, do you still have any questions<>

Dear, what grade are you in<>

What's the other way?

Summary. Hello, I am a professional consulting teacher, please wait, I am giving you the best answers and suggestions according to your questions, you just need to wait patiently for a while, and give you a reply within five minutes, thank you very much.

Xiaoli's house is 185 meters to Xiaoming's house and 548 meters to the school. Xiaohong's house is 450 meters away from the school, how many meters is there to Xiaoming's house?

Hello, I am a professional consulting teacher, please wait, I am giving you the best answers and suggestions according to your questions, you just need to wait patiently for a while, and give you a reply within five minutes, thank you very much.

Hello, according to the question you provided, first of all, Xiaoli's house is 185 meters to Xiaoming's house, 548 meters to the school, and Xiaohong's house is 450 meters away from the school, first of all, in this case, use 548-185=363This is the distance from Xiao Ming's house to the school, now use 450-363, which is equal to 87, so Xiaohong's house is 87 meters from Xiao Ming's house, I hope it can help you.

According to the known conditions, the distance from Xiao Ming's house to Xiao Tansun Zheng Hong's house is 268 meters, while the distance from Xiaohong's house to Rang Song's school should be 587-453 = 134 meters. Therefore, the distance from Xiao Ming's house to the school should be 268 + 134 = 402 meters. Kaizhou.

Xiao Ming's house and Xiao Jun's house are in a straight line with the school, Xiao Ming's house is 840 meters away from the school, Xiao Ming takes 15 minutes to walk to the school, and Xiao Jun takes 20 minutes to walk to the school. How far is Xiaojun's house from school?

Solution: Let Xiao Ming and Xiao Jun walk at the same speed.

Formula: s=vt (distance = time at velocity).

t=840 15=56m min.

s = 56x20 = 1120 meters.

A: Xiaojun's house is 1120 meters away from the school.