Math Puzzle! The answer is right! Solve math problems!

1.An intersection point, the line A determines the intersection of b and c, and the intersection of b, c and the line d can only be the intersection of a, b, and c.

It takes seconds for B to walk from B to A.

A should rest for 7 seconds in the middle, which is 21 + 7 = 28 seconds.

84 seconds after launch, both arrived at station B at the same time.

A 1There is only one intersection point.

Since two straight lines intersect at one point, and three straight lines can only intersect at one point, the fourth straight line must intersect at one point with two of them, and must intersect at the same point with those three straight lines.

2.Since a, b, c, and d intersect at the same point and e is parallel to d, d must intersect with ab c at 3 points respectively, so.

There are a total of 5 line segments.

2. B takes seconds to get from A to B.

However, since A has to rest for one second at each stop, and A has to rest for 7 seconds the first time from A to B, A needs 21 + 7 = 28 seconds.

Suppose it takes n seconds for A and B to reach a point at the same time (n is less than or equal to 120 seconds).

Then the smallest n is equal to the least common multiple of 21 and 28, which is 84

Because n is less than or equal to 120, A and B have only visited the same site once.

1. The class size is the number of points that have been reduced, the average number of points that have been reduced=27, and the average number of 2 points is (2*30+36) 3=32

One. x=45 There are 45 people.

Two. A + B = 60, B + C = 72, C + A = 66 A + B + C + A + B + C = 60 + 72 + 66198 A + B + C = 99

The average number of A, B, C, is 99 3 = 33

Three. 84*3+x=（84+

x = four. x number of girls and 2x number of boys.

4*2x+x=9x

Average: 9x 3x=3

1.(96-69)/(

The total number of three.

A 99-36 2 = 27

B 99-33 2=33

C 99-33-27 = 39

Mean 99 3 = 33

4.(4 2 + 1 1) (2 + 1) = 3 trees.

(1) Set the fruit candy sold for x kilograms.

x = 26 toffee: 60-26 = 34 kg.

2) There are x number of big monks.

3x+1/3(100-x)=100

3x+100/3-1/3x=100

8/3x=200/3

x = 25 little monks: 100-25 = 75.

3) There are x types of coupons.

7*(x+31)+4x+2[85-(x+31)-x]=5007x+217+4x+108-4x=500

7x=175

x = 25 A type: 25 + 31 = 56 sheets.

4) Let there be x spiders and y dragonflies.

8x+6y+6(18-x-y)=118;2y+1*(18-x-y)=20

x=5 y=7

Spiders: 5 Dragonflies: 7 Cicadas: 18-5-7 = 6 (5) There are x octagonal ones.

x = 8 triangular: 20-8 = 12

6) Let there be x rabbits.

4x+80=2*(100-x)

4x+80=200-2x

6x=120

x = 20 chickens: 100-20 = 80 chickens.

It's done in a hurry, there may be miscalculations, most of them should be right, it's better to do the math yourself.

Wife = x

My son will inherit two-thirds of the estate, and my wife will receive one-third of the son=2x

and my wife will inherit two-thirds of the inheritance, and my daughter will receive one-third daughter = (1 2 )x

Total assets = 1

Get 2x+x+(1 2 )x=1

Calculate x=2 7

1) Divide the estate into two parts;

2), two-thirds of the son's share, that is, one-third of the entire estate;

The wife took a third of the portion. i.e. one-sixth of the entire estate.

3) The daughter gets a third of the portion. i.e. one-sixth of the entire estate.

The wife is two-thirds of the portion. That is, one-third of the total estate.

4) The wife participates in two distributions, totaling one-half.

Wife: 2 7

Son: 4 7

Daughter: 1 7

Process: Because mathematicians only consider 2 combinations of wife and son, wife and daughter, and these 2 combinations are related to the wife, so

If the proportion of the wife's share of the estate is a, then there is:

The proportion of the son's inheritance is: 2a

When the wife and son are one, the wife is 1 3 and the son is 2 3. Wife: Son = 1:2).

The proportion of the daughter's inheritance is: (1 2)a

When the wife and daughter are a whole, the wife is 2 3 and the daughter is 1 3. Wife: Daughter = 1: 1 2).

The whole inheritance is regarded as a whole as 1, that is, the sum of the proportion of the inheritance of the wife, son, and daughter is 1, then there is: a+2a+(1 2)a=1

The solution is a = 2 7

Therefore, the proportion of the wife's share of the estate is a=2 7

The proportion of the son's inheritance is: 2a = 4 7

The proportion of the daughter's inheritance is: (1 2) a = 1 7

I wish you progress in your studies!!

Daughter: Son.

1:2 Wife: Son.

1:2 Wife: Daughter.

2:1 Wife: Daughter: Son.

Then 2+1+4=7

The son inherited four-sevenths.

The daughter inherited one-seventh.

The wife inherited two-sevenths.

o^)

...... in an even number

2014 is the 2014th 2 = 1007 numbers.

The number in the array starts at 2, and every group of 8 (i.e., every two rows) 1007 8 = 125 ......Remainder 7

Then 2014 is the 7th in group 126, and its position is equivalent to the 7th in group 1, that is, 2014 is in column d in row 126*2=252.

The least common multiple of the first row is 12 for every 3 words in the first row and every 4 words in the second row

Then every 12 words is a big cycle.

460 ÷ 12 = 38 ……Remainder 4

Therefore, group 460, which is equivalent to group 4, is "small movement".

Dividing by 2 is 1007, and every 2 rows is seen as a group of 10. Then the remaining 7 is b?

2. The first row of 3 is a cycle, the remaining one is small, the second row is 4 a cycle, divisible so it is moving, so it is a small movement.

If B originally invested $ x million yuan, then from the title, A originally invested $5 x million yuan.

A withdraws 6 million yuan, then A's current investment amount is 5x-600 B's additional capital is 6 million yuan, then B's current investment amount is x+600 from the title, and B's investment amount is 2 times that of A.

Then the equation is x+600=2(5x-600).

Solution x = 200

Then B originally invested 2 million yuan, so A originally invested 10 million yuan.

Solution: If the original plan B invests x million yuan, then A invests 5x million yuan, then, B's actual investment is (x+600) yuan, and A's actual investment is (5x-600) yuan, which is derived from the title, x+600=2(5x-600).

i.e., 9x=1800

Solution, x = 200 (10,000 yuan).

Then A originally planned to invest 5x=1000 (10,000 yuan).

Solution: Let A originally invest x million yuan, and B originally invested 1 5x million yuan 2 (x-600) = 1 5x + 600

Get x=1000

Answer: A originally invested 10 million yuan.

If A's original investment is x million yuan, and B y's million yuan, then there is x=5y 2(x-600)=y+600 x=1000 y=200 from the above two formulas, and all A's original investment is 10 million yuan.

Let B = n, A = 5n Unit: 10,000 yuan.

2(5n-600)=n+600

10n-1200=n+600

9n=1800

n=200A originally invested 10 million yuan.

If the investment of plan B is x yuan, then plan A plans to invest 5x, 2 (5x-600) = x + 600

x=200, so A plans to invest 5*200=1000

Write a system of equations to solve it, let A be x million yuan, B be y million yuan x = 5y

2(x-600)=y+600

x=1000 y=200

A originally invested 10 million.

Visually inspect one is more suitable, and the cost of selling one is different from 26.

In terms of the current mathematical system, the answer to this question is unique.

Because the question is: how much is an average apple? Therefore, the amount of money should be divided according to the number of apples, ie.

With 22, it becomes a number of points according to money, and the meaning becomes How many apples do you buy for an average dollar?